Call Now to Set Up Tutoring:

(888) 888-0446

ISEE Middle Level Math : Geometry

Study concepts, example questions & explanations for ISEE Middle Level Math

Create An Account

All ISEE Middle Level Math Resources

6 Diagnostic Tests 303 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #53 : Quadrilaterals

Find the area of a square with a width of 13in.

Possible Answers:

$169\text{in}^2$

$121\text{in}^2$

$100\text{in}^2$

$144\text{in}^2$

$172\text{in}^2$

Correct answer:

$169\text{in}^2$

Explanation:

To find the area of a square, we will use the following formula:

$\text{area of square} = l \cdot w$

where l is the length and w is the width of the square.

Now, we know the width of the square is 13in. Because it is a square, we know all sides are equal. Therefore, the length is also 13in.

Knowing this, we can substitute into the formula. We get

$\text{area of square} = 13\text{in} \cdot 13\text{in}$

$\text{area of square} = 169\text{in}^2$

Report an Error

Example Question #151 : Plane Geometry

Find the area of a square with a base of 17cm.

Possible Answers:

$289\text{cm}^2$

$312\text{cm}^2$

$68\text{cm}^2$

$178\text{cm}^2$

$204\text{cm}^2$

Correct answer:

$289\text{cm}^2$

Explanation:

To find the area of a square, we will use the following formula:

$A = l \cdot w$

Now, we know the length of the square is 17cm. Because it is a square, all sides are equal. Therefore, the width is also 17cm.

Knowing this, we can substitute into the formula. We get

$A = 17\text{cm} \cdot 17\text{cm}$

$A = 289\text{cm}^2$

Report an Error

Example Question #52 : Squares

Find the area of a square with a base of 19cm.

Possible Answers:

$361\text{cm}^2$

$96\text{cm}^2$

$76\text{cm}^2$

$121\text{cm}^2$

$256\text{cm}^2$

Correct answer:

$361\text{cm}^2$

Explanation:

To find the area of a square, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the square.

Now, we know the base (or length) of the square is 19cm. Because it is a square, all sides are equal. Therefore, the width is also 19cm.

Knowing this, we can substitute into the formula. We get

$A = 19\text{cm} \cdot 19\text{cm}$

$A = 361\text{cm}^2$

Report an Error

Example Question #53 : Squares

Use the following square to answer the question:

Square2

Find the area.

Possible Answers:

$169\text{cm}^2$

$196\text{cm}^2$

$144\text{cm}^2$

$56\text{cm}^2$

$72\text{cm}^2$

Correct answer:

$196\text{cm}^2$

Explanation:

To find the area of a square, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the square.

Now, given the square

Square2

we can see the length is 14cm. Because it is a square, all sides are equal. Therefore, the width is also 14cm. Knowing this, we can substitute into the formula. We get

$A = 14\text{cm} \cdot 14\text{cm}$

$A = 196\text{cm}^2$

Report an Error

Example Question #54 : Squares

The area of a square is $121\text{in}^2$ . Find the length of one side of the square.

Possible Answers:

$13\text{in}$

$\text{There is not enough information to solve the problem.}$

$22\text{in}$

$12\text{in}$

$11\text{in}$

Correct answer:

$11\text{in}$

Explanation:

To find the area of a square, we use the following formula:

A = x^2

where x is the length of one side.

Now, we want to find the length of one side, so we will solve for x. We know the area of the square is $121\text{in}^2$ . So, we will substitute.

$121\text{in}^2 = x^2$

$\sqrt{121\text{in}^2} = \sqrt{x^2}$

$11\text{in} = x$

$x = 11\text{in}$

Therefore, the length of one side of the square is 11in.

Report an Error

Example Question #54 : Quadrilaterals

Find the area of a square with a length of 12in.

Possible Answers:

$144\text{in}^2$

$136\text{in}^2$

$48\text{in}^2$

$96\text{in}^2$

$121\text{in}^2$

Correct answer:

$144\text{in}^2$

Explanation:

To find the area of a square, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the square.

Now, we know the length of the square is 12in. Because it is a square, all sides are equal. Therefore, the width is also 12in. So, we can substitute.

$A = 12\text{in} \cdot 12\text{in}$

$A = 144\text{in}^2$

Report an Error

Example Question #61 : Squares

Find the area of a square with a width of 5in.

Possible Answers:

$10\text{in}^2$

$30\text{in}^2$

$15\text{in}^2$

$25\text{in}^2$

$20\text{in}^2$

Correct answer:

$25\text{in}^2$

Explanation:

To find the area of a square, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the square.

Now, we know the width of the square is 5in. Because it is a square, all sides are equal. Therefore, the length is also 5in. So, we can substitute. We get

$A = 5\text{in} \cdot 5\text{in}$

$A = 25\text{in}^2$

Report an Error

Example Question #153 : Plane Geometry

Find the area of a square with a length of 9in.

Possible Answers:

$63\text{in}^2$

$72\text{in}^2$

$45\text{in}^2$

$36\text{in}^2$

$81\text{in}^2$

Correct answer:

$81\text{in}^2$

Explanation:

To find the area of a square, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the square.

Now, we know the length of the square is 9in. Because it is a square, all sides are equal. Therefore, the width is also 9in. So, we get

$A = 9\text{in} \cdot 9\text{in}$

$A = 81\text{in}^2$

Report an Error

Example Question #61 : Quadrilaterals

Find the area of a square that has a width of 13in.

Possible Answers:

$52\text{in}^2$

$39\text{in}^2$

$26\text{in}^2$

$169\text{in}^2$

$118\text{in}^2$

Correct answer:

$169\text{in}^2$

Explanation:

To find the area of a square, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the square.

Now, we know the width of the square is 13in. Because it is a square, all sides are equal. Therefore, the length is also 13in.

Knowing this, we can substitute into the formula. We get

$A = 13\text{in} \cdot 13\text{in}$

$A = 169\text{in}^2$

Report an Error

Example Question #1 : How To Find The Area Of A Rectangle

What is the area of a rectangle with length $14\ cm$ and width $12\ cm$ ?

Possible Answers:

$148\; cm^{2}$

$144\; cm^{2}$

$168\;cm^{2}$

$198\;cm^{2}$

$158\;cm^{2}$

Correct answer:

$168\;cm^{2}$

Explanation:

The formula for the area, , of a rectangle when we are given its length, , and width, , is A = L * W .

To calculate this area, just multiply the two terms.

$A = 14\ cm * 12\ cm = 168\; cm^{2}$

Report an Error

View Tutors

Mike Bahaa
Certified Tutor

Concordia University-Ann Arbor, Master of Arts Teaching, Mathematics Teacher Education.

View Tutors

Reza
Certified Tutor

University of Sherbrooke, Doctor of Philosophy, Mathematics. University of Manitoba, Master of Science, Mathematics.

View Tutors

Sumit
Certified Tutor

Calcutta University, Bachelor of Science, Mathematics. Indian Statistical Institute, Master of Science, Mathematics.

All ISEE Middle Level Math Resources

6 Diagnostic Tests 303 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Physics Tutors in Atlanta, Spanish Tutors in San Francisco-Bay Area, SSAT Tutors in Phoenix, MCAT Tutors in Seattle, Chemistry Tutors in Los Angeles, Statistics Tutors in Phoenix, Algebra Tutors in Seattle, GMAT Tutors in San Francisco-Bay Area, MCAT Tutors in Los Angeles, French Tutors in San Francisco-Bay Area

Popular Courses & Classes

LSAT Courses & Classes in San Diego, GMAT Courses & Classes in Philadelphia, ACT Courses & Classes in Miami, Spanish Courses & Classes in Philadelphia, ACT Courses & Classes in San Francisco-Bay Area, GMAT Courses & Classes in Phoenix, MCAT Courses & Classes in Miami, ACT Courses & Classes in Denver, LSAT Courses & Classes in Washington DC, MCAT Courses & Classes in New York City

Popular Test Prep

LSAT Test Prep in Philadelphia, ACT Test Prep in Dallas Fort Worth, GMAT Test Prep in Miami, ACT Test Prep in San Francisco-Bay Area, LSAT Test Prep in Washington DC, ACT Test Prep in Miami, GMAT Test Prep in Philadelphia, MCAT Test Prep in San Diego, GRE Test Prep in Chicago, GRE Test Prep in Phoenix

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

ISEE Middle Level Math : Geometry

Study concepts, example questions & explanations for ISEE Middle Level Math

All ISEE Middle Level Math Resources

Example Questions

Example Question #53 : Quadrilaterals

Example Question #151 : Plane Geometry

Example Question #52 : Squares

Example Question #53 : Squares

Example Question #54 : Squares

Example Question #54 : Quadrilaterals

Example Question #61 : Squares

Example Question #153 : Plane Geometry

Example Question #61 : Quadrilaterals

Example Question #1 : How To Find The Area Of A Rectangle

All ISEE Middle Level Math Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: