To find probability, you have to consider part over whole. The total number of marbles is 12. Then, identify how many red marbles there are (3). From there, you can make a fraction , which can be simplified to .

One-ninth of the 36 possible rolls is 4, so we are looking for an outcome that can happen four ways.

There are 6 ways that both dice can show the same number - double 1, double 2, and so forth.

There are 3 ways to roll a sum of 10: (4,6), (5,5), and (6,4).

There are 6 ways to roll a sum divisible by 6: (1,5), (2,4), (3,3), (4,2), and (5,1) all yield 6, and (6,6) yields 12.

There are 4 ways to roll a sum of 5: (1,4), (2,3), (3,2), and (4,1). 

There are 3 ways to roll a sum of 4: (1,3), (2,2), (3,1).

The correct choice is the event that the sum of the dice is 5.

Given that in Gina’s bag of 12 marbles, half of them are black and half are white, this means that there are 6 black marbles and 6 white marbles. However, because she already picked out 2 white marbles, this means that there are now only 4 out of 10 white marbles left. 4 out of 10 converts to 40 percent, which is therefore the correct answer. 

If 10 percent of puppies are born with spots, and of those, 50 percent have black spots, then the total percent of puppies who have spots AND the color of the spots is black can be found by multiplying the two percentages by one another:

0.05 is the equivalent of 5 percent, the correct answer. 

There are 10 total participants in the raffle.

288, 289, 290, 291, 292, 292, 294, 295, 296, 297

Only 2 participants have tickets with numbers that beging in 2 and 8.; therefore, Jenny has a 50 percent chance of holding the winning raffle ticket.

The winner is either 288 or 289, leaving Jenny a 50 percent chance. 

If each boy gets 7 raffle tickets, that means that each girl gets 14 raffle tickets. 

Therefore, Tracy will have 14 raffle tickets, and the total number of raffle tickets will be equal to . 

Thus, Tracy's chance of winning will be equal to:

Whenever an even number is added to an odd number, the result is odd. Whenever an even number is added to an even number, the result is even. 

Given that all the numbers in set  are even, there is a 100 percent chance of an even number being selected; however in set , one of the three numbers is odd, so there is a one third chance of an odd number being selected. 

Given that the sum of an even number and an odd number is odd, there is a probability of  that the sum of a number randomly selected from set  and from set  wil be an odd number. 

The only way in which a negative number would be acheived by subtracting  is if  was equal to 2, and any number was selected for . 

Therefore, the chance of  resulting in a negative number would be equal to the odds of selecting 2 from set . Given that there are four numbers in set , there is a one fourth chance. 

Thus, the correct answer is .

The only way that a product of  will be acheived is if the number  is selected from set , and the number  is selected from set . 

There is a one half chance of the number 4 being selected and a one half chance of the number 6 being selected, given that each set contains two numbers. 

Therefore, the probability of both these number being chosen is:

If Mark flips a coin, the chance that it will land on heads is . On a die, there are 2 out of 6 numbers that are a multiple of 3 (3 and 6); therefore, there is a  chance that the dice will be a multiple of 3. 

The probability that the coin will land on heads and that the dice will be a multiple of 3 is: