All High School Physics Resources
Example Questions
Example Question #3 : Elastic And Inelastic Collisions
Hockey puck A () travels with a velocity of to the right when it collides with hockey puck B (), which was originally at rest. After the collision, puck A is stationary. Assume no external forces are in play and that the momentum of the pucks are conserved. What is the final velocity of puck B after the collision?
Elastic collisions occur when two objects collide and kinetic energy isn't lost. The objects rebound from each other and kinetic energy and momentum are conserved. Inelastic collisions are said to occur when the two objects remain together after the collision so we are dealing with an elastic collision.
Above, the subscripts 1 and 2 denote puck A and B respectively, and the initial momentum of puck B is zero, so that term is not included in the equation above.
Plug in initial and final velocities and mass:
Example Question #1 : Elastic And Inelastic Collisions
A car with mass and initial velocity strikes a car of mass , which is at rest. If the two cars stick together after the collision, what is the final velocity?
We know that the cars stick together after the collision, which means that the final velocity will be the same for both of them. Using the formula for conservation of momentum, we can start to set up an equation to solve this problem.
First, we will write the initial momentum.
We know that the second car starts at rest, so this equation can be simplified.
Now we will write out the final momentum. Keep in mind that both cars will have the same velocity!
Set these equations equal to each other and solve to isolate the final velocity.
This is our answer, in terms of the given variables.
Example Question #5 : Elastic And Inelastic Collisions
A sports car collides into the rear end of SUV stopped at a red light. The bumper lock, the brakes lock and the two cars skid forward before coming to a stop. The police officer, knowing the coefficient of kinetic friction between the tires and the road is about . He calculates the speed of the sports car at impact. What was that speed?
Knowns
Unknowns
To solve the problem we must consider two different situations. The first is when the cars are skidding across the ground. While they are skidding the force of friction is what is resisting their motion and therefore doing work on the cars to slow them down to a stop.
The second situation is the collision itself when the first car has an initial speed and the second car is stopped. After the collision both cars are traveling with the same speed as their bumpers have been locked together.
To begin, we need to find the speed that the cars are skidding across the ground after the bumpers have been interlocked.
The work-kinetic energy theorem states that the work done is equal to the change in kinetic energy of the object.
Work is directly related to the force times the displacement of the object.
In this case, the force that is doing the work is friction.
Since the cars are on a level surface the normal force is equal to the force of gravity.
The force of gravity is directly related to the mass and the acceleration due to gravity acting on an object.
When we put all these equations together we get
We also know that kinetic energy is related to the mass and velocity squared.
Therefore our final equation should look like
Notice that the mass falls out of the equation since it is in every term. Also note that the final velocity is 0m/s so this will cancel out as well.
Since both of these terms have a negative we can cancel this out as well.
We can now substitute our variables to determine the velocity of both cars just after the crash.
This is the velocity of the cars after the collision. We must now consider our second situation of the collision itself. During this collision momentum must be conserved. The law of conservation of momentum states
We can substitute our values for the masses of the cars, the final velocity of the cars after the collision (which we just found) and the initial value of the stopped car.
Now we can solve for our missing variable.
Example Question #881 : High School Physics
A car traveling at collides with another car that is at rest. The two bumpers lock and the cars move forward together. What is their final velocity?
This is an example of an inelastic collision, as the two cars stick together after colliding. We can assume momentum is conserved.
To make the equation easier, let's call the first car "1" and the second car "2."
Using conservation of momentum and the equation for momentum, p=mv, we can set up the following equation.
Since the cars stick together, they will have the same final velocity. We know the second car starts at rest, and the velocity of the first car is given. Plug in these values and solve for the final velocity.
Example Question #6 : Elastic And Inelastic Collisions
Which of these would NOT be an example of an inelastic collision?
A man is clapping his hands such that they move with equal, but opposite velocities
A match scrapes a matchbook and bursts into flame
Two hydrogen atoms fuse together to form a helium atom and gamma radiation
Two cars crash into each other, and stop with a loud bang
Neutrons fuse with hydrogen atoms in a nuclear reactor core such that kinetic energy is conserved
Neutrons fuse with hydrogen atoms in a nuclear reactor core such that kinetic energy is conserved
The difference between an elastic and an inelastic collision is the loss or conservation of kinetic energy. In an inelastic collision kinetic energy is not conserved, and will change forms into sound, heat, radiation, or some other form. In an elastic collision kinetic energy is conserved and does not change forms.
