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Linear Algebra : Eigenvalues and Eigenvectors of Symmetric Matrices

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Example Question #11 : Eigenvalues And Eigenvectors Of Symmetric Matrices

$\begin{align*}&\text{Find any and all eigenvalues for the matrix }\\&A=\begin{bmatrix}3&2&15\\2&-7&-16\\15&-16&-1\end{bmatrix}\end{align*}$

Possible Answers:

$\lambda_{1}=-30.16;\lambda_{2}=-4.74;\lambda_{3}=14.90$

$\lambda_{1}=-34.16;\lambda_{2}=-8.74;\lambda_{3}=10.90$

$\lambda_{1}=-25.16;\lambda_{2}=0.26;\lambda_{3}=19.90$

$\lambda_{1}=-27.16;\lambda_{2}=-1.74;\lambda_{3}=17.90$

Correct answer:

$\lambda_{1}=-25.16;\lambda_{2}=0.26;\lambda_{3}=19.90$

Explanation:

$\begin{align*}&\text{Eigenvalues of a matrix, typically noted as }\lambda\text{, are those values which satisfy}\\&det(A-\lambda I)\text{(I being the identity matrix). For the matrix }A=\begin{bmatrix}3&2&15\\2&-7&-16\\15&-16&-1\end{bmatrix}\\&\text{We can represent that equation as follows }\begin{bmatrix}3 - \lambda&2&15\\2&- \lambda - 7&-16\\15&-16&- \lambda - 1\end{bmatrix}\\&\text{For a square matrix with dimensions of }3\\&det\begin{vmatrix} a&b&c \\ d&e&f\\g&h&i \end{vmatrix}=a(ei-fh)-b(di-fg)+c(dh-eg)\\&\text{From that, we can find the eigenvalues:}\\&(-1)\cdot (5\lambda ^{2} - 502\lambda + \lambda ^{3} + 128)\\&\lambda_{1}=-25.16;\lambda_{2}=0.26;\lambda_{3}=19.90\\&\text{Note that since our matrix was symmetric, our eigenvalues are real.}\end{align*}$

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Example Question #471 : Operations And Properties

$\begin{align*}&\text{Find the eigenvalues for the matrix }\\&A=\begin{bmatrix}18&-12&9\\-12&-16&4\\9&4&7\end{bmatrix}\end{align*}$

Possible Answers:

$\lambda_{1}=-21.38;\lambda_{2}=5.39;\lambda_{3}=24.99$

$\lambda_{1}=-16.38;\lambda_{2}=10.39;\lambda_{3}=29.99$

$\lambda_{1}=-30.38;\lambda_{2}=-3.61;\lambda_{3}=15.99$

$\lambda_{1}=-18.38;\lambda_{2}=8.39;\lambda_{3}=27.99$

Correct answer:

$\lambda_{1}=-21.38;\lambda_{2}=5.39;\lambda_{3}=24.99$

Explanation:

$\begin{align*}&\text{Eigenvalues of a matrix A, usually denoted as }\lambda\text{, are values which satisfy}\\&det(A-\lambda I)\text{, where I is the identity matrix. For our matrix }A=\begin{bmatrix}18&-12&9\\-12&-16&4\\9&4&7\end{bmatrix}\\&\text{We can define a matrix of the form }\begin{bmatrix}18 - \lambda&-12&9\\-12&- \lambda - 16&4\\9&4&7 - \lambda\end{bmatrix}\\&\text{For a square matrix with dimensions of }3\\&det\begin{vmatrix} a&b&c \\ d&e&f\\g&h&i \end{vmatrix}=a(ei-fh)-b(di-fg)+c(dh-eg)\\&\text{Using this, we can solve for our eigenvalues:}\\&(-1)\cdot (\lambda ^{3} - 9\lambda ^{2} - 515\lambda + 2880)\\&\lambda_{1}=-21.38;\lambda_{2}=5.39;\lambda_{3}=24.99\\&\text{Note that since our matrix was symmetric, our eigenvalues are real.}\end{align*}$

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Example Question #552 : Linear Algebra

$\begin{align*}&\text{Find any and all eigenvalues for the matrix }\\&A=\begin{bmatrix}-13&10&-11\\10&-9&11\\-11&11&-17\end{bmatrix}\end{align*}$

Possible Answers:

$\lambda_{1}=-34.75;\lambda_{2}=-3.90;\lambda_{3}=-0.35$

$\lambda_{1}=-42.75;\lambda_{2}=-11.90;\lambda_{3}=-8.35$

$\lambda_{1}=-36.75;\lambda_{2}=-5.90;\lambda_{3}=-2.35$

$\lambda_{1}=-29.75;\lambda_{2}=1.10;\lambda_{3}=4.65$

Correct answer:

$\lambda_{1}=-34.75;\lambda_{2}=-3.90;\lambda_{3}=-0.35$

Explanation:

