All MCAT Physical Resources
Example Questions
Example Question #3 : Voltaic/Galvanic Cells
A student conducts an experiment for a chemistry class. The student wishes to explore power generation from different types of voltaic cells. He sets up three different cells, and then compares the amount of energy generated from each one.
One of his cells is shown below as an example. Both remaining cells follow the same layout.
The student in the passage wants to replace the water, represented by the blue in the diagram, with an alternative solvent. Which solvent would be most likely to produce a functioning cell?
Acetic acid
Ethane
Heptane
Benzene
Carbon tetrachloride
Acetic acid
The function of a voltaic cell requires the generation and dissolution of ions. Acetic acid is the only answer choice with a net dipole moment, and would therefore be the only one to dissolve the ions produced. The other choices would be unable to dissolve the ions, and the cell would not function.
Example Question #4 : Voltaic/Galvanic Cells
A student conducts an experiment for a chemistry class. The student wishes to explore power generation from different types of voltaic cells. He sets up three different cells, and then compares the amount of energy generated from each one.
One of his cells is shown below as an example. Both remaining cells follow the same layout.
If the structure labeled X were removed from the cell, which of the folllowing would be true?
The reduction potential for is 0.34. The reduction potential for 0.80.
Copper ions forming during cell function would be increasingly repelled by existing ions in solution
Ag ions forming during cell function would be inceasingly attracted by existing ions in solution
Ag ions forming during cell function would be inceasingly repelled by existing ions in solution
The cell would generate an uncontrolled burst of high energy
Copper ions forming during cell function would be increasingly attracted by existing ions in solution
Copper ions forming during cell function would be increasingly repelled by existing ions in solution
As the cell runs, only copper produces ions. Silver actually loses ions from solution. If this continues without balance by the salt bridge, the positive ions build up in the solution on the left side of the diagram, without any balanced negative ions, and repel the formation of new copper ions more and more strongly.
Example Question #5 : Voltaic/Galvanic Cells
A student conducts an experiment for a chemistry class. The student wishes to explore power generation from different types of voltaic cells. He sets up three different cells, and then compares the amount of energy generated from each one.
One of his cells is shown below as an example. Both remaining cells follow the same layout.
The student in the passage disassembles the cell, and attempts to rebuild it the next day. He forgets, however, to include in the solvent of the half cell on the right side of the diagram. Which of the following is likely to happen?
The cell will not function at all
The cell will function, but for a shorter period of time before it reaches equilibrium and ceases to produce energy
The cell requires , not , in the right-side half reaction to function properly
The cell will produce more energy, because there is no existing ion to repel further ionization into solution
The cell will function without pre-existing in solution, but not without
The cell will not function at all
There must be pre-existing in the right-side half reaction for the cell to function at all. Without the pre-existing ions, the cell has no electron acceptor dissolved in solution, and no electron transfer can therefore take place. Electron transfer is the fundamental energy-producing process that takes place in a voltaic cell.
Example Question #11 : Electrochemistry
A student conducts an experiment for a chemistry class. The student wishes to explore power generation from different types of voltaic cells. He sets up three different cells, and then compares the amount of energy generated from each one.
One of his cells is shown below as an example. Both remaining cells follow the same layout.
Which of the following compounds could be used to construct the structure labeled "X"?
Structure "X" corresponds to the slat bridge. Its main function is balancing the ionic charge that builds up as a voltaic cell functions; therefore, there needs to be an ability for the salt bridge to ionize and send appropriate ions to each half cell. KOH is the only ionizable salt among the answer choices.
Example Question #21 : Electrochemistry
When a galvanic cell contains two different solutions, a salt bridge is often required. The salt bridge allows the two solutions to remain isolated by providing ionic interactions for both solutions, without severely reducing the potential difference. The salt bridge is commonly composed of a potassium chloride solution.
In what direction would you expect the potassium ions to travel in a galvanic cell?
The ions will distribute evenly in the salt bridge
The potassium will remain bound to chlorine, and will not ionize
Toward the cathode
Toward the anode
Toward the cathode
Potassium ions (K+) will be positively charged, which means they will travel towards the side of the cell that is more negative. Reduction takes place at the cathode, because electrons flow from the anode to the cathode. Since negative charge accumulates at the cathode, the cations will travel in that direction, while the anions will travel towards the anode.
Example Question #22 : Electrochemistry
Imagine a galvanic cell which uses solid zinc and aqueous iron ions to produce a voltage.
The cell above resulted in a transfer of 0.05mol of electrons. The cell ran for four minutes at a constant voltage. What is the current of the cell?
This problem requires us to use dimensional analysis in order to compare what we know, and arrive at the current of the cell. First, we start by noting that the unit for current is Coulombs per second, or . Next, we combine the details of the galvanic cell in order to arrive at the appropriate units, and determine the current.
Example Question #21 : Electrochemistry
You are charging your cell phone battery with your cell phone charger. What can you conclude about this process?
The cell phone battery is acting as a galvanic cell because it is acquiring voltage
The cell phone battery is acting as a galvanic cell because it is releasing voltage
The cell phone battery is acting as an electrolytic cell because it is acquiring voltage
The cell phone battery is acting as an electrolytic cell because it is releasing voltage
The cell phone battery is acting as an electrolytic cell because it is acquiring voltage
A single battery can act as both a galvanic and an electrolytic cell. When a battery is discharging it is considered to be a galvanic cell because it is undergoing a spontaneous redox reaction and is losing voltage. On the other hand, when a battery is charging, it is acquiring voltage (from the phone charger that is connected to an outlet) and is considered an electrolytic cell.
Recall that electrolytic cells facilitate nonspontaneous reactions and require energy to carry out these unfavorable reactions. Charging a battery is a nonspontaneous process (because the reaction involved is the reverse of the reaction that occurs when the battery is discharging) and requires energy in the form of voltage input.
Example Question #1 : Other Electrochemical Principles
A researcher is analyzing an electrolytic cell. In trial 1, he applies of current for two hours to the cell and observes that the cathode produces of zinc metal. In trial 2, he applies the same amount of current but only for one hour. What will the researcher observe in the cathode during trial 2?
Same amount of zinc as trial 1 because the applied charge stays the same
Same amount of zinc as trial 1 because the current stays the same
Larger amount of zinc than trial 1 because the charge decreases
Smaller amount of zinc than trial 1 because the applied charge decreases
Smaller amount of zinc than trial 1 because the applied charge decreases
Faraday’s Law states that the amount of substance produced in a half-cell is dependent on the charge applied to the system; therefore, the more charge applied the more substance produced. The question states that the researcher applies the same amount of current, but for a shorter time, in trial 2. Recall the definition of current:
This means that charge equals:
Trial 1 and Trial 2 have the same current; however, trial 2 has a smaller time. This means that the charge applied in trial 2 is smaller than the charge applied in trial 1; therefore, according to Faraday’s law, the researcher must observe a smaller mass of zinc metal in trial 2.
Example Question #1 : Other Electrochemical Principles
Faraday’s Law states that the amount of product in a cell __________ as the __________ increases.
increases . . . charge
increases . . . time
decreases . . . charge
decreases . . . time
increases . . . charge
Faraday’s Law states that the amount of product in a half cell is proportional to the charge applied to the cell; therefore, the amount of product in a cell increases as the charge increases. Faraday’s Law states nothing about the relationship between the amount of product and time.
Example Question #21 : Electrochemistry
Which of the following substances cannot conduct electricity in water?
I. Sodium chloride
II. Iron (II) carbonate
III. Glucose
I and II
I only
II and III
II only
II and III
The question asks you to pick substances that cannot conduct electricity. Recall that molecules that conduct electricity in solution are called electrolytes. In a chemical solution, a substance will conduct electricity if it can dissociate into ions; therefore, you are looking for molecules that will not dissociate into ions in water.
Sodium chloride, or , is an ionic compound that will dissociate into sodium ions and chlorine ions; therefore, sodium chloride will conduct electricity in water.
Iron (II) carbonate is an insoluble compound in water. This means that it will not dissociate into ions and will not conduct electricity. Remember that most carbonates are insoluble in water.
Glucose is soluble in water because of its polar hydroxyl groups; however, it does not dissociate into ions. This means that glucose does not conduct electricity.
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