All ISEE Lower Level Math Resources
Example Questions
Example Question #81 : Distributive Property
Multiply:
To multiply these terms use the Distributive property by applying the FOIL method. The FOIL method requires that we multiply each term and then combine like terms:
Note: FOIL stands for First, Outside, Inside, Last, where
First
Outside
Inside
Last
Final solution equals:
Example Question #82 : Isee Lower Level (Grades 5 6) Mathematics Achievement
Evaluate:
To evaluate these terms apply the Distributive property:
Thus, the solution is:
Remember: we can not combine or add unlike variables or terms. For example,
Example Question #81 : How To Find The Distributive Property
Expand the expression.
Use FOIL (first, outer, inner, last) to expand.
First:
Outside:
Inside:
Last:
Sum the four terms into one expression.
Simplify by combining like terms.
Example Question #83 : Distributive Property
Jack purchased tomato seeds and wants to make bags to sell at the local farmers’ market. How many different ways can Jack make seed bags with an equal number of seeds in each bag?
We will solve this problem by finding factor pairs. Factor pairs are composed of two numbers that are multiplied together to equal a product. List all the factor pairs of Jack’s seeds.
Do not forget to list their reciprocals.
Jack can make different seed bag combinations with an equal number of seeds in each bag.
Example Question #1671 : Grade 6
Jack purchased tomato seeds and wants to make bags to sell at the local farmers’ market. If he wants to have at least two bags to sell, many different ways can Jack make seed bags with an equal number of seeds in each bag?
We will solve this problem by finding factor pairs. Factor pairs are composed of two numbers that are multiplied together to equal a product. List all the factor pairs of Jack’s seeds.
-- but note that one bag of 18 seeds does not satisfy the condition that he wants to have at least two bags to sell, so this factorization does not count toward the answer.
-- two bags of nine seeds each
-- three bags of six seeds each
Do not forget to list their reciprocals.
-- six bags of three seeds each
-- nine bags of two seeds each
-- eighteen bags of one seed each
Jack can make different seed bag combinations with an equal number of seeds in each bag.
Example Question #1 : How To Find The Whole From The Part
Find the whole from the part. Round to the nearest tenths place.
16 is 55% of what number?
To find the whole from a part, divide the "part" by the percent. But first, change the percent into a decimal (55% = 0.55)
Round to the nearest tenths place = 29.1.
Example Question #1 : How To Find The Whole From The Part
Roman is ordering uniforms for the tennis team. He knows how many people are on the team and how many uniforms come in each box. Which equation can be used to solve for how many boxes Roman should order?
b = number of students ÷ number of uniforms per box
b = number of students - number of uniforms per box
b = number of students x number of uniforms per box
b = number of boxes ÷ number of uniforms per box
b = number of boxes x number of uniforms per box
b = number of students ÷ number of uniforms per box
The total number of uniforms needed equals the number of students divided by the number of uniforms per box.
Example Question #1 : How To Find The Whole From The Part
52 is 25% of what number?
208
13
1,300
240
208
To find the whole from the part, divide the “part” by the percent. In order to do this, first change the percent into a decimal (25% becomes 0.25).
Therefore, 52 is 25% of 208.
Example Question #2 : How To Find The Whole From The Part
At a party, of the cake was eaten. If each of the 12 attendees had one piece of cake, how many pieces were in the whole cake?
15
4
36
48
36
12 pieces of cake is equivalent to of the whole. Proportions can be used to determine how many pieces were in the entire cake. Let equal the number of pieces in the entire cake.
Using this set up, both fractions are equal to . Cross multiply.
Example Question #81 : Isee Lower Level (Grades 5 6) Mathematics Achievement
is of . Solve for .
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