All Precalculus Resources
Example Questions
Example Question #1 : Determine If A Relation Is A Function
Which of the following expressions is not a function?
Recall that an expression is only a function if it passes the vertical line test. Test this by graphing each function and looking for one which fails the vertical line test. (The vertical line test consists of drawing a vertical line through the graph of an expression. If the vertical line crosses the graph of the expression more than once, the expression is not a function.)
Functions can only have one y value for every x value. The only choice that reflects this is:
Example Question #2 : Determine If A Relation Is A Function
Suppose we have the relation on the set of real numbers whenever . Which of the following is true.
The relation is a function because every relation is a function, since that's how relations are defined.
The relation is not a function because and both hold.
The relation is a function because for every , there is only one such that holds.
The relation is a function because holds and also holds.
The relation is not a function because holds but does not.
The relation is not a function because and both hold.
The relation is not a function because and hold. If it were a function, would hold only for one . But we know it holds for because and . Thus, the relation on the set of real numbers is not a function.
Example Question #1 : Determine If A Relation Is A Function
Consider a family consisting of a two parents, Juan and Oksana, and their daughters Adriana and Laksmi. A relation is true whenever is the child of . Which of the following is not true?
The relation is not a function because (Laksmi,Juan) and (Laksmi,Oksana) both hold.
Even if the two parents had only one daughter, the relation would not be a function.
(Laksmi,Adriana) does not hold because Adriana is not Laksmi's child.
If the two parents had only one daughter, the relation would be a function.
(Adriana,Laksmi) does not hold because Laksmi is not Adriana's child and is a boy.
Even if the two parents had only one daughter, the relation would not be a function.
The statement
"Even if the two parents had only one daughter, the relation would not be a function."
is not true because if they had only one daughter, say Adriana, then the only relations that would exist would be (Juan, Adriana) and (Oksana,Adriana), which defines a function.
Example Question #3 : Determine If A Relation Is A Function
Which of the following relations is not a function?
The definition of a function requires that for each input (i.e. each value of ), there is only one output (i.e. one value of ). For , each value of corresponds to two values of (for example, when , both and are correct solutions). Therefore, this relation cannot be a function.
Example Question #1 : Determine If A Relation Is A Function
Given the set of ordered pairs, determine if the relation is a function
Cannot be determined
Yes
No
No
A relation is a function if no single x-value corresponds to more than one y-value.
Because the mapping from goes to and
the relation is NOT a function.
Example Question #1 : Determine If A Relation Is A Function
What equation is perpendicular to and passes throgh ?
First find the reciprocal of the slope of the given function.
The perpendicular function is:
Now we must find the constant, , by using the given point that the perpendicular crosses.
solve for :
Example Question #5 : Determine If A Relation Is A Function
Is the following relation of ordered pairs a function?
Yes
No
Cannot be determined
Yes
A set of ordered pairs is a function if it passes the vertical line test.
Because there are no more than one corresponding value for any given value, the relation of ordered pairs IS a function.
Example Question #1 : Real Numbers
Which of the following is not true about a field. (Note: the real numbers is a field)
For every element in the field, there is another element such that their product is equal to , where is the multiplicative identity, in the case of real numbers.
We have for any and in the field.
A field can be defined in many ways.
For every element in the field, there is another element such that their sum is equal to , where is the additive identity.
There is an element in the field such that for any element in the field.
For every element in the field, there is another element such that their product is equal to , where is the multiplicative identity, in the case of real numbers.
It is not the case that for any element in a field, there is another one such that their product is . Take in the real numbers. Multiply by any number and you get , so you will never get . This is true for any field that has more than 1 element.
Example Question #1 : Modeling
John lives in Atlanta, but commutes every Monday to LaGrange where he has an apartment he stays in Monday-Friday for work. Each Monday he drives 350 miles to LaGrange. Once he arrives to his home away from home he is in walking distance of work and does not use his car for anything else. After 23 weeks his odometer shows 186,000 miles. Write an equation that models his odometer reading as a function of the number of weeks he has been driving after commencing his new job.
The rate of change of his mileage is 700 per week (350 x 2=700 there and back). The rate of change is the same thing as slope. Since we are looking for equation an equation that models his odometer reading as a function of the number of weeks he has been driving we can extract the point (23 , 18600) since after 23 weeks his odometer read 18,600 miles. Now we will use the point slope formula:
distribute the right side
isolate y
Example Question #1 : Linear Modeling
John lives in Atlanta, but commutes every Monday to LaGrange where he has an apartment he stays in Monday-Friday. Each Monday he drives 350 miles to LaGrange. Once he arrives to his apartment he is in walking distance of work and does not use his car for anything else. After 23 weeks his odometer shows 186,000 miles. Write an equation that models his odometer reading as a function of the number of weeks he has been driving after commencing his new job. Using the equation you just made, what is the y intercept or his original mileage before starting?
y intercept=153,800 miles
Need more information to solve.
y intercept=169,900 miles
y intercept=186,000 miles
y intercept=16,100 miles
y intercept=169,900 miles
The y intercept can be found by plugging in 0 for x in your original equation: y=700x+169,900 because at x=0 you can only reach the y axis and thus will find the y intercept.