Remember, total energy and total momentum are conserved regardless of the type of collision; however, while energy cannot be created nor destroyed, it can change forms.
In the answer options, only one choice preserves the total kinetic energy. The resulting bang from the car crash, the flame from the match, the sound of hands clapping, and the gamma radiation during hydrogen fusion are all examples of the conversion of kinetic energy to other forms, making each of these an inelastic collision. Only the neutron fusion described maintains the conservation of kinetic energy, making this an elastic collision.
Example Question #1 : Period Of Shm
A spring has a spring constant of . If a force of is used to stretch out the spring, what is the total displacement of the spring?
For this problem, use Hooke's law:
In this formula, is the spring constant, is the compression of the spring, and is the necessary force. We are given the spring constant and the force, allowing us to solve for the displacement.
Plug in our given values and solve.
Note that both the force and the displacement are positive because the stretching force will pull in the positive direction. If the spring were compressed, the change in distance would have been negative.
Example Question #2 : Period Of Shm
A spring is attached to a mass, oscillating freely in simple harmonic motion. What change can be made to increase the period of the oscillation?
Take the spring to a planet with a lower acceleration due to gravity
Lengthen the spring
Decrease the mass at the end of the spring
Increase the mass at the end of the spring
Use a spring with a greater spring constant
Increase the mass at the end of the spring
The equation for the period of a spring in simple harmonic motion is:
In this formula, m is the mass and k is the spring constant. The only two things we can adjust that can change the period, then, are the mass and spring constant. The length of the spring and the acceleration due to gravity are irrelevant.
If we increase the mass we get a larger numerator, which in turns will give us a larger period. If we decrease the mass we get a smaller numerator, which would give us a smaller period. If we use a higher spring constant we get a larger denominator, which also gives us a smaller period.
Example Question #31 : Harmonic Motion
A man swings a bucket back and forth at the end of a rope, creating a pendulum. What factor could be used to increase the period of the pendulum?
Move the pendulum to a lower altitude
Use a stronger rope
Remove water from the bucket
Add water to the bucket
Increase the length of the rope
Increase the length of the rope
The equation for the period of a pendulum is:
Notice that the material of the pendulum and the mass at the end do not enter into the equation at all. The only things that are capable of affecting the period are the length of the pendulum and the acceleration due to gravity.
While changing the altitude of the pendulum will change the period, it will do it only slightly unless you take it miles above the earth's crust. Furthermore, decreasing the altitude of the pendulum will increase the force due to gravity, which will result in a decreased period. The best answer is to increase the length of the rope. This will increase the period of the pendulum.
Example Question #32 : Harmonic Motion
Your grandfather clock’s pendulum has a length of . If the clock loses half a minute per day, how should you adjust the length of the pendulum?
We should length the pendulum by
We should shorten the pendulum by
We should lengthen the pendulum by
We should shorten the pendulum by
We should lengthen the pendulum by
We should lengthen the pendulum by
We also can calculate the total number of seconds in a day.
There are seconds in one day.
Therefore we want our clock to swing a certain number of times with a period of to equal .
We know that our current clock has a certain number of swings with a period of to equal
So we have
We can calculate the current period of the pendulum using the equation
We can set up a ratio of each of these two periods to determine the missing length.
Notice that 2, pi and g are all in both the numerator and denominator and therefore fall out of the problem.
We can now solve for our missing piece.
Square both sides to get rid of the square root.
We should lengthen the pendulum by
Example Question #391 : Motion And Mechanics
A mass is placed at the end of a spring. It has a starting velocity of and is allowed to oscillate freely. If the mass has a starting velocity of , what would the period be?
The period would remain the same.
The period would be 14 as long.
The period would be 4 times as long.
The period would be twice as long.
The period would be half as long.
The period would remain the same.
When it comes to the period of a spring, the velocity of the object has no effect.
The equation is