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Intermediate Geometry : Triangles

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Example Questions

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Example Question #23 : How To Find An Angle In An Acute / Obtuse Triangle

True or false: It is possible for a triangle to have three interior angles, each of whose measures are $50^{\circ }$ .

Possible Answers:

True

False

Correct answer:

False

Explanation:

A triangle with three congruent angles is an equiangular - and equilateral - triangle; such an angle must have three angles that measure $60^{\circ }$ .

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Example Question #24 : How To Find An Angle In An Acute / Obtuse Triangle

Given: $\bigtriangleup ABC$ with perimeter 40;

AB = 12 , BC = 14

True or false: $\angle A \cong \angle B$

Possible Answers:

False

True

Correct answer:

True

Explanation:

The perimeter of $\bigtriangleup ABC$ is the sum of the lengths of its sides - that is,

AB + BC + AC = P

The perimeter is 40, so set AB = 12 , BC = 14, P = 40 , and solve for :

AB + BC + AC = P

12+14 + AC = 40

26 + AC = 40

Subtract 26 from both sides:

26 + AC - 26 = 40 - 26

AC= 14

$\overline{BC}\cong \overline{AC}$ , so by the Isosceles Triangle Theorem, their opposite angles are congruent - that is,

$\angle A \cong \angle B$ .

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Example Question #25 : How To Find An Angle In An Acute / Obtuse Triangle

$\bigtriangleup ABC$ is an equilateral triangle; is the midpoint of $\overline{BC}$ ; the segment $\overline{AM }$ is constructed.

True or false: $m \angle BAM = 40^{\circ }$ .

Possible Answers:

False

True

Correct answer:

False

Explanation:

The referenced triangle is below:

Equilateral 2

In an equilateral triangle, the median from - the segment from to , the midpoint of the opposite side $\overline{BC}$ - is also the bisector of the angle $\angle BAC$ , so

$m \angle BAM = \frac{1}{2} \cdot \angle BAC$

Each interior angle of an equilateral triangle, including $\angle BAC$ , measures $60^{\circ }$ , so substitute and evaluate:

$m \angle BAM = \frac{1}{2} \cdot 60^{\circ } = 30 ^{\circ }$ .

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Example Question #26 : How To Find An Angle In An Acute / Obtuse Triangle

$\bigtriangleup ABC$ is an equilateral triangle. Locate a point along $\overline{BC}$ and construct $\overline{AD}$ . $m \angle ADB = 80^{\circ }$ .

Evaluate $m \angle DAC$ .

Possible Answers:

$20^{\circ }$

$30^{\circ }$

$\textup{Insufficient information is given to answer the problem}$

$25^{\circ }$

$15^{\circ }$

Correct answer:

$20^{\circ }$

Explanation:

The referenced figure is below. Note that $m \angle C = 60 ^{\circ }$ , as is the case with all of the interior angles of an equilateral triangle.

Equilateral

The interior angles of an equilateral triangle each measure $60^{\circ }$ . An exterior angle of a triangle has as its degree measure the sum of its remote interior angles; specifically,

$m \angle ADB = m\angle C + m \angle DAC$

Substitute the known angle measures, and solve:

$80^{\circ }= 60^{\circ } + m \angle DAC$

$80^{\circ }- 60^{\circ } = 60^{\circ } + m \angle DAC - 60^{\circ }$

$20^{\circ } = m \angle DA C$

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Example Question #1 : How To Find The Length Of The Hypotenuse Of An Acute / Obtuse Triangle

An acute scalene triangle has one side length of inches and another of inches. Find the length of the hypotenuse.

Possible Answers:

10in

$4\sqrt{29}in$

116in

$2\sqrt{29} in$

Correct answer:

$2\sqrt{29} in$

Explanation:

To find the length of the hypotenuse, apply the Pythagorean Theorem: a^2+b^2=c^2 , where the length of the hypotenuse.

Thus, the solution is:

4^2+10^2=c^2

16+100=c^2

c^2=116

$c=\sqrt{116}=\sqrt{4\times 29}=\sqrt{4} \sqrt{29}=2\sqrt{29}$

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Example Question #2 : How To Find The Length Of The Hypotenuse Of An Acute / Obtuse Triangle

Obtuse_isos_tri

Find the hypotenuse of the obtuse isosceles triangle shown above.

Possible Answers:

180ft

$\sqrt{180.5} ft$

$\sqrt{90.5}ft$

$\sqrt{180}ft$

Correct answer:

$\sqrt{180.5} ft$

Explanation:

To find the length of the hypotenuse, apply the Pythagorean Theorem: a^2+b^2=c^2 , where the length of the hypotenuse.

Thus, the solution is:

9.5^2+9.5^2=c^2

c^2=90.25+90.25=180.5

$c=\sqrt{180.5}$

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Example Question #3 : How To Find The Length Of The Hypotenuse Of An Acute / Obtuse Triangle

A scalene triangle has one side length of yards and another side length of yards. Find the hypotenuse.

Possible Answers:

$\sqrt{144}yds$

$16\sqrt{13}yds$

$4\sqrt{13}yds$

208yds

Correct answer:

$4\sqrt{13}yds$

Explanation:

To find the length of the hypotenuse, apply the Pythagorean Theorem: a^2+b^2=c^2 , where the length of the hypotenuse.

Thus, the solution is:

12^2+8^2=c^2

c^2=144+64=208

$c=\sqrt{208}=\sqrt{16\times 13}=\sqrt{16}\sqrt{13}=4\sqrt{13}$

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Example Question #4 : How To Find The Length Of The Hypotenuse Of An Acute / Obtuse Triangle

Isos_obtus_tri_dos

Find the hypotenuse of the obtuse isosceles triangle shown above.

Possible Answers:

$11\sqrt{2}m$

$\sqrt{11}m$

$\sqrt{11}\sqrt{2}m$

$\sqrt{121}m$

Correct answer:

$11\sqrt{2}m$

Explanation:

To find the length of the hypotenuse, apply the Pythagorean Theorem: a^2+b^2=c^2 , where the length of the hypotenuse.

Thus, the solution is:

11^2+11^2=c^2

c^2=121+121=242

$c=\sqrt{242}=\sqrt{121\times 2}=\sqrt{121}\sqrt{2}=11\sqrt{2}$

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Example Question #5 : How To Find The Length Of The Hypotenuse Of An Acute / Obtuse Triangle

An isosceles right triangle has two sides with a length of inches each. Find the length of the hypotenuse.

Possible Answers:

$20\sqrt{2}in$

25in

40in

$\sqrt{20}in$

Correct answer:

$20\sqrt{2}in$

Explanation:

To find the length of the hypotenuse, apply the Pythagorean Theorem: a^2+b^2=c^2 , where the length of the hypotenuse.

Thus, the solution is:

20^2+20^2=c^2

400+400=c^2

c^2=800

$c=\sqrt{800}=\sqrt{400\times 2}=\sqrt{400}\sqrt{2}=20\sqrt{2}$

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Example Question #6 : How To Find The Length Of The Hypotenuse Of An Acute / Obtuse Triangle

A scalene right triangle has one side length of inches and another side length of inches. Find the length of the hypotenuse.

Possible Answers:

49in

$\sqrt{74} in$

74in

$\sqrt{49}in$

Correct answer:

$\sqrt{74} in$

Explanation:

To find the length of the hypotenuse, apply the Pythagorean Theorem: a^2+b^2=c^2 , where the length of the hypotenuse.

Thus, the solution is:

5^2+7^2=c^2

c^2=25+49=74

$c=\sqrt{74}$

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Intermediate Geometry : Triangles

Study concepts, example questions & explanations for Intermediate Geometry

All Intermediate Geometry Resources

Example Questions

Example Question #23 : How To Find An Angle In An Acute / Obtuse Triangle

Example Question #24 : How To Find An Angle In An Acute / Obtuse Triangle

Example Question #25 : How To Find An Angle In An Acute / Obtuse Triangle

Example Question #26 : How To Find An Angle In An Acute / Obtuse Triangle

Example Question #1 : How To Find The Length Of The Hypotenuse Of An Acute / Obtuse Triangle

Example Question #2 : How To Find The Length Of The Hypotenuse Of An Acute / Obtuse Triangle

Example Question #3 : How To Find The Length Of The Hypotenuse Of An Acute / Obtuse Triangle

Example Question #4 : How To Find The Length Of The Hypotenuse Of An Acute / Obtuse Triangle

Example Question #5 : How To Find The Length Of The Hypotenuse Of An Acute / Obtuse Triangle

Example Question #6 : How To Find The Length Of The Hypotenuse Of An Acute / Obtuse Triangle

All Intermediate Geometry Resources

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