All High School Math Resources
Example Questions
Example Question #24 : How To Solve Two Step Equations With Integers In Pre Algebra
Solve for if .
To perform a two step algebra problem with addition and multiplication, we must remove the constants from so that it is by itself on one side of the equation.
To do this we first look to see if a number is being added or subtracted from .
In this case a number is being added so we must subtract the number, , from each side of the equation:
Perform the math to make our equation look like .
Then, we divide each side of the equation by the constant attached to to get by itself:
The division yields .
Example Question #21 : How To Solve Two Step Equations With Integers In Pre Algebra
Solve for if .
To perform a two step algebra problem with addition and division, we must remove the constants from so that it is by itself on one side of the equation.
To do this we first look to see if a number is being added or subtracted from .
In this case a number is being subtracted, so we must add the number, , to each side of the equation:
Perform the math to see that that our equation looks like .
Then we multiply each side of the equation by the constant attached to to get by itself:
Perform the multiplication to find .
Example Question #30 : How To Solve Two Step Equations With Integers In Pre Algebra
Solve for if .
The problem above is a two-step algebra problem with distribution.
To solve you must first distribute the outside of the parentheses through the numbers inside by multiplying.
Remember, when you distribute a negative, both of the numbers inside the parentheses are being multiplied by a negative number, so they must both flip signs.
Our problem now looks like .
Then we must isolate our variable, .
We must subtract the number, , from each side of the equation:
Perform the math so that our equation looks like .
Then divide each side of the equation by the constant attached to to get by itself:
Solve the math to find the answer, .
Example Question #281 : Pre Algebra
Solve for if .
To solve for we must move all of the constants to the other side of the equation of .
When solving a simple two step equation we must remove the numbers that are interacting with in this order: Addition/Subtraction, Multiplication/Division, Polynomials.
To do this in a problem where is multiplied by a number, we must divide both sides of the equation by the number.
In this case the number is , so we divide each side of the equation by to make it look like this:
Our new problem will look like this:
We then must solve the polynomial.
To solve an equation with , we must take the square root of each side of the equation to isolate .
Doing this makes our problem look like .
Then we take the square root of both sides to get the answer, .
Always remember that can also equal , so our answer most include both the positive and negative number.
The final answer is .
Example Question #31 : How To Solve Two Step Equations With Integers In Pre Algebra
Solve for if .
To perform a two-step algebra problem with addition and multiplication, we must remove the numbers from so it is by itself on one side of the equation.
To do this we first look to see if a number is being added or subtracted from .
In this case a number is being added, so we must subtract this number, , from each side of the equation:
Perform the math so that our equation looks like .
Then we divide each side of the equation by the constant attached to to get by itself:
The answer is then .
Example Question #32 : How To Solve Two Step Equations With Integers In Pre Algebra
Solve for if .
The problem above is a two-step algebra problem with distribution.
To solve you must first distribute the outside of the parentheses through both of the numbers inside by multiplying to get .
Then we must get our variable, , by itself.
To do this add to each side of the equation:
Perform the math so that our equation looks like .
Then we divide each side of the equation by the constant attached to to get by itself:
Then the answer is .
Example Question #33 : How To Solve Two Step Equations With Integers In Pre Algebra
Solve for if .
To perform a two-step algebra problem with addition and division we must remove the numbers from so that it is by itself on one side of the equation.
To do this we first look to see if a number is being added or subtracted from .
In this case a number is being subtracted, so we must add the number, , to each side of the equation:
Perform the math so that our equation looks like .
Then we multiply each side of the equation by the constant under to get by itself:
Then the answer is .
Example Question #181 : Algebraic Equations
Solve for if .
When there are variables and numbers on each side of the equation, we must move the variables to one side of the equation and the numbers to the other.
To do this we put all of the variables on the right side of the equation by subtracting from each side of the equation:
When adding or subtracting variables, only add or subtract the numbers in front of the variables. If there is no number, the number value is .
Perform the math to get .
Then add to both sides of the equation:
Perform the math:
At this point we must divide each side of the equation by the constant attached to to isolate :
Then the answer is .
Example Question #31 : How To Solve Two Step Equations With Integers In Pre Algebra
Solve for if .
To perform a two-step algebra problem with addition and multiplication, we must isolate .
To do this we first look to see if a number is being added or subtracted from .
In this case a number is being added, so we must subtract the number, , from each side of the equation:
Perform the math so that our equation looks like .
Then we divide each side of the equation by the constant attached to :
Perform the math to find the answer, .
Example Question #32 : How To Solve Two Step Equations With Integers In Pre Algebra
Solve for if .
To perform a two-step algebra problem with addition and division we must isolate .
To do this we first look to see if a number is being added or subtracted from .
In this case a number is being subtracted, so we must add the number, , to each side of the equation:
Perform the math so that our equation looks like .
Then we multiply each side of the equation by the number that is under to get by itself:
Perform the math to find the answer, .