All New SAT Math - No Calculator Resources
Example Questions
Example Question #211 : New Sat
Which point lies on the line that goes through the points (1, 2) and (4, 5)?
First calculate the slope of the line using the slope formula.
Substituting in the known information.
Now use point slope form to find the equation of the line passing through these points.
Now identify which point lies on the line.
Therefore, the point that lies on the line is (9,10)
Example Question #212 : New Sat
Add:
Find the least common denominator to solve this problem
Multiply 27 with , and multiply with 3 to obtain common denominators.
Convert the fractions.
Combine the terms as one fraction.
The answer is:
Example Question #213 : New Sat
Simplify
Simplify the numerator
Pull an x out of each term in the numerator
The x in the numerator and the x in the denominator cancel
Example Question #214 : New Sat
What is a possible solution for if the equation has exactly one solution for ?
Given
Given
First FOIL the first equation. FOIL means to multiply each term in the first binomial with each term in the second binomial.
Now solve the second equation for .
Substitute the equation for into the first equation to get a new equation only in terms of .
Distribute to eliminate the parentheses and simplify.
Now use the quadratic formula.
Given a quadratic in the form,
For this particular question,
From here recall that if the value under the radical sign equals zero than results in having just one solution.
Therefore, set the value that is under the radical equal to zero and solve for .
Since the binomials containing are the same, set one equal to zero and solve.
Example Question #215 : New Sat
Give the positive solution of the question.
This question is testing one's ability to analyze a function algebraically and recognize different but equivalent forms. Identifying properties of functions through analyzing equivalent forms is critical to this concept. Such properties that can be found through analyzing the different forms of a function include finding roots (zeros), extreme values, symmetry, and intercepts.
Knowing the standard and the concept for which it relates to, we can now do the step-by-step process to solve the problem in question.
Step 1: Recognize the general form of the function.
This is known as the difference of squares.
Step 2: Identify what is known.
Step 3: Substitute the known values into the difference of perfect squares found in step 1.
Step 4: Answer the question.
To find the positive solution set each binomial equal to zero and solve for x.
Therefore the positive solution is four.
Example Question #91 : Triangles
An meteor crashed in the desert and created an oblong shaped crater. Scientists want to find the width of the crater as it is near their research facility. Line segments AC and DE intersect at B making the angles E and D the same. If AB is 2000 meters, BD is 1800 meters, DC is 600 meters and EB is 3600 meters, what is the width of the crater?
To calculate the width of the crater, use the given information to establish that the image draws similar triangles. When triangles that have corresponding angles and a ratio to their side lengths they are considered to be similar triangles.
Identify the known information.
therefore,
and the bases of the triangles are parallel.
Also,
Set up the side ratios for this particular problem.
Looking at the only full ratio that is given, the scalar multiplier can be found.
Therefore, to find the width of the crater multiply by two.
Example Question #2064 : Sat Mathematics
If
and
What is ?
First, solve this equation for y and then substitute the answer into the second equation:
Now substitute into the second equation and solve for x:
To solve for x, add the coefficients on the x variables together then divide both sides by three.
Example Question #216 : New Sat
Given a right triangle whose and , find .
To solve for first identify what is known.
The question states that is a right triangle whose and . It is important to recall that any triangle has a sum of interior angles that equals 180 degrees.
Therefore, to calculate use the complimentary angles identity of trigonometric functions.
and since , then
Example Question #217 : New Sat
If the following are true, solve for .
Given the two equations, substitute the numerical value of into the second equation to solve for .
Substituting the numerical value for into the equation with is as follows.
From here, distribute the three.
Now square both side of the equation.
Remember to square both terms within the parentheses. Also, recall that squaring a square root sign cancels them out.
To solve for divide both sides by six.
Example Question #218 : New Sat
If , what is the value of ?