As soon as we know that Dana performs second we can place Ona in the first spot. Therefore any answer that has someone other than Ona performing first OR has Ona performing somewhere other than first cannot be true. We know that the fifth spot must be a solo, so the answer that has Linda performing fifth must be wrong automatically, because she always has to perform with Nicole. If we place Carrie in the second spot with Dana we automatically place Belle in the fourth spot because of our conditional. If Amy performs third, we know she has to perform alone. This leaves us with Nicole, Linda and Monique left to place. Since Nicole and Linda have to perform together, Monique must perform fifth alone. We then have to place Nicole and Linda in the fourth spot with Belle, since Amy always performs alone and placing them in the second spot with Dana and Carrie would create a quartet. In this scenario, Dana is NOT in a trio, so this answer is incorrect. The correct answer (Carrie performs second and Nicole performs third) yields the following set list: First: Ona; Second: Dana, Carrie, Monique; Third: Nicole, Linda; Fourth: Belle; Fifth: Amy.

We can figure this one out from the initial set-up of the game. If we are placing eight dancers into five numbers, we know there has to be one girl in each spot. This takes care of five dancers. We have three left over. Our options are to place all three in different numbers, yielding a 1:1:2:2:2 ratio OR to place two in one number and one in another, yielding a 1:1:1:2:3 ratio. Therefore the only correct answer is that there is at most one trio.

This is a simple list question turned inside out. In order to answer this question we need to figure out who is chosen for the committe in each answer and elminate answers based on rule violations. We know that Harris and McHenry cannot both be chosen and Nin and Innis cannot both be chosen. If Innis is chosen, Kenzi must also be chosen, as when Harris is chosen Innis must also be chosen. We also know that at least one of Harris and Jenkins must always be chosen, so any answer that has both of them out is wrong. The only correct possibility leaves this committee: Harris, Innis, Kenzi.

We know that when Harris is chosen, Innis must also be chosen. If Innis is chosen, Kenzi must also be chosen. So the smallest possible group is Harris, Innis and Kenzi. Nin and Innis cannot both be chosen, so Nin cannot be in this group. McHenry and Harris cannot both be chosen, so McHenry also cannot be in this group. The only answer that could be true is that Jenkins is chosen - Jenkins does not have to be in this group but could be.

We know that if Jenkins is not chosen, Harris is. Therefore if Harris is not chosen, Jenkins is. This means that we must always have at least one or the other of these two in the game. If Harris is chosen this leads to several other members being chosen as well, but if Jenkins is chosen he could be the only representative on the committee.

The only answer that would exceed three people is Harris and Jenkins are both chosen. When Harris is chosen we must also choose Innis and then Kenzi. Choosing Jenkins as well would require four people to be on the committee. The other answers yield the following groups: Harris, Kenzi, Innis; Kenzi, Lawrence, Jenkins; Nin, McHenry, Jenkins; McHenry, Lawrence, Jenkins

The only false statement here is that Harris and Jenkins cannot both be chosen - no rule states this. We know from the rules that McHenry and Harris cannot both be chosen, and that Nin and Innis cannot both be chosen. Since McHenry must be chosen when Nin is chosen, Nin therefore cannot be chosen with Harris either. There is no rule that states that McHenry and Innis cannot be chosen together.

To answer this question we start by choosing Nin. We then automatically choose McHenry and eliminate Innis. Because we have chosen McHenry, we eliminate Harris. Eliminating Harris forces us to choose Jenkins. All that are left are Kenzi and Lawrence, who could or could not be chosen. Therefore, if we wanted to create the largest possibly committee starting with Nin, we could add in McHenry, Jenkins, Lawrence and Kenzi. 

Make sure you accurately understand each rule, then apply the rules to eliminate each incorrect answer.  Each incorrect answer directly violates at least one rule.

Sara cannot be in the same section as Nora, but Nora must be in the same section as Ulric.  As a result, Sara is prohibited from being in the same section as Ulric, just as she is prohibited from being in the same section as Nora.