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High School Physics : Waves, Sound, and Light

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Example Questions

Example Question #1 : Understanding Wavelength And Frequency

A drummer beats his drum every $\frac{1}{6}s$ . What is the frequency of the drum beat?

Possible Answers:

$\frac{5}{6}Hz$

$\frac{1}{36}Hz$

6Hz

$\frac{1}{6}Hz$

3Hz

Correct answer:

6Hz

Explanation:

Period describes the amount of time per event cycle. The relationship between period and frequency is $f=\frac{1}T$ .

We are given the period, allowing us to solve for the frequency.

$f=\frac{1}T$

$f=\frac{1}{\frac{1}{6}s}$

f=6Hz

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Example Question #1 : Understanding Wavelength And Frequency

A microwave has a wavelength of 0.01m . What is the frequency of the wave?

$c=3*10^8\frac{m}{s}$

Possible Answers:

$3*10^{-11}Hz$

$3*10^{10}Hz$

3*10^8Hz

$3*10^{-6}Hz$

3*10^6Hz

Correct answer:

$3*10^{10}Hz$

Explanation:

The velocity of a wave is equal to the product of the wavelength and frequency:

$v=\lambda f$

We can rearrange this formula to solve for the frequency.

$f=\frac{v}{\lambda}$

Since microwaves are on the electromagnetic spectrum, their velocity will be equal to the speed of light. We are given the wavelength. Using these values, we are able to solve for the frequency.

$f=\frac{3*10^8\frac{m}{s}}{0.01m}$

$f=3*10^{10}Hz$

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Example Question #8 : Understanding Wavelength And Frequency

A certain type of radiation on the electromagnetic spectrum has a frequency of $10^{20}Hz$ . What is the wavelength of this radiation?

$c=3*10^8\frac{m}{s}$

Possible Answers:

$3*10^{20}m$

$3*10^{-28}m$

$3*10^{-12}m$

$3*10^{18}m$

$3*10^{2.5}m$

Correct answer:

$3*10^{-12}m$

Explanation:

The velocity of a wave is equal to the product of the wavelength and frequency:

$v=\lambda f$

We can rearrange this formula to solve for the wavelength.

$\lambda=\frac{c}{f}$

We can use the given values for the frequency and velocity to solve for the wavelength.

$\lambda=\frac{3*10^8\frac{m}{s}}{10^{20}Hz}$

$\lambda=3*10^{-12}m$

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Example Question #11 : Understanding Wavelength And Frequency

A certain type of radiation on the electromagnetic spectrum has a period of $10^{-17}s$ . What is the wavelength of this radiation?

$c=3*10^8\frac{m}{s}$

Possible Answers:

$3*10^{-25}m$

$3*10^{-9}m$

$3*10^{-17}m$

$3*10^{-2.125}m$

$3*10^{8}m$

Correct answer:

$3*10^{-9}m$

Explanation:

The velocity of a wave is equal to the product of the wavelength and frequency:

$v=\lambda f$

We can rearrange this formula to solve for the wavelength.

$\lambda=\frac{c}{f}$

We also know that the period is the inverse of the frequency:

$T=\frac{1}{f}$

Substitute this into the equation for wavelength.

$\lambda=c*T$

Now we can use our given values for the period and the velocity to solve for the wavelength.

$\lambda=(3*10^8\frac{m}{s})*(10^{-17}s)$

$\lambda=3*10^{-9}m$

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Example Question #11 : Understanding Wavelength And Frequency

A certain type of radiation on the electromagnetic spectrum has a period of $10^{-9}s$ . What is the wavelength of this radiation?

$c=3*10^8\frac{m}{s}$

Possible Answers:

$3*10^{1.125}m$

0.3m

$3*10^{-17}m$

$3*10^{17}m$

Correct answer:

0.3m

Explanation:

The velocity of a wave is equal to the product of the wavelength and frequency:

$v=\lambda f$

We can rearrange this formula to solve for the wavelength.

$\lambda=\frac{c}{f}$

We also know that the period is the inverse of the frequency:

$T=\frac{1}{f}$

Substitute this into the equation for wavelength.

$\lambda=c*T$

Now we can use our given values for the period and the velocity to solve for the wavelength.

$\lambda=(3*10^8\frac{m}{s})*(10^{-9}s)$

$\lambda=0.3m$

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Example Question #12 : Understanding Wavelength And Frequency

A certain type of radiation on the electromagnetic spectrum has a period of $10^{-9}s$ . What is the frequency of this radiation?

