In order to solve this problem, it is best to work backwards by "plugging in" the answer choices to see which one yields a correct answer. 

If 29 is the largest of the three odd consecutive numbers, then that means that the numbers being added together would be 25, 27, and 29. 

Given that , is the correct answer. 

In this sequence, every subsequent number is equal to one third of the preceding number:

Given that , that is the correct answer. 

For a set to be a subset of , all of its elements must also be elements of  - that is, all of its elements must be multiples of 5. An integer is a multple of 5 if and only if its last digit is 5 or 0, so all we have to do is examine the last digit of each number in all four sets. Every number in every set ends in 5 or 0, so every number in every set is a multiple of 5. This makes all four sets subsets of .

The elements of the set  - that is, the intersection of  and  - are exactly those in both sets. We can test each of the six elements in  for inclusion in set  by dividing each by 3 and noting which divisions yield no remainder:

 and  have three elements in common, so  has that many elements.

For a set to be a subset of , all of its elements must be elements of  - that is, all of its elements must be multiples of 4. A set can therefore be proved to not be a subset of  by identifying one element not a multiple of 4.

We can do that with all four given sets:

: 

: 

: 

: 

The correct response is therefore "None of the other responses are correct."

By dividing the numerator of each fraction by its denominator, each fraction can be rewritten as its decimal equivalent:

Of the four,  and  fall between 0.6 and 0.8 exclusive. The correct response is "two"

For a set to be a subset of , all of its elements must also be elements of  - that is, all of its elements must be multiples of 4. An integer is a multple of 4 if and only the number formed by its last two digits is also a multiple of 4, so all we have to do is examine the last two digits of each number in all four sets. 

Of all of the numbers in the four sets listed, only 8,878 has this characteristic:

8,878 is not a multiple of 4, so among the sets from which to choose,

is the only set that is not a subset of .

If every number that appears in set  also appears in set , that means that set  must be broader than set . 

Any number that is a multiple of 16 will also be a multiple of 8 (characteristic of set ); therefore, if set  consists of multiples of 16, set  will include all those numbers. 

Therefore, Set  can consist of multiples of 16. 

In this set, each subsequent fraction is half the size of the preceding fraction; (the denominator is doubled for each successive fraction, but the numerator stays the same). Given that the last fraction in the set is , it follows that the subsequent fraction will be . 

A prime number only has two factors, one and itself.   and  are the only values given that have that property.  But the range of the set is between  and  which means that the answer cannot be  since it is greater than .  That means the final answer is .