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ISEE Middle Level Math : Equations

Study concepts, example questions & explanations for ISEE Middle Level Math

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Example Questions

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Example Question #361 : Equations

Solve for b when f is equal to 0

$b^3=\frac{4}{f}+2$

Possible Answers:

No real solutions

$b=\sqrt[3]{2}$

b=8

b=-2

Correct answer:

No real solutions

Explanation:

Solve for b when f is equal to 0

$b^3=\frac{4}{f}+2$

Let's start by plugging in 0 for f

$b^3=\frac{4}{(0)}+2$

Now, we cannot go any further, because we cannot divide by zero.

This means that there is no value of b for which f will equal zero.

This means we have no real solutions.

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Example Question #362 : How To Find The Solution To An Equation

Solve the following equation for u when y is equal to 6.

$\frac{4y}{u}=12$

Possible Answers:

Correct answer:

Explanation:

Solve the following equation for u when y is equal to 6.

$\frac{4y}{u}=12$

To begin, let's plug in 6 for y.

$\frac{4*6}{u}=12$

Next, bring the u over to the other side by multiplying both sides by u

24=12u

Finally, divide both sides by 12 to see what u is

$\frac{24}{12}=u=2$

So we get u=2 as our answer.

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Example Question #363 : How To Find The Solution To An Equation

Solve for x in the following equation:

2x = 10

Possible Answers:

Correct answer:

Explanation:

To solve for x, we want x to stand alone or to be by itself. So in the equation

2x = 10

we want x to stand alone. To do that, we need to cancel the that is next to it. The is being multiplied to x, so to cancel it out, we will need to divide by . If we divide by on the left side of the equal sign, we have to divide by on the right side of the equal sign. So,

$\frac{2x}{2} = \frac{10}{2}$

Now, we simplify.

x = 5

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Example Question #364 : How To Find The Solution To An Equation

A + B = 100

A = -40

Evaluate .

Possible Answers:

B = -140

B = 60

B = 140

B = -60

Correct answer:

B = 140

Explanation:

A + B = 100

To evaluate, substitute -40 in for A.

-40 + B = 100

Add 40 to each side to isolate and solve for B.

-40 + B + 40 = 100 + 40

B = 140

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Example Question #365 : How To Find The Solution To An Equation

Solve the equation:

5x+ 7 = 89

Possible Answers:

x = 14.4

x = 18.4

x = 12.4

x = 16.4

Correct answer:

x = 16.4

Explanation:

To solve the equation, isolate the variable on one side of the equation and all other constants on the other side. To accomplish this, perform the opposite operation to manipulate the equation.

5x+ 7 = 89

First add seven to both sides.

5x+ 7 - 7 = 89 - 7

5x = 82

Now divide by five on both sides.

$5x \div 5 = 82 \div 5$

x = 16.4

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Example Question #366 : How To Find The Solution To An Equation

Solve the following equation for y when z=3

12y+6=2z^3-26

Possible Answers:

$1.8\bar{3}$

$18.\bar{3}$

188

Correct answer:

$1.8\bar{3}$

Explanation:

Solve the following equation for y when z=3

12y+6=2z^3-26

Let's begin by rearranging the equation to get y by itself.

12y+6(-6)=2z^3-26(-6)

$12y(\div12)=(2z^3-32)(\div12)$

$y=\frac{2z^3-32}{12}$

Next, just plug in 3 for z and solve.

$y=\frac{2(3)^3-32}{12}=\frac{54-32}{12}=\frac{22}{12}=1.8\bar{3}$

So our answer is

$1.8\bar{3}$

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Example Question #367 : How To Find The Solution To An Equation

Solve for :

-0.04 z + (-7) = - 121

Possible Answers:

z = 3,200

z=- 2,850

z= 2,850

z = - 3,200

Correct answer:

z= 2,850

Explanation:

-0.04 z + (-7) = - 121

-0.04 z + (-7) - (-7) = - 121 - (-7)

-0.04 z = - 121+ 7

-0.04 z = - (121- 7)

-0.04 z = -114

$-0.04 z \div (-0.04 ) = -114 \div (-0.04 )$

$z = 114 \div 0.04$

To divide, move the decimal point in both numbers two units to the right;

$z = 11400 \div 4$

z= 2,850

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Example Question #368 : How To Find The Solution To An Equation

Solve the following equation for h, when l is equal to 5

$3h+12=\frac{l^3-25}{5}$

Possible Answers:

$h=\frac{5}{3}$

$h=\frac{4}{3}$

h=3

$h=\frac{8}{3}$

Correct answer:

$h=\frac{8}{3}$

Explanation:

Solve the following equation for h, when l is equal to 5

$3h+12=\frac{l^3-25}{5}$

Let's begin by substituting in 5 for l

$3h+12=\frac{5^3-25}{5}$

Simplify

$3h+12=\frac{125-25}{5}=\frac{100}{5}=20$

3h+12=20

Next, move the twelve over:

3h=20-12=8

3h=8

Finally, we get:

$h=\frac{8}{3}$

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Example Question #2691 : Isee Middle Level (Grades 7 8) Mathematics Achievement

Solve for the equation when x=4 ,

$y=\frac{1}{2}x+13$ .

Possible Answers:

Correct answer:

Explanation:

The first step is to plug in your value so your equation looks like,

$y=\frac{1}{2}(4)+13$ .

Then you multiply $4*\frac{1}{2}$ to get .

Then you add to get your final answer .

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Example Question #571 : Algebraic Concepts

Solve for x in the following:

x-8=1

Possible Answers:

x=1

x=8

x=18

x=10

x=9

Correct answer:

x=9

Explanation:

To solve for x, we want x to stand alone or be by itself. So,

x-8=1

we want to get x to be by itself. To do that, we need to move the $- \ 8$ . To move it, we need to cancel it out. To cancel it out, we must $+ \ 8$ (add 8). If we add 8 on the left side of the equal sign, we must add 8 on the right side of the equal sign. So,

x-8+8=1+8

x+0 = 9

x=9

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ISEE Middle Level Math : Equations

Study concepts, example questions & explanations for ISEE Middle Level Math

All ISEE Middle Level Math Resources

Example Questions

Example Question #361 : Equations

Example Question #362 : How To Find The Solution To An Equation

Example Question #363 : How To Find The Solution To An Equation

Example Question #364 : How To Find The Solution To An Equation

Example Question #365 : How To Find The Solution To An Equation

Example Question #366 : How To Find The Solution To An Equation

Example Question #367 : How To Find The Solution To An Equation

Example Question #368 : How To Find The Solution To An Equation

Example Question #2691 : Isee Middle Level (Grades 7 8) Mathematics Achievement

Example Question #571 : Algebraic Concepts

All ISEE Middle Level Math Resources

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