All MCAT Physical Resources
Example Questions
Example Question #12 : Force Equilibrium
A 2kg mass is suspended on a rope that wraps around a frictionless pulley. The pulley is attached to the ceiling and has a mass of 0.01kg and a radius of 0.25m. The other end of the rope is attached to a massless suspended platform, upon which 0.5kg weights may be placed. While the system is initially at equilibrium, the rope is later cut above the weight, and the platform subsequently raised by pulling on the rope.
Assuming the system is motionless, how many weights must be on the suspended platform?
One
Six
Three
Four
Nine
Four
Given that the system is motionless and that the tensional force is constant throughout the rope, we know that the weights on the platform must balance the weight of the mass. Given that the mass weights 2kg and each weight is 0.5kg, we can determine the number of weights required by dividing 2kg/0.5kg = 4 weights. Note that we can neglect the weight of the pulley in this problem; while this is usually the case on the MCAT as well, be sure to double check.
Example Question #232 : Newtonian Mechanics And Motion
An object mass is on a table with a coefficient of kinetic friction of . The object is tied to another object of the same mass by a string on an ideal, frictionless pulley. the object on the table is moving to the right due to the uniform force .
What force needs to act on the block on the table in order to give the two blocks an acceleration of to the right?
For acceleration to be zero, the force needs to equal the sum of the frictional force on the block and the gravitational force on the hanging block.
To then accelerate the system, an additional force is needed.
This is the additional force required. Thus the total force required is:
Example Question #233 : Newtonian Mechanics And Motion
A force and a force act at the same point on a block of wood. The force is pushing east and the force is pushing north. What is the summed force vector?
Northeast
Northeast
North
Northwest
Northwest
Northeast
Since the two vectors are perpendicular, they form a right triangle with the vector sum. Therefore, we simply use the Pythagorean theorem to solve for the sum.
The two vector components' directions determine the vector sum's direction as well. Since the components are north and east, the resultant vector is roughly northeast.
Example Question #13 : Force Equilibrium
A shuttle launched into space continues to fly in the direction it was sent even after its thrusters have turned off. What law does this illustrate?
Newton's first law
Pascal's principle
Snell's law
Kirchhoff's first law
Newton's second law
Newton's first law
Newton's first law indicates that an object in motion will "want" to remain in motion at constant velocity unless it is acted on by a net force. In this case, Newton's first law is the only reasonable answer since in space, it is assumed there is no frictional or gravitational forces acting on the shuttle. Newton's second law can be described using the equation . Note that his first law is just a special case of the second law, where . Snell's law describes the interaction between waves and different media. Kirchhoff's laws involve charge conservation within circuits. Pascale's principle indicates that pressure exerted within a fluid is exerted equally in all directions.
Example Question #46 : Forces
An object mass is on a table with a coefficient of kinetic friction of . The object is tied to another object of the same mass by a string on an ideal, frictionless pulley. The object on the table is moving to the right due to the uniform force .
What force needs to act on the object on the table to cause it to accelerate to the right at a constant velocity of ?
Since the block is moving to the right, we know that the frictional force is acting to the left. Also acting to the left is the gravitational force on the hanging block. Since it is a constant velocity of , we know that acceleration is zero and the downward force on the hanging block plus the frictional force is exactly equal to the force . Add the two forces.
Example Question #1 : Newton's Second Law
What is the acceleration of the system shown above? (Assume the table is frictionless and the mass of the rope connecting blocks is negligible).
The force that translates to the entire system is that of gravity acting on the mass hanging over the ledge.
140N is the total force acting on the system, which has a mass equal to both blocks combined (65 kg + 14 kg = 79 kg). We can find the acceleration using Newton's second law.
Example Question #1 : Newton's Second Law
A 2kg lead ball is loaded into a spring cannon and the cannon is set at a 45º angle on a platform. The spring has a spring constant of 100N/m and the ball and spring system is compressed by 1m before launch. While the ball is in flight air resistance can be neglected, and the ball finishes its flight by landing at a cushion placed some distance away from the cannon.
What is the acceleration of the ball during launch?
53m/s2
50m/s2
10m/s2
19m/s2
50m/s2
Newton’s second law can be used in combination with the spring force equation to solve for the acceleration of the system. Remember that any force, whether it is kinematic, electrical, or gravitational, is equal to Newton’s second law.
Fspring = kx = masystem
Example Question #11 : Ap Physics 1
A potted plant is hanging from a rope attached to a hook. The plant exerts 25N of force. Assume the rope is weightless.
If the packaging says the rope is able to withstand 800N of force, what is the maximum amount of mass that can be hanging from the rope?
If the rope can only withstand 800N of force, we can solve for the mass of the object which would result in this maximum force when hanging from the rope.
Example Question #11 : Ap Physics 1
A skydiver with a mass of 100kg jumps out of an airplane and reaches a terminal velocity of .
Which of the following factors will not decrease the total force on the man as he jumps from the plane?
Increasing the man's mass
The man immediately opens his parachute
The man jumps as the plane is descending sharply
The man orients his stomach toward the ground, rather than his feet
Increasing the man's mass
The equation for force is This shows that by increasing the man's mass, his force will increase after jumping from the plane.
All other options will result in a decreased acceleration when falling. Falling with his stomach downward increases the surface area of the diver, which increases his air resistance. A parachute will also increase the air resistance and surface area. If the plane is descending when he jumps, his time to reach terminal velocity will be reduced, as he will already have an initial velocity in the downward direction.
Example Question #1 : Newton's Second Law
If a jet accelerates on a runway at and the net force in the horizontal plane is equal to , what is the mass of the jet?
To solve this problem use Newton's second law:
We are given the acceleration and the force, both in the horizontal direction. Using these values we can find the mass of the jet.
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