$\begin{align*}&\text{Eigenvalues of a matrix, typically noted as }\lambda\text{, are those values which satisfy}\\&det(A-\lambda I)\text{(I being the identity matrix). For the matrix }A=\begin{bmatrix}-13&10&-11\\10&-9&11\\-11&11&-17\end{bmatrix}\\&\text{We can represent that equation as follows }\begin{bmatrix}- \lambda - 13&10&-11\\10&- \lambda - 9&11\\-11&11&- \lambda - 17\end{bmatrix}\\&\text{For a square matrix with dimensions of }3\\&det\begin{vmatrix} a&b&c \\ d&e&f\\g&h&i \end{vmatrix}=a(ei-fh)-b(di-fg)+c(dh-eg)\\&\text{From that, we can find the eigenvalues:}\\&(-1)\cdot (149\lambda + 39\lambda ^{2} + \lambda ^{3} + 47)\\&\lambda_{1}=-34.75;\lambda_{2}=-3.90;\lambda_{3}=-0.35\\&\text{Note that since our matrix was symmetric, our eigenvalues are real.}\end{align*}$

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Example Question #481 : Operations And Properties

$\begin{align*}&\text{Calculate the eigenvalues for the matrix }\\&\begin{bmatrix}-5&17&-20\\17&-3&-2\\-20&-2&12\end{bmatrix}\end{align*}$

Possible Answers:

$\lambda_{1}=-26.37;\lambda_{2}=0.91;\lambda_{3}=29.46$

$\lambda_{1}=-24.37;\lambda_{2}=2.91;\lambda_{3}=31.46$

$\lambda_{1}=-30.37;\lambda_{2}=-3.09;\lambda_{3}=25.46$

$\lambda_{1}=-18.37;\lambda_{2}=8.91;\lambda_{3}=37.46$

Correct answer:

$\lambda_{1}=-26.37;\lambda_{2}=0.91;\lambda_{3}=29.46$

Explanation:

$\begin{align*}&\text{Eigenvalues of a matrix A, often denoted as }\lambda\text{, are values which satisfy}\\&det(A-\lambda I)\text{, where I represents the identity matrix. For the given matrix }\begin{bmatrix}-5&17&-20\\17&-3&-2\\-20&-2&12\end{bmatrix}\\&\text{We can write a matrix of the form }\begin{bmatrix}- \lambda - 5&17&-20\\17&- \lambda - 3&-2\\-20&-2&12 - \lambda\end{bmatrix}\\&\text{For a square matrix with dimensions of }3\\&det\begin{vmatrix} a&b&c \\ d&e&f\\g&h&i \end{vmatrix}=a(ei-fh)-b(di-fg)+c(dh-eg)\\&\text{Knowing this, we can expand and solve:}\\&(-1)\cdot (\lambda ^{3} - 4\lambda ^{2} - 774\lambda + 708)\\&\lambda_{1}=-26.37;\lambda_{2}=0.91;\lambda_{3}=29.46\\&\text{Note that since our matrix was symmetric, our eigenvalues are real.}\end{align*}$

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Example Question #15 : Eigenvalues And Eigenvectors Of Symmetric Matrices

$C= \begin{bmatrix} 4 & a \\ a & 8 \end{bmatrix}$ ,

where is a real number.

For to have two real eigenvalues, what must be true for ?

Possible Answers:

a < -4 or a > 4

$a < - 4 \sqrt{2}$ or $a > 4 \sqrt{2}$

-4 < a < 4

$-4 \sqrt{2} < a < 4 \sqrt{2}$

can be any real number.

Correct answer:

can be any real number.

Explanation:

Any real value of makes a symmetric matrix with real entries. It holds that any eigenvalues of must be real regardless of the value of .

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Example Question #561 : Linear Algebra

$G = \begin{bmatrix} b & b \\ b & b \end{bmatrix}$

Give the set of eigenvalues of in terms of , if applicable.

Possible Answers:

The eigenvalues are b+ bi and b - bi .

The only eigenvalue is 0.

The eigenvalues are 0 and .

The only eigenvalue is .

The eigenvalues are 0 and .

Correct answer:

The eigenvalues are 0 and .

Explanation:

An eigenvalue of is a zero of the characteristic equation formed from the determinant of $\lambda I - G$ , so find this determinant as follows:

$\lambda I - G$

$= \lambda \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix} - \begin{bmatrix} b & b \\ b & b \end{bmatrix}$

$= \begin{bmatrix} \lambda & 0 \\ 0 & \lambda \end{bmatrix} - \begin{bmatrix} b & b \\ b & b \end{bmatrix}$

Subtracting elementwise:

$= \begin{bmatrix}\lambda - b & - b \\- b & \lambda -b \end{bmatrix}$

Set the determinant to 0 and solve for $\lambda$ :

$\begin{vmatrix}\lambda - b & - b \\- b & \lambda -b \end{vmatrix} = 0$

The determinant can be found by taking the upper-left-to-lower-right product and subtracting the upper-right-to-lower-left product:

$(\lambda - b)(\lambda - b) - (-b) (-b) = 0$

$\lambda ^{2} - 2 \lambda b + b^{2} - b^{2} = 0$

$\lambda ^{2} - 2 \lambda b = 0$

$\lambda \left (\lambda - 2b \right ) = 0$ ,

so the eigenvalues of this matrix are 0 and .

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Linear Algebra : Eigenvalues and Eigenvectors of Symmetric Matrices

Study concepts, example questions & explanations for Linear Algebra

All Linear Algebra Resources

Example Questions

Example Question #11 : Eigenvalues And Eigenvectors Of Symmetric Matrices

Example Question #471 : Operations And Properties

Example Question #552 : Linear Algebra

Example Question #481 : Operations And Properties

Example Question #15 : Eigenvalues And Eigenvectors Of Symmetric Matrices

Example Question #561 : Linear Algebra

All Linear Algebra Resources

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