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Example Questions
Example Question #201 : Organic Concepts
Alpha-D-glucopyranose:
Glucose (pictured) is defined as which of the following?
Ketohexose
Aldohexose
Ketopentose
Aldopentose
Triose phosphate
Aldohexose
Glucose in its open chain form (shown below), has a free aldehyde group (an aldose), and it contains six carbons (a hexose). Together, glucose is shown to be an aldohexose.
Example Question #202 : Organic Concepts
Alpha-D-glucopyranose
Which of the labelled carbon atoms is the anomeric carbon?
D
A
B
E
C
A
The anomeric carbon is formed from the original carbonyl carbon in the straight-chain form of the molecule being attacked by a hydroxyl group to form a hemiacetal. This is seen as a carbon that is bonded to two oxygen atoms. In the case of glucose, the carbon labelled A is a hemiacetal, and is considered to be the anomeric carbon.
Example Question #13 : Help With Organic Carbohydrates
Shown below is the structure of a sugar molecule.
Which of the following is the most appropriate classification of this sugar?
Ketoheptose
Aldoheptose
Aldohexose
Ketohexose
Aldoheptose
In this question, we're given the structure of a sugar molecule, and we're asked to identify which answer choice represents the correct identification of this molecule.
To answer this question, there are two things we need to look at. For one, we need to determine whether it is an aldehyde sugar (aldose) or a ketone sugar (ketose). The first carbon atom in the molecule (shown at the very top in the image) is shown as . This means that the carbon contains a double bond to the oxygen. Furthermore, since it also contains a bond to a hydrogen, we can conclude that this is an aldehyde functional group. Consequently, we know that this must be an aldose sugar.
Next, we need to look at the number of carbon atoms in the molecule. In the image shown in the question, there are a total of seven carbon atoms. Thus, this sugar would be classified as a heptose sugar (seven carbons) rather than a hexose sugar (six carbons).
Putting these two pieces of information together, we know that the sugar is both an aldose and a heptose. Therefore, this sugar is an aldoheptose.
Example Question #1 : Help With Organic Proteins
Which of the following is an example of a basic amino acid?
Lysine
Alanine
Aspartic acid
Leucine
Tyrosine
Lysine
Lysine's R-group includes an amine (-NH2), which can be ionized by picking up a hydrogen. This ability classifies lysine as basic.
Example Question #1 : Sulfide Chemistry
Which of the following amino acids can participate in the formation of a disulfide bridge?
Alanine
Tyrosine
Aspartic acid
Phenylalanine
Cysteine
Cysteine
Cysteine's R-group contains a sulfhydryl group (-SH), which can participate in the formation of a disulfide bridge in a protein's tertiary and/or quaternary structure. Cysteine is the only amino acid to contain a sulfur atom.
Example Question #3 : Help With Organic Proteins
Which of the following amino acids is the only one to contain a side chain that results in an achiral amino acid?
Lysine
Aspartic acid
Alanine
Glycene
Glycene
The only achiral amino acid is Glycene. Glycene's side chain is simply a hydrogen. Because a hydrogen already exists on the fundamental structure of an amino acid backbone, a side chain of a single hydrogen atom causes glycene to be achiral.
Example Question #2 : Help With Organic Proteins
How many essential amino acids are there?
Ten
Zero
Twelve
Twenty
Nine
Nine
The nine essential amino acids are valine, leucine, isoleucine, histidine, phenylalanine, tryptophan, methionine, threonine, and lysine. These amino acids must be consumed in the diet, since they cannot be synthesized by adult humans.
Example Question #31 : Biological Molecules
What is the D/L configuration and the absolute (R/S) configuration of the following amino acid (cysteine)?
L, R
D, R
L, S
Cysteine is achiral
D, S
L, R
Cysteine is an unusual amino acid. Although each of the normal biological amino acids have the L configuration (with the exception of glycine, which is achiral), meaning they can be drawn with the Fischer projection as shown:
the fact that cysteine contains a sulfur group makes the side chain a higher priority than the carboxylic acid. Therefore, the absolute configuration of cysteine will be R, and not S like the other amino acids.
Example Question #1 : Help With Organic Proteins
Consider L-glutamate, which is shown below.
Using the pKa information provided, what is the isoelectric point (pI) of the given molecule?
The isoelectric point is the average of the two pKa values around which the molecule has an overall neutral charge. In the case of glutamate, the amino acid is in its neutral (zwitterion) form in between the lower two pKa values. Taking the average of the two values gives the pI.
Example Question #1 : Help With Organic Proteins
Consider the amino acid L-lysine, shown below.
Given the pKa values shown, calculate the pI of lysine.
The isoelectric point is the average of the two pKa values around which the molecule has an overall neutral charge. In the case of lysine, the amino acid is in its neutral (zwitterion) form in between the higher two pKa values. Taking the average of the two values gives the pI.
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