To find the missing side of this kite, work backwards using the formula:

$\displaystyle p=2(a+b)$, where $\displaystyle a$ and $\displaystyle b$ represent the length of one side from each of the two pairs of adjacent sides. 

The solution is:

$\displaystyle 58=2(11+b)$

$\displaystyle \frac{58}{2}=11+b$

$\displaystyle 29=11+b$

$\displaystyle b=29-11=18$

To find the missing side of this kite, work backwards using the formula:

$\displaystyle p=2(a+b)$, where $\displaystyle a$ and $\displaystyle b$ represent the length of one side from each of the two pairs of adjacent sides. 

The solution is:

$\displaystyle 2.5 feet=2(0.5 foot+b)$

$\displaystyle \frac{2.5}{2}=(0.5+b)$

$\displaystyle 1.25=0.5+b$

$\displaystyle b=1.25-0.5=0.75=\frac{3}{4}$

To find the missing side of this kite, work backwards using the formula:

$\displaystyle p=2(a+b)$, where $\displaystyle a$ and $\displaystyle b$ represent the length of one side from each of the two pairs of adjacent sides. 

The solution is:

$\displaystyle 62=2(8+b)$

$\displaystyle \frac{62}{2}=(8+b)$

$\displaystyle 31=8+b$

$\displaystyle b=31-8=23$

To find the missing side of this kite, work backwards using the formula:

$\displaystyle p=2(a+b)$, where $\displaystyle a$ and $\displaystyle b$ represent the length of one side from each of the two pairs of adjacent sides. 

The solution is:

$\displaystyle 138=2(33+b)$

$\displaystyle \frac{138}{2}=33+b$

$\displaystyle 69=33+b$

$\displaystyle b=69-33=36$

To find the missing side of this kite, work backwards using the formula:

$\displaystyle p=2(a+b)$, where $\displaystyle a$ and $\displaystyle b$ represent the length of one side from each of the two pairs of adjacent sides. 

The solution is:

$\displaystyle 30=2(9.5+a)$

$\displaystyle 30=19+2a$

$\displaystyle 2a=30-19=11$

$\displaystyle a=\frac{11}{2}=5.5$

The sides have the ratio $\displaystyle 4:1$, thus the longer sides must be $\displaystyle 4$ times greater than the smaller sides.

Since the longer sides are $\displaystyle 12$ cm, the shorter sides must be: 

$\displaystyle 12\div4=3$

To find the missing side of this kite, work backwards using the formula:

$\displaystyle p=2(a+b)$, where $\displaystyle a$ and $\displaystyle b$ represent the length of one side from each of the two pairs of adjacent sides. 

The solution is:

$\displaystyle 214=2(52+b)$

$\displaystyle \frac{214}{2}=(52+b)$

$\displaystyle 107=52+b$

$\displaystyle b=107-52=55$

To find the missing side of this kite, work backwards using the formula:

To solve this problem use the formula $\displaystyle p=2(a+b)$, where $\displaystyle a$ and $\displaystyle b$ represent the length of one side from each of the two pairs of adjacent sides. 

The solution is:

$\displaystyle 3\frac{1}{2}=2(1+b)$

$\displaystyle 3\frac{1}{2}\div2=1+b$

Make the first fraction into an improper fraction. Then find the reciprocal of the denominator and switch the operation sign:

$\displaystyle 3\frac{1}{2}\times\frac{1}{2}$

$\displaystyle \frac{7}{2}\times \frac{1}{2}=1+b$

$\displaystyle \frac{7}{4}=1+b$

$\displaystyle b=\frac{7}{4}-\frac{4}{4}=\frac{3}{4}$

Below is regular Pentagon $\displaystyle PENTA$ with center $\displaystyle C$, a segment drawn from $\displaystyle C$ to each vertex - that is, each of its radii drawn.

A kite is a quadrilateral with two sets of congruent adjacent sides, with the common length of one pair differing from that of the other. A regular polygon has congruent sides, so $\displaystyle \overline{EN} \cong \overline{EP}$; also, all radii of a regular polygon are congruent, so $\displaystyle \overline{CP} \cong \overline{CN}$. It follows by definition that Quadrilateral $\displaystyle CPEN$ is a kite.