Possible Answers:

$10^{17}Hz$

10^9Hz

$10^{18}Hz$

10^3Hz

$10^{-9}Hz$

Correct answer:

10^9Hz

Explanation:

The relationship between frequency and period is:

$f=\frac{1}{T}$

We are given the period in the question. Using this value, we can solve for the frequency.

$f=\frac{1}{10^{-9}s}$

$f=(10^{-9}s)^{-1}$

f=10^9Hz

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Example Question #13 : Understanding Wavelength And Frequency

Two notes are played simultaneously. One of them has a period of and the other has a period of . Which one has a longer wavelength?

Possible Answers:

We need to know the period in order to solve

They have the same wavelength

We need to know the frequency in order to solve

Correct answer:

Explanation:

The relationship between frequency and wavelength determines the velocity:

$v=\lambda f$

The frequency is the inverse of the period. We can substitute this into the equation above.

$v=\lambda \frac{1}{T}$

In the question, both of the notes are played at the same time in the same location, so they both should have the same velocity. We can set the equation for each tone equal to each other.

$\lambda_1\frac{1}{T_1}=\lambda_2\frac{1}{T_2}$

We are told that T_2=2T_1 . Substitute into our equation.

$\lambda_1\frac{1}{T_1}=\lambda_2\frac{1}{2T_1}$

We can cancel the period from each side of the equation, leaving the relationship between the two wavelengths.

$\lambda_1\frac{1}{T_1}=\lambda_2\frac{1}{2}\frac{1}{T_1}$

$\lambda_1=\frac{1}{2}\lambda_2$

The wavelength of the first wave is equal to half the wavelength of the second. This means that the wavelength for the tone with a longer period will have a longer wavelength as well.

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Example Question #14 : Understanding Wavelength And Frequency

What is the period of a wave with a frequency of 61Hz ?

Possible Answers:

61s

$\frac{1}{3721}s$

We need to know the wavelength in order to solve

3721s

$\frac{1}{61}s$

Correct answer:

$\frac{1}{61}s$

Explanation:

The relationship between frequency and period is:

$T=\frac{1}{f}$

Period is simply the reciprocal of frequency.

$T=\frac{1}{61Hz}$

$T=\frac{1}{61}s$

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Example Question #15 : Understanding Wavelength And Frequency

A cat meows with a frequency of 512Hz . What is the wavelength of this sound?

$v_{sound}=340.29\frac{m}{s}$

Possible Answers:

0.66m

852.29m

1.5m

171.71m

There is insufficient information to solve

Correct answer:

0.66m

Explanation:

The relationship between velocity, wavelength, and frequency is:

$v=f\lambda$

We know the speed of sound and the frequency of the sound, allowing us to solve for the wavelength.

$340.29\frac{m}{s}=(512Hz)\lambda$

$\lambda=\frac{340.29\frac{m}{s}}{512Hz}$

$\lambda=0.66m$

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Example Question #16 : Understanding Wavelength And Frequency

A saxophone plays a note with a wavelength of 0.88m . What is the frequency?

$v_s=340.29\frac{m}{s}$

Possible Answers:

0.003Hz

386.69Hz

216Hz

343.72Hz

2.91Hz

Correct answer:

386.69Hz

Explanation:

The relationship between wavelength, frequency, and velocity is:

$v=f\lambda$

We are given the speed of sound and the wavelength, allowing us to solve for the frequency.

$340.29\frac{m}{s}=f(0.88m)$

$f=\frac{340.29\frac{m}{s}}{0.88m}$

f=386.69Hz

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High School Physics : Waves, Sound, and Light

Study concepts, example questions & explanations for High School Physics

All High School Physics Resources

Example Questions

Example Question #1 : Understanding Wavelength And Frequency

Example Question #1 : Understanding Wavelength And Frequency

Example Question #8 : Understanding Wavelength And Frequency

Example Question #11 : Understanding Wavelength And Frequency

Example Question #11 : Understanding Wavelength And Frequency

Example Question #12 : Understanding Wavelength And Frequency

Example Question #13 : Understanding Wavelength And Frequency

Example Question #14 : Understanding Wavelength And Frequency

Example Question #15 : Understanding Wavelength And Frequency

Example Question #16 : Understanding Wavelength And Frequency

All High School Physics Resources

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