High School Chemistry : Acid-Base Chemistry

Study concepts, example questions & explanations for High School Chemistry

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Example Questions

Example Question #1 : Using Acid Dissociation Constant (Ka)

A student has a 0.50M solution of acetic acid. She adds solid sodium acetate until the concentration of sodium acetate is 0.050M. What is the final pH of the solution?

The  for acetic acid is . Assume the volume remains constant.

Possible Answers:

Correct answer:

Explanation:

Acetic acid is a weak acid, and its dissociation reaction is written as:

Using an ICE table, we can find the pH of the solution when the sodium acetate is added:

I: There is initially a 0.50M concentration of acetic acid. Because sodium acetate will dissolve completely, there will be a 0.050M concentration of acetate ions in the solution.

C: As acetic acid dissociates, the concentrations of acetate ions and hydronium ions will increase by an unknown concentration . Conversely, the acetic acid concentration will decrease by the same amount.

E: By setting the equilibrium expression equal to the acid equilibrium constant, we can solve for the value of .

*Because the value for  will be so much lower than the initial concentration, we can omit it from the acetate expression as well as the acetic acid concentration:

Keep in mind that  is equal to the concentration of hydronium ions now in the solution.

Use this value in the equation for pH:

Example Question #3 : Using Acid Dissociation Constant (Ka)

What property distinguishes a strong acid from a weak acid?

Possible Answers:

A weak acid will fail to dissociate completely in water and have a high Ka value

There is no difference between a strong acid and a weak acid based on their properties in water

A strong acid will dissociate completely in water and have a low Ka value

A strong acid will dissociate completely in water and have a high Ka value

A weak acid will dissociate completely in water and have a low Ka value

Correct answer:

A strong acid will dissociate completely in water and have a high Ka value

Explanation:

The acid dissociation constant (Ka) is used to distinguish strong acids from weak acids. Strong acids have exceptionally high Ka values.

The Ka value is found by looking at the equilibrium constant for the dissociation of the acid. The higher the Ka, the more the acid dissociates. Thus, strong acids must dissociate more in water. In contrast, a weak acid is less likely to ionize and release a hydrogen ion, thus resulting in a less acidic solution.

This equation makes it clear that the more the acid converts from its original form to its ionzied, dissociated form, the higher the Ka value will be.

Example Question #21 : P H And Poh Of Strong Acids And Bases

Which of the following is what determines the strength of an acid?

Possible Answers:

Electronegativity values

The Ka

Its physical state

The Kb

How many bonds the central atom makes

Correct answer:

The Ka

Explanation:

The Ka is the acid dissociation constant, and thus it is what determines how strong the acid is. Stronger acids dissociate to a greater extent and produce lower pH values.

Example Question #1 : Using Acid Dissociation Constant (Ka)

Determine the equilibrium concentration of ions in a solution.

Possible Answers:

Correct answer:

Explanation:

The definition of  for  is:

Set up an "ICE" table:

Plug in values:

Use the quadratic formula to solve:

Example Question #1 : Using Acid Dissociation Constant (Ka)

Determine the equilibrium concentration of  ions in a   solution.

Possible Answers:

Correct answer:

Explanation:

Set up an "ICE" table

Plug in values:

Use the quadratic formula:

Example Question #1 : Using Base Dissociation Constant (Kb)

A 1M solution of a monoprotic acid has a pH of 4.6. What is the  value for the conjugate base of the acid?

Possible Answers:

Correct answer:

Explanation:

In order to find the base dissociation constant for the conjugate base, we can start by finding the acid dissociation constant for the acid. Since a 1M solution of the acid has a pH of 4.6, we can find the proton concentration of the solution.

Since the acid is monoprotic, we can set the following equilibrium expression equal to its acid dissociation constant.

We can see that, since the acid is monoprotic, the concntration of protons will be equal to the concentration of the acid anion. The final concentration of the acid molecule will be equal to the initial concentration, minus the amount of protons formed. Using these values, we can solve for the equilibrium constant for the acid.

Now that we have the acid dissociation constant, we can find the conjugate base's dissociation constant by setting the product of the two values equal to the autoionization of water.

Example Question #1 : Help With Buffers

Which of the following would best buffer a solution from a pH of 4 to 6?

Possible Answers:

Carbonic acid (pKa = 6.3)

Formic acid (pKa = 3.7)

Uric acid (pKa = 3.9)

Acetic acid (pKa = 4.7)

Hydrocyanic acid (pKa = 9.2)

Correct answer:

Acetic acid (pKa = 4.7)

Explanation:

A weak acid/base best buffers about 1 pH point above and below its pKa. The pKA closest to the middle of 4 and 6 (so want as close to 5) is acetic acid at 4.7.

Example Question #41 : Reaction Types

Which of the following solutions has the greatest buffering capacity?

Possible Answers:

3M Rubidium Hydroxide

1M Acetic Acid

4M Nitric Acid

2M Formic Acid

Correct answer:

2M Formic Acid

Explanation:

Nitric Acid is a strong acid and can't buffer. Rubidium Hydroxide is a strong base and thus can't buffer. Of the remaining, both are weak acids, but the one with a greater concentration has a greater buffering capacity.

Example Question #1 : Help With Buffers

To create a buffer solution, you can use a weak acid and                       .

Possible Answers:

its conjugate acid

its conjugate base

a strong base

another weak acid

Correct answer:

its conjugate base

Explanation:

The definition of a buffer solution is that it contains a weak acid and its conjugate base, or a weak base and its conjugate acid. Since we are starting with a weak acid in this case, we need its conjugate base.

Example Question #41 : Acid Base Reactions

Which of the following will increase the pH of an  buffer solution?

I. Removing carbonic acid

II. Adding sodium bicarbonate

Possible Answers:

Neither of these options

Both I and II

II only

I only

Correct answer:

Both I and II

Explanation:

To answer this question we need to look at the reaction below:

An increase in the pH will result in a decrease in the concentration of hydrogen ions (). Using Le Chatelier’s principle we can find out which answer choices will decrease .

Removing carbonic acid will decrease the concentration of . To maintain equilibrium, the reaction will shift to the left and make more reactants from products; therefore, there will be a decrease in the  and an increase in pH.

Recall that salts like sodium bicarbonate, or , will dissociate in water and form ions. Sodium bicarbonate will form sodium () and bicarbonate () ions. This side reaction will result in an increase in the bicarbonate ion concentration. Le Chatelier’s principle will shift the equilibrium of the given reaction to the left and, therefore, decrease the . Adding sodium bicarbonate will increase the pH.

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