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Flashcards: Operations and Algebraic Thinking

Complete the table below using the equation y=10x+4 $\displaystyle y=10x+4$

Screen shot 2015 07 27 at 8.52.55 am

172 $\displaystyle 172$

162 $\displaystyle 162$

164 $\displaystyle 164$

174 $\displaystyle 174$

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Flashcards: Operations and Algebraic Thinking

Complete the table below using the equation y=10x+4 $\displaystyle y=10x+4$

Screen shot 2015 07 27 at 8.52.55 am

172 $\displaystyle 172$

162 $\displaystyle 162$

164 $\displaystyle 164$

174 $\displaystyle 174$

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Flashcards: Operations and Algebraic Thinking

Complete the table below using the equation y=10x+4 $\displaystyle y=10x+4$

Screen shot 2015 07 27 at 8.52.55 am

Your answer:

172 $\displaystyle 172$

Your answer:

162 $\displaystyle 162$

Your answer:

174 $\displaystyle 174$

Correct answer:

164 $\displaystyle 164$

Explanation:

We need to use both the equation and the table to answer this question. We are looking for the corresponding $\displaystyle y$ value for x=16 $\displaystyle x=16$ . We can plug $\displaystyle 16$ into the $\displaystyle x$ in our equation to solve for $\displaystyle y$ .

$\displaystyle y=10(16)+4$

y=160+4 $\displaystyle y=160+4$

y=164 $\displaystyle y=164$

Flashcards: Operations and Algebraic Thinking

Sally drank $\frac{1}{12}$ $\displaystyle \frac{1}{12}$ of the milk and Sam drank $\frac{2}{3}$ $\displaystyle \frac{2}{3}$ . What fraction of the milk did they drink?

$\frac{1}{2}$ $\displaystyle \frac{1}{2}$

$\frac{5}{7}$ $\displaystyle \frac{5}{7}$

$\frac{3}{4}$ $\displaystyle \frac{3}{4}$

$\frac{3}{15}$ $\displaystyle \frac{3}{15}$

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Flashcards: Operations and Algebraic Thinking

Sally drank $\frac{1}{12}$ $\displaystyle \frac{1}{12}$ of the milk and Sam drank $\frac{2}{3}$ $\displaystyle \frac{2}{3}$ . What fraction of the milk did they drink?

Your answer:

$\frac{1}{2}$ $\displaystyle \frac{1}{2}$

Your answer:

$\frac{5}{7}$ $\displaystyle \frac{5}{7}$

Your answer:

$\frac{3}{15}$ $\displaystyle \frac{3}{15}$

Correct answer:

$\frac{3}{4}$ $\displaystyle \frac{3}{4}$

Explanation:

$\frac{1}{12}+\frac{2}{3}$ $\displaystyle \frac{1}{12}+\frac{2}{3}$

In order to solve this problem, we first need to make common denominators.

$\frac{2}{3}\times\frac{4}{4}=\frac{8}{12}$ $\displaystyle \frac{2}{3}\times\frac{4}{4}=\frac{8}{12}$

Now that we have common denominators, we can add the fractions. Remember, when we add fractions, the denominator stays the same, we only add the numerator.

$\frac{1}{12}+\frac{8}{12}=\frac{9}{12}$ $\displaystyle \frac{1}{12}+\frac{8}{12}=\frac{9}{12}$

$\frac{9}{12}$ $\displaystyle \frac{9}{12}$ can be reduced by dividing $\displaystyle 3$ by both sides.

$\frac{9}{12}\div \frac{3}{3}=\frac{3}{4}$ $\displaystyle \frac{9}{12}\div \frac{3}{3}=\frac{3}{4}$

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