Call Now to Set Up Tutoring:

(888) 888-0446

Intermediate Geometry : Intermediate Geometry

Study concepts, example questions & explanations for Intermediate Geometry

Create An Account

All Intermediate Geometry Resources

8 Diagnostic Tests 250 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #12 : How To Find The Equation Of A Circle

Write the equation for a circle with center (1,-3) and passing through the point (0,4)

Possible Answers:

(x+1)^2 + (y-3)^2 = 2

(x-1)^2 + (y+3)^2 = 48

(x+1)^2 + (y-3)^2 = 48

(x-1)^2 + (y-3)^2 = 2

(x-1)^2 + (y+3)^2 = 50

Correct answer:

(x-1)^2 + (y+3)^2 = 50

Explanation:

To determine the radius of the circle, use the distance formula:

$r = \sqrt{(1-0)^2 + (-3-4)^2} = \sqrt{1+49} = \sqrt{50}$

The equation for the circle is $(x-1)^2 + (y--3)^2 = \sqrt{50}^2$ or more simply (x-1)^2 + (y+3)^2 = 50

Report an Error

Example Question #11 : Circles

What is the equation of a circle that has its center at (-10, 2) and a radius of ?

Possible Answers:

(x+10)^2+(y-2)=144

(x+10)^2+(y+2)=144

(x+10)^2+(y-2)=24

(x-10)^2+(y-2)=36

Correct answer:

(x+10)^2+(y-2)=144

Explanation:

Recall the standard form for the equation of a circle:

(x-a)^2+(y-b)^2=r^2

In this equation, (a, b) represents the center of the circle and is the radius of the circle.

Since the center and radius of the circle are given to us, just substitute in the information itno the standard form of the equation of the circle.

The equation of the given circle is:

(x+10)^2+(y-2)=144

Report an Error

Example Question #322 : Coordinate Geometry

What is the equation of a circle that has its center at (-2, 14) and a radius of ?

Possible Answers:

(x-14)^2+(y-2)^2=4

(x+2)^2+(y-14)^2=16

(x-2)^2-(y+14)^2=4

(x-2)^2+(y+14)^2=16

Correct answer:

(x+2)^2+(y-14)^2=16

Explanation:

Recall the standard form for the equation of a circle:

(x-a)^2+(y-b)^2=r^2

In this equation, (a, b) represents the center of the circle and is the radius of the circle.

Since the center and radius of the circle are given to us, just substitute in the information itno the standard form of the equation of the circle.

The equation of the given circle is:

(x+2)^2+(y-14)^2=16

Report an Error

Example Question #323 : Coordinate Geometry

What is the equation of a circle that has its center at (12, 15) and a radius of ?

Possible Answers:

(x-12)^2-(y+15)^2=16

(x-12)^2+(y-15)^2=8

(x-12)^2+(y-15)^2=16

(x+12)^2+(y+15)^2=16

Correct answer:

(x-12)^2+(y-15)^2=16

Explanation:

Recall the standard form for the equation of a circle:

(x-a)^2+(y-b)^2=r^2

In this equation, (a, b) represents the center of the circle and is the radius of the circle.

Since the center and radius of the circle are given to us, just substitute in the information itno the standard form of the equation of the circle.

The equation of the given circle is:

(x-12)^2+(y-15)^2=16

Report an Error

Example Question #11 : How To Find The Equation Of A Circle

What is the equation of a circle that has its center at $(5, \frac{1}{4})$ and a radius length of $\frac{1}{5}$ ?

Possible Answers:

$(x-\frac{1}{4})^2+(y+5)^2=\frac{1}{25}$

$(x-5)^2+(y-\frac{1}{4})^2=\frac{1}{25}$

$(x-5)^2-(y+\frac{1}{4})^2=\frac{1}{5}$

$(x-5)^2+(y-\frac{1}{4})^2=\frac{1}{10}$

Correct answer:

$(x-5)^2+(y-\frac{1}{4})^2=\frac{1}{25}$

Explanation:

Recall the standard form for the equation of a circle:

(x-a)^2+(y-b)^2=r^2

In this equation, (a, b) represents the center of the circle and is the radius of the circle.

Since the center and radius of the circle are given to us, just substitute in the information itno the standard form of the equation of the circle.

The equation of the given circle is:

$(x-5)^2+(y-\frac{1}{4})^2=\frac{1}{25}$

Report an Error

Example Question #14 : How To Find The Equation Of A Circle

What is the equation of a circle that has its center at (15, 2) and a radius of $\frac{3}{5}$ ?

Possible Answers:

$(x-15)^2+(y-2)^2=\frac{9}{25}$

$(x+15)^2+(y+2)^2=\frac{9}{25}$

$(x-15)^2+(y+2)^2=\frac{6}{5}$

$(x-15)^2+(y-2)^2=\frac{3}{5}$

Correct answer:

$(x-15)^2+(y-2)^2=\frac{9}{25}$

Explanation:

Recall the standard form for the equation of a circle:

(x-a)^2+(y-b)^2=r^2

In this equation, (a, b) represents the center of the circle and is the radius of the circle.

Since the center and radius of the circle are given to us, just substitute in the information itno the standard form of the equation of the circle.

The equation of the given circle is:

$(x-15)^2+(y-2)^2=\frac{9}{25}$

Report an Error

Example Question #332 : Coordinate Geometry

What is the equation of a circle that has its center of (124, -201) and a radius of ?

