Call Now to Set Up Tutoring:

(888) 888-0446

New SAT Reading : New SAT

Study concepts, example questions & explanations for New SAT Reading

Create An Account

All New SAT Reading Resources

3 Diagnostic Tests 34 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1 : Geometry

The measure of the supplement of angle A is 40 degrees larger than twice the measure of the complement of angle A. What is the sum, in degrees, of the measures of the supplement and complement of angle A?

Possible Answers:

140

190

Correct answer:

190

Explanation:

Let A represent the measure, in degrees, of angle A. By definition, the sum of the measures of A and its complement is 90 degrees. We can write the following equation to determine an expression for the measure of the complement of angle A.

A + measure of complement of A = 90

Subtract A from both sides.

measure of complement of A = 90 – A

Similarly, because the sum of the measures of angle A and its supplement is 180 degrees, we can represent the measure of the supplement of A as 180 – A.

The problem states that the measure of the supplement of A is 40 degrees larger than twice the measure of the complement of A. We can write this as 2(90-A) + 40.

Next, we must set the two expressions 180 – A and 2(90 – A) + 40 equal to one another and solve for A:

180 – A = 2(90 – A) + 40

Distribute the 2:

180 - A = 180 – 2A + 40

Add 2A to both sides:

180 + A = 180 + 40

Subtract 180 from both sides:

A = 40

Therefore the measure of angle A is 40 degrees.

The question asks us to find the sum of the measures of the supplement and complement of A. The measure of the supplement of A is 180 – A = 180 – 40 = 140 degrees. Similarly, the measure of the complement of A is 90 – 40 = 50 degrees.

The sum of these two is 140 + 50 = 190 degrees.

Report an Error

Example Question #12 : How To Find An Angle Of A Line

$\dpi{100} \small \overline{AB}$ is a straight line. $\dpi{100} \small \overline{CD}$ intersects $\dpi{100} \small \overline{AB}$ at point $\dpi{100} \small E$ . If $\dpi{100} \small \angle AEC$ measures 120 degrees, what must be the measure of $\dpi{100} \small \angle BEC$ ?

Possible Answers:

$\dpi{100} \small 60$ degrees

$\dpi{100} \small 75$ degrees

None of the other answers

$\dpi{100} \small 65$ degrees

$\dpi{100} \small 70$ degrees

Correct answer:

$\dpi{100} \small 60$ degrees

Explanation:

$\dpi{100} \small \angle AEC$ & $\dpi{100} \small \angle BEC$ must add up to 180 degrees. So, if $\dpi{100} \small \angle AEC$ is 120, $\dpi{100} \small \angle BEC$ (the supplementary angle) must equal 60, for a total of 180.

Report an Error

Example Question #793 : New Sat

Two parallel lines are intersected by a transversal. If the minor angle of intersection between the first parallel line and the transversal is $36^{\circ}$ , what is the minor angle of intersection between the second parallel line and the transversal?

Possible Answers:

$144^{\circ}$

$36^{\circ}$

$54^{\circ}$

$18^{\circ}$

$66^{\circ}$

Correct answer:

$36^{\circ}$

Explanation:

When a line intersects two parallel lines as a transversal, it always passes through both at identical angles (regardless of distance or length of arc).

Report an Error

Example Question #11 : How To Find An Angle Of A Line

If $\overleftrightarrow{FH} \parallel \overleftrightarrow{AD}$ , $\overline{BE}\perp \overleftrightarrow{GC}$ , and $m\angle HGC=58^\circ$ , what is the measure, in degrees, of $\angle ABE$ ?

