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ISEE Lower Level Math : Rectangles

Study concepts, example questions & explanations for ISEE Lower Level Math

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Example Questions

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Example Question #51 : Quadrilaterals

A computer screen has a height of 9 inches and a width of 16 inches. Find its area.

Possible Answers:

50in^2

25in^2

288in^2

144in^2

Correct answer:

144in^2

Explanation:

A computer screen has a height of 9 inches and a width of 16 inches. Find its area.

Area can be found by multiplying the length by the width.

A=9*16=144

So our answer is 144

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Example Question #55 : Plane Geometry

A rectangle measures inches on its short side, and y + 1 inches on its long side. What is its area?

Possible Answers:

2xy

xy + 1

xy + x

2xy + 2

y + x

Correct answer:

xy + x

Explanation:

To find the area of a rectangle, multiply the length of the long side by the length of the short side. The best way to find the answer is:

x * (y + 1) = xy + x

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Example Question #54 : Quadrilaterals

A rectangle measures inches on its short side, and u - 1 inches on its long side. What is its area?

Possible Answers:

14u - 1

14u - 14

7u - 7

7u - 1

7u^2 - 7

Correct answer:

7u - 7

Explanation:

To find the area of a rectangle, multiply the length of the long side by the length of the short side. The best way to find the answer is:

7(u-1) = 7u - 7

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Example Question #57 : Plane Geometry

A swimming pool is in the shape of a rectangle that is 20 feet wide and 30 feet long. Find the area of the swimming pool.

Possible Answers:

$600\text{ft}^2$

$50\text{ft}$

$50\text{ft}^2$

$600\text{ft}$

$100\text{ft}$

Correct answer:

$600\text{ft}^2$

Explanation:

To find the area of a rectangle, we use the following formula:

$\text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

In this case, we know the length of the swimming pool is 30 feet. We also know the width of the pool is 20 feet. So, we can substitute into the formula. We get

$\text{area of rectangle} = 30\text{ft} \cdot 20\text{ft}$

$\text{area of rectangle} = 600\text{ft}^2$

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Example Question #58 : Plane Geometry

Use the following to answer the question.

Rectangle2

You go to the community center to go swimming. You see that the pool is a rectangular shape. If the pool has a length of 45 feet and a width of 20 feet, what is the area of the pool?

Possible Answers:

$130\text{ feet}$

$900 \text{ feet}$

$130\text{ feet}^2$

$900\text{ feet}^2$

$\text{There is not enough information to answer the question.}$

Correct answer:

$900\text{ feet}^2$

Explanation:

To find the area of a rectangle, we use the following formula:

$\text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

So, given the rectangle

Rectangle2

we can see the length is 45 feet and the width is 20 feet. Knowing this, we can substitute into the formula. We get

$\text{area of rectangle} = 45\text{ feet} \cdot 20\text{ feet}$

$\text{area of rectangle} = 900 \text{ feet}^2$

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Example Question #59 : Plane Geometry

Find the area of a rectangle with a length of 10cm and a width that is half the length.

Possible Answers:

$\text{There is not enough information to solve the problem.}$

$50\text{cm}$

$30\text{cm}^2$

$50\text{cm}^2$

$30\text{cm}$

Correct answer:

$50\text{cm}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the length of the rectangle is 10cm. We also know the width is half of the length. Therefore, the width is 5cm. Knowing this, we can substitute into the formula. We get

$\text{area of rectangle} = 10\text{cm} \cdot 5\text{cm}$

$\text{area of rectangle} = 50\text{cm}^2$

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Example Question #41 : Rectangles

Find the area of a rectangle with a width of 6 feet and a length that is two times the width.

Possible Answers:

$72\text{ft}^2$

$36\text{ft}$

$72\text{ft}$

$36\text{ft}^2$

$144\text{ft}$

Correct answer:

$72\text{ft}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the width is 6 feet. We know the length is two times the width. Therefore, the length is 12 feet. Knowing this, we can substitute into the formula. We get

$\text{area of rectangle} = 12\text{ft} \cdot 6\text{ft}$

$\text{area of rectangle} = 72\text{ft}^2$

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Example Question #61 : Plane Geometry

Find the area of a rectangle with a width of 4 inches and a length that is twice the width.

Possible Answers:

$24\text{in}$

$32\text{in}$

$24\text{in}^2$

$32\text{in}^2$

$\text{There is not enough information to solve the problem.}$

Correct answer:

$32\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the width of the rectangle is 4 inches. We also know the length is two times the width. Therefore, the length of the rectangle is 8 inches. Knowing this, we can substitute into the formula. We get

$\text{area of rectangle} = 8\text{in} \cdot 4\text{in}$

$\text{area of rectangle} = 32\text{in}^2$

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Example Question #62 : Plane Geometry

Find the area of a rectangle with a length of 10 inches and a width that is half the length.

Possible Answers:

$50\text{in}^2$

$15\text{in}^2$

$30\text{in}$

$30\text{in}^2$

$50\text{in}$

Correct answer:

$50\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the length of the rectangle is 10 inches. We also know the width is half the length. Therefore, the width is 5 inches. Knowing this, we can substitute into the formula. We get

$\text{area of rectangle} = 10\text{in} \cdot 5\text{in}$

$\text{area of rectangle} = 50\text{in}^2$

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Example Question #61 : Plane Geometry

Find the area of a rectangle with a length of 8in and a width of 7in.

Possible Answers:

$30\text{in}$

$56\text{in}^2$

$30\text{in}^2$

$56\text{in}$

$\text{There is not enough information to solve the problem.}$

Correct answer:

$56\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the length is 8in and the width is 7in. Knowing this, we can substitute into the formula. We get

$\text{area of rectangle} = 8\text{in} \cdot 7\text{in}$

$\text{area of rectangle} = 56\text{in}^2$

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ISEE Lower Level Math : Rectangles

Study concepts, example questions & explanations for ISEE Lower Level Math

All ISEE Lower Level Math Resources

Example Questions

Example Question #51 : Quadrilaterals

Example Question #55 : Plane Geometry

Example Question #54 : Quadrilaterals

Example Question #57 : Plane Geometry

Example Question #58 : Plane Geometry

Example Question #59 : Plane Geometry

Example Question #41 : Rectangles

Example Question #61 : Plane Geometry

Example Question #62 : Plane Geometry

Example Question #61 : Plane Geometry

All ISEE Lower Level Math Resources

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