In order to determine how much fence Dennis will need, we must find the perimeter of his property, which can be found using the formula $\displaystyle \small \small 2W+ 2L$. When we plug $\displaystyle \small 2\ mi$ in the $\displaystyle \small W$ and $\displaystyle \small 3\ mi$ in for $\displaystyle \small L$, we find that Dennis needs $\displaystyle \small 10\ mi$ of fence to surround his property.

$\displaystyle \small 2(2\ mi) + 2(3\ mi) = 10\ mi$

Add the length and the height, then multiply the sum by two:

$\displaystyle (11 + 18) \times 2 = 29 \times 2 = 58$

The rectangle has a perimeter of 58 inches.

Use the following formula, substituting $\displaystyle L = 30, W = 15$ :

$\displaystyle A = 2 (L + W)$

$\displaystyle A = 2 (30 + 15) = 2 \times 45 = 90 \textrm{ in}$

Now, divide this by 12 to convert inches to feet.

$\displaystyle \frac{90}{12} = 7 \textrm{ R }6$

6 inches make half of a foot, so this means the perimeter is $\displaystyle 7 \frac{1}{2}$ feet.

The perimeter of a shape is the sum of all its sides. To find the perimeter of a rectangle, one can use the formula listed above, $\displaystyle \small \left ( P= 2l+2w\right )$, since a rectangle has opposite sides of equal length.

The length of the rectangle is $\displaystyle \small 7$:

$\displaystyle \small 2\times7=14$

The width of the rectangle is $\displaystyle \small 4$:

$\displaystyle \small 4\times2=8$.

$\displaystyle \small 14+8=22$

Therefore, the perimeter is $\displaystyle \small 22$.  

$\displaystyle P=2(l+w)=2(5+3)=2(8)=16$

The perimeter of a rectangle is equal to the sum of all its sides. The formula for finding the perimeter of a rectangle is $\displaystyle P= 2(l+w)$. 

The length of the rectangle is eight, and the width is five; $\displaystyle 8+5=13$.

$\displaystyle 13\times2=26$

Therefore, the perimeter of the rectangle is $\displaystyle 26$.

The perimeter is calculated by adding up all the sides of the rectangle—in this case,

$\displaystyle 6+6+4+4=20$

So the perimeter is $\displaystyle 20$ feet.

A rectangle has two sides of congruent, or equal, sides. Therefore, there are two 10 cm sides and two 4 cm sides. Perimeters is the sum of all the sides, so you must add up the four sides. The answer is 28 cm.

The perimeter of a rectangle is found by adding together all four sides. Two sides will be equal to the length, and two sides will be equal to the width.

$\displaystyle P=width+width+length+length$

$\displaystyle P=2l+2w$

Since the width is 6.5 inches and the length is 9 inches, the perimeter would be:

$\displaystyle P=6.5+6.5+9+9$

$\displaystyle P=2(6.5)+2(9)$

$\displaystyle P=13+18$

$\displaystyle P=31$

We will need to find the area of the rectangle by multiplying the length by the width:

$\displaystyle A=l\times w$

Use the given dimensions:

$\displaystyle A=4\times2=8\ \text{ft}^2$