Alternate interior angles

Possible Answers:

148

122

Correct answer:

148

Explanation:

The question states that $\overleftrightarrow{FH} \parallel \overleftrightarrow{AD}$ . The alternate interior angle theorem states that if two parallel lines are cut by a transversal, then pairs of alternate interior angles are congruent; therefore, we know the following measure:

$m\angle GCA = 58^\circ$

The sum of angles of a triangle is equal to 180 degrees. The question states that $\overline{BE}\perp \overleftrightarrow{GC}$ ; therefore we know the following measure:

$m \angle BEC = 90^\circ$

Use this information to solve for the missing angle: $\angle EBC$

$180^\circ=m\angle EBC+58^\circ+90^\circ$

$m\angle EBC=32^\circ$

The degree measure of a straight line is 180 degrees; therefore, we can write the following equation:

$180^\circ=m\angle ABE+32^\circ$

$m\angle ABE=148^\circ$

The measure of $\angle ABE$ is 148 degrees.

Report an Error

Example Question #5 : How To Find An Angle Of A Line

Lines A and B in the diagram below are parallel. The triangle at the bottom of the figure is an isosceles triangle.

Act2

What is the degree measure of angle ?

Possible Answers:

Correct answer:

Explanation:

Since A and B are parallel, and the triangle is isosceles, we can use the supplementary rule for the two angles, and 2x+30 which will sum up to 180 . Setting up an algebraic equation for this, we get 4x+2x+30=180 . Solving for , we get x=25 . With this, we can get either 2(25)+30=80 (for the smaller angle) or 4(25)=100 (for the larger angle - must then use supplementary rule again for inner smaller angle). Either way, we find that the inner angles at the top are 80 degrees each. Since the sum of the angles within a triangle must equal 180, we can set up the equation as 80+80+y=180

y=20 degrees.

Report an Error

Example Question #1 : Properties Of Roots And Exponents

Which of the following is equal to $\sqrt{75}$ ?

Possible Answers:

$7.5\sqrt{10}$

$3\sqrt{5}$

$5\sqrt{3}$

Correct answer:

$5\sqrt{3}$

Explanation:

√75 can be broken down to √25 * √3. Which simplifies to 5√3.

Report an Error

Example Question #2 : Properties Of Roots And Exponents

Simplify $\sqrt{a^{3}b^{4}c^{5}}$ .

Possible Answers:

$a^{2}bc^{2}\sqrt{ac}$

$a^{2}b^{2}c\sqrt{ab}$

$a^{2}b^{2}c^{2}\sqrt{bc}$

$ab^{2}c^{2}\sqrt{ac}$

$a^{2}bc\sqrt{bc}$

Correct answer:

$ab^{2}c^{2}\sqrt{ac}$

Explanation:

Rewrite what is under the radical in terms of perfect squares:

$x^{2}=x\cdot x$

$x^{4}=x^{2}\cdot x^{2}$

$x^{6}=x^{3}\cdot x^{3}$

Therefore, $\sqrt{a^{3}b^{4}c^{5}}= \sqrt{a^{2}a^{1}b^{4}c^{4}c^{1}}=ab^{2}c^{2}\sqrt{ac}$ .

Report an Error

Example Question #1 : Properties Of Roots And Exponents

What is $\sqrt{50}$ ?

Possible Answers:

$10\sqrt{2}$

$2\sqrt{5}$

$5\sqrt{2}$

Correct answer:

$5\sqrt{2}$

Explanation:

We know that 25 is a factor of 50. The square root of 25 is 5. That leaves $\sqrt{2}$ which can not be simplified further.

Report an Error

Example Question #3 : Properties Of Roots And Exponents

Which of the following is equivalent to $\frac{x + \sqrt{3}}{3x + \sqrt{2}}$ ?