Possible Answers:

(x-124)^2+(y+201)^2=15

(x-124)^2+(y+201)^2=225

(x-201)^2+(y+124)^2=225

$(x-124)^2+(y-201)^2=\sqrt{15}$

Correct answer:

(x-124)^2+(y+201)^2=225

Explanation:

Recall the standard form for the equation of a circle:

(x-a)^2+(y-b)^2=r^2

In this equation, (a, b) represents the center of the circle and is the radius of the circle.

Since the center and radius of the circle are given to us, just substitute in the information itno the standard form of the equation of the circle.

The equation of the given circle is:

(x-124)^2+(y+201)^2=225

Report an Error

Example Question #333 : Coordinate Geometry

What is the equation of a circle that has its center of (19, 28) and a radius of ?

Possible Answers:

$(x-19)^2+(y-28)^2=\sqrt{13}$

(x-19)^2+(y-28)^2=26

(x-19)^2+(y-28)^2=169

$(x-19)^2+(y-28)^2=\frac{13}{2}$

Correct answer:

(x-19)^2+(y-28)^2=169

Explanation:

Recall the standard form for the equation of a circle:

(x-a)^2+(y-b)^2=r^2

In this equation, (a, b) represents the center of the circle and is the radius of the circle.

Since the center and radius of the circle are given to us, just substitute in the information itno the standard form of the equation of the circle.

The equation of the given circle is:

(x-19)^2+(y-28)^2=169

Report an Error

Example Question #334 : Coordinate Geometry

What is the equation of a circle that has its center at (-22, -120) and a radius of ?

Possible Answers:

(x+22)^2+(y+120)^2=400

$(x+22)^2+(y+120)^2=2\sqrt5$

(x+120)^2+(y+22)^2=40

(x-22)^2-(y+120)^2=100

Correct answer:

(x+22)^2+(y+120)^2=400

Explanation:

Recall the standard form for the equation of a circle:

(x-a)^2+(y-b)^2=r^2

In this equation, (a, b) represents the center of the circle and is the radius of the circle.

Since the center and radius of the circle are given to us, just substitute in the information itno the standard form of the equation of the circle.

The equation of the given circle is:

(x-19)^2+(y-28)^2=169

Report an Error

Example Question #21 : How To Find The Equation Of A Circle

What is the equation of a circle that has its center at $(-\frac{1}{4}, 2)$ and a radius of ?

Possible Answers:

$(x+\frac{1}{4})^2+(y-2)^2=128$

$(x+\frac{1}{4})^2+(y-2)^2=4$

$(x+\frac{1}{4})^2+(y+2)^2=512$

$(x+\frac{1}{4})^2+(y-2)^2=256$

Correct answer:

$(x+\frac{1}{4})^2+(y-2)^2=256$

Explanation:

Recall the standard form for the equation of a circle:

(x-a)^2+(y-b)^2=r^2

In this equation, (a, b) represents the center of the circle and is the radius of the circle.

Since the center and radius of the circle are given to us, just substitute in the information itno the standard form of the equation of the circle.

The equation of the given circle is:

$(x+\frac{1}{4})^2+(y-2)^2=256$

Report an Error

View Tutors

Ahmed
Certified Tutor

George Mason University, Bachelor of Science, Information Technology.

View Tutors

Alejandro
Certified Tutor

Kennesaw State University, Bachelor of Science, Computer Software Engineering.

View Tutors

Richard
Certified Tutor

CUNY Brooklyn College, Bachelor of Science, Chemistry. CUNY Brooklyn College, Master of Arts, Experimental Psychology.

All Intermediate Geometry Resources

8 Diagnostic Tests 250 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

SAT Tutors in Atlanta, Biology Tutors in San Francisco-Bay Area, LSAT Tutors in Dallas Fort Worth, LSAT Tutors in Philadelphia, ISEE Tutors in Houston, MCAT Tutors in San Diego, SAT Tutors in Seattle, SSAT Tutors in Washington DC, Chemistry Tutors in Washington DC, SSAT Tutors in Seattle

Popular Courses & Classes

Spanish Courses & Classes in Philadelphia, GRE Courses & Classes in Washington DC, ISEE Courses & Classes in Houston, LSAT Courses & Classes in Washington DC, SAT Courses & Classes in Phoenix, ISEE Courses & Classes in San Francisco-Bay Area, SAT Courses & Classes in Washington DC, MCAT Courses & Classes in Miami, ISEE Courses & Classes in Phoenix, ACT Courses & Classes in Philadelphia

Popular Test Prep

SSAT Test Prep in Miami, SSAT Test Prep in San Diego, GMAT Test Prep in Los Angeles, MCAT Test Prep in Seattle, LSAT Test Prep in Atlanta, MCAT Test Prep in Philadelphia, GMAT Test Prep in Philadelphia, ACT Test Prep in San Francisco-Bay Area, ACT Test Prep in Phoenix, GRE Test Prep in Seattle

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Intermediate Geometry : Intermediate Geometry

Study concepts, example questions & explanations for Intermediate Geometry

All Intermediate Geometry Resources

Example Questions

Example Question #12 : How To Find The Equation Of A Circle

Example Question #11 : Circles

Example Question #322 : Coordinate Geometry

Example Question #323 : Coordinate Geometry

Example Question #11 : How To Find The Equation Of A Circle

Example Question #14 : How To Find The Equation Of A Circle

Example Question #332 : Coordinate Geometry

Example Question #333 : Coordinate Geometry

Example Question #334 : Coordinate Geometry

Example Question #21 : How To Find The Equation Of A Circle

All Intermediate Geometry Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: