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High School Math : High School Math

Study concepts, example questions & explanations for High School Math

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8 Diagnostic Tests 613 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #63 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for when x+20=3x+42

Possible Answers:

x=14

x=-11

x=-64

x=16

Correct answer:

x=-11

Explanation:

When there are variables on both sides of the equation, it is easiest to move them to the same side. Move all variables to the left side of the equation by subtracting from each side:

x+20-3x=3x+42-3x

-2x+20=42

Then subtract from each side of the equation:

-2x+20-20=42-20

-2x=22

Then divide each side by :

$\frac{-2x}{-2}=\frac{22}{-2}$

x=-11

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Example Question #61 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for when 7x-17=32

Possible Answers:

x=7

x=343

x=79

x=14

Correct answer:

x=7

Explanation:

To solve for , begin by adding to both sides of the equation:

7x-17+17=32+17

7x=49

Then divide both sides of the equation by :

$\frac{7x}{7}=\frac{49}{7}$

x=7

Report an Error

Example Question #225 : Algebraic Equations

Solve for when x+18=7x-18

Possible Answers:

x=24

x=-7

x=18

x=6

Correct answer:

x=6

Explanation:

When there are variables on both sides of the equation, it is easiest to move them to the same side. Move all variables to the right side of the equation by subtracting from each side:

x-x+18=7x-x-18

18=6x-18

Then add to both sides of the equation:

18+18=6x-18+18

36=6x

Then divide each side of the equation by :

$\frac{36}{6}=\frac{6x}{6}$

x=6

Report an Error

Example Question #71 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for when $\frac{x}{4}+16=48$

Possible Answers:

x=8

x=128

x=16

x=64

Correct answer:

x=128

Explanation:

To solve for , begin by subtracting from both sides of the equation:

$\frac{x}{4}+16-16=48-16$

$\frac{x}{4}=32$

Then multiply both sides by :

$\frac{x}{4}\cdot 4=32\cdot 4$

x=128

Report an Error

Example Question #72 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for if, 4(x+8)=72

Possible Answers:

x=10

x=4

x=8

x=12

Correct answer:

x=10

Explanation:

To solve for , first distribute the outside the parentheses to both values inside the parentheses:

4x+32=72

Then subtract from both sides of the equation:

4x+32-32=72-32

4x=40

Then divide each side of the equation by :

$\frac{4x}{4}=\frac{40}{4}$

x=10

Report an Error

Example Question #73 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for when 8(x-7)=40

Possible Answers:

$x=\frac{47}{8}$

x=14

x=12

x=8

Correct answer:

x=12

Explanation:

To solve for , first distribute the outside the parentheses to both values inside the parentheses:

8x-56=40

Then add to both sides of the equation:

8x-56+56=40+56

8x=96

Then divide both sides by :

$\frac{8x}{8}=\frac{96}{8}$

x=12

Report an Error

Example Question #71 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for when 7x-82=2

Possible Answers:

x=48

x=24

x=16

x=12

Correct answer:

x=12

Explanation:

To solve for , first add to both sides of the equation:

7x-82+82=2+82

7x=84

Then divide each side of the equation by :

$\frac{7x}{7}=\frac{84}{7}$

x=12

Report an Error

Example Question #72 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for when $\frac{x}{9}+71=89$

Possible Answers:

x=144

x=162

x=81

x=9

Correct answer:

x=162

Explanation:

To solve for , first subtract from both sides of the equation:

$\frac{x}{9}+71-71=89-71$

$\frac{x}{9}=18$

Then multiply each side of the equation by :

$\frac{x}{9}\cdot 9=18\cdot 9$

x=162

Report an Error

Example Question #73 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for when -3(x+16)=12

Possible Answers:

x=-28

x=7

x=-20

x=20

Correct answer:

x=-20

Explanation:

To solve for , first distribute the outside the parentheses to both values inside the parentheses:

-3x-48=12

Then add to both sides of the equation:

-3x-48+48=12+48

-3x=60

Then divide both sides of the equation by :

$\frac{-3x}{-3}=\frac{60}{-3}$

x=-20

Report an Error

Example Question #74 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for when 8x+64=128

Possible Answers:

x=8

x=64

x=36

x=16

Correct answer:

x=8

Explanation:

To solve for , first subtract from both sides of the equation:

8x+64-64=128-64

8x=64

Then divide both sides of the equation by :

$\frac{8x}{8}=\frac{64}{8}$

x=8

Report an Error

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High School Math : High School Math

Study concepts, example questions & explanations for High School Math

All High School Math Resources

Example Questions

Example Question #63 : How To Solve Two Step Equations With Integers In Pre Algebra

Example Question #61 : How To Solve Two Step Equations With Integers In Pre Algebra

Example Question #225 : Algebraic Equations

Example Question #71 : How To Solve Two Step Equations With Integers In Pre Algebra

Example Question #72 : How To Solve Two Step Equations With Integers In Pre Algebra

Example Question #73 : How To Solve Two Step Equations With Integers In Pre Algebra

Example Question #71 : How To Solve Two Step Equations With Integers In Pre Algebra

Example Question #72 : How To Solve Two Step Equations With Integers In Pre Algebra

Example Question #73 : How To Solve Two Step Equations With Integers In Pre Algebra

Example Question #74 : How To Solve Two Step Equations With Integers In Pre Algebra

All High School Math Resources

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