Possible Answers:

$\frac{3x^{2} - \sqrt{6}}{9x^{2} + 2}$

$\frac{3x^{2} -x \sqrt{2} + 3x\sqrt{3} - \sqrt{6}}{9x^{2} - 2}$

$\frac{3x^{2} + 3x\sqrt{2} + x\sqrt{3} +\sqrt{6}}{9x^{2} - 2}$

$\frac{3x^{2} + \sqrt{6}}{3x - 2}$

$\frac{4x + \sqrt{5}}{3x + 2}$

Correct answer:

$\frac{3x^{2} -x \sqrt{2} + 3x\sqrt{3} - \sqrt{6}}{9x^{2} - 2}$

Explanation:

Multiply by the conjugate and the use the formula for the difference of two squares:

$\frac{x + \sqrt{3}}{3x + \sqrt{2}}$

$\frac{x + \sqrt{3}}{3x + \sqrt{2}}\cdot \frac{3x - \sqrt{2}}{3x - \sqrt{2}}$

$\frac{3x^{2} -x \sqrt{2} + 3x\sqrt{3} - \sqrt{6}}{(3x)^{2} - (\sqrt{2})^{2}}$

$\frac{3x^{2} -x \sqrt{2} + 3x\sqrt{3} - \sqrt{6}}{9x^{2} - 2}$

Report an Error

Example Question #4 : Properties Of Roots And Exponents

Which of the following is the most simplified form of:

$\sqrt{468}$

Possible Answers:

$17\sqrt{2}$

$4\sqrt{29}$

$\sqrt{468}$

$2\sqrt{117}$

$6\sqrt{13}$

Correct answer:

$6\sqrt{13}$

Explanation:

First find all of the prime factors of 468

$468=6\ast78=6\ast6\ast13=2\ast3\ast2\ast3\ast13$

So $\sqrt{468}=\sqrt{2\ast2\ast3\ast3\ast13}=2\ast3\sqrt{13}=6\sqrt{13}$

Report an Error

View SAT Reading Tutors

Masoud
Certified Tutor

University of Guilan,, Bachelor of Science, Biological/Biosystems Engineering. University of Tehran, Master of Science, Anima...

View SAT Reading Tutors

Quang
Certified Tutor

Georgetown University, Bachelor of Science, Finance.

View SAT Reading Tutors

Sven
Certified Tutor

Rider University, Bachelor of Science, Computer Science.

All New SAT Reading Resources

3 Diagnostic Tests 34 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Chemistry Tutors in Dallas Fort Worth, GMAT Tutors in Washington DC, Physics Tutors in San Diego, Spanish Tutors in Seattle, Math Tutors in Washington DC, LSAT Tutors in Los Angeles, French Tutors in Phoenix, SSAT Tutors in Chicago, Reading Tutors in San Francisco-Bay Area, Reading Tutors in Philadelphia

Popular Courses & Classes

LSAT Courses & Classes in Seattle, SAT Courses & Classes in San Francisco-Bay Area, SSAT Courses & Classes in Phoenix, Spanish Courses & Classes in Phoenix, GRE Courses & Classes in Seattle, GMAT Courses & Classes in Philadelphia, GRE Courses & Classes in New York City, GMAT Courses & Classes in Chicago, ACT Courses & Classes in Atlanta, SSAT Courses & Classes in Washington DC

Popular Test Prep

GRE Test Prep in Miami, MCAT Test Prep in Washington DC, SAT Test Prep in Atlanta, LSAT Test Prep in Los Angeles, GRE Test Prep in Chicago, SSAT Test Prep in Seattle, GRE Test Prep in Seattle, ISEE Test Prep in New York City, ACT Test Prep in San Diego, SSAT Test Prep in Dallas Fort Worth

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

New SAT Reading : New SAT

Study concepts, example questions & explanations for New SAT Reading

All New SAT Reading Resources

Example Questions

Example Question #1 : Geometry

Example Question #12 : How To Find An Angle Of A Line

Example Question #793 : New Sat

Example Question #11 : How To Find An Angle Of A Line

Example Question #5 : How To Find An Angle Of A Line

Example Question #1 : Properties Of Roots And Exponents

Example Question #2 : Properties Of Roots And Exponents

Example Question #1 : Properties Of Roots And Exponents

Example Question #3 : Properties Of Roots And Exponents

Example Question #4 : Properties Of Roots And Exponents

All New SAT Reading Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: