All GRE Subject Test: Biochemistry, Cell, and Molecular Biology Resources
Example Questions
Example Question #21 : Enzymes
How do competitive inhibitors affect enzyme efficiency?
Raise the Michaelis constant
Lower the Michaelis constant
Raise the maximum rate of the enzymatic reaction
Lower the maximum rate of the enzymatic reaction
Raise the Michaelis constant
Competitive inhibitors can be overpowered by introducing excess substrate, so they do not affect the maximum rate of the enzyme. They do, however, make it so that more substrate is required in order to get the enzyme working at half of its maximum rate. As a result, competitive inhibitors act by raising the Michaelis constant of enzymes.
Example Question #5 : Enzyme Regulation
How does a noncomeptitive inhibitor affect an enzyme?
Raises the Michaelis constant of the enzyme
Lowers the maximum rate of the enzymatic reaction
Raises the maximum rate of the enzymatic reaction
Lowers the Michaelis constant of the enzyme
Lowers the maximum rate of the enzymatic reaction
A noncompetitive inhibitor acts to decrease how fast the enzyme can act on substrates. It accomplishes this by lowering the maximum rate at which it can create products. Noncompetitive inhibitors do not alter the enzyme's Michaelis constant.
Example Question #6 : Enzyme Regulation
How is pepsinogen activated in the stomach?
It is phosphorylated by another enzyme
It is activated by the temperature change in the stomach lumen
Cofactors bind to the enzyme, increasing its efficiency
A portion is cleaved, activating the enzyme
A portion is cleaved, activating the enzyme
Once in the stomach lumen, pepsinogen finds itself in a very acidic environment. The acidic environment cleaves an amino acid sequence from pepsinogen, turning it into the active enzyme pepsin. This type of activation causes pepsin to only activate in the stomach lumen where it is needed.
Example Question #1 : Help With Glycolysis
The carbohydrate mannose is not present in the standard glycolytic pathway. It can, however, enter glycolysis by first being converted into another sugar. Which of the following choices represents the point at which mannose first enters the glycolytic pathway?
Glucose-6-phosphate
Fuctose-6-phosphate
Glucose
Fuctose-1,6-bisphosphate
Fuctose-6-phosphate
Mannose enters glycolysis by first being phosphorylated by hexokinase. The newly formed mannose-6-phosphate is then isomerized into fructose-6-phosphate by the enzyme phosphomannose isomerase. The sugar is now in a form that can follow the normal glycolytic pathway.
Example Question #2 : Cellular Metabolism
During the first step of glycolysis, glucose is phosphorylated by hexokinase. What is the purpose of this reaction?
The phophorylation of glucose creates a negative charge on the glucose molecule so that it cannot pass through the plasma membrane
The phophorylation of glucose changes the structure of glucose so that it can be isomerized in the next step
The hydrolysis of ATP is necessary to start the glycolytic pathway
The proton released via the phosphorylation reaction is necessary for the formation of NADH
The phophorylation of glucose creates a negative charge on the glucose molecule so that it cannot pass through the plasma membrane
If glucose was not phosphorylated, it would be free to diffuse through the plasma membrane and leave the cell. This situation would not be good for the cell because the reaction cannot continue outside of the cytosol. The negative charge created by the phosphorylation prevents the glucose molecule from crossing the plasma membrane due to the similar charge at the plasma membrane.
Example Question #1 : Help With Glycolysis
What does it mean to say that glycolysis has an energy investment phase?
ATP must be used in order to create the NADH in glycolysis
ATP must be used in order to prepare the glucose molecule to be split
ATP must be used in order to move the glucose into the cytosol
There is a net loss of ATP in glycolysis
ATP must be used in order to prepare the glucose molecule to be split
Glycolysis can be divided into two parts: the energy investment phase and the energy payoff phase. The energy investment phase comes first when glucose is phosphorylated twice, requiring the use of two molecules of ATP. After the glucose is split, four molecules of ATP will be made in the final steps. This results in a net gain of two ATP in glycolysis, but ATP must be spent prior to being made.
Example Question #1 : Help With Glycolysis
What molecule is the critical product of fermentation that is reinvested in glycolysis?
Glucose
ADP
NADH
NAD+
NAD+
During glycolysis, a total of two molecules of NAD+ are reduced in order to form two NADH molecules. These NAD+ molecules need to be regenerated in order for more glycolytic reactions to take place; otherwise, the process would come to a halt. Fermentation takes care of this problem in anaerobic environments by oxidizing excess NADH (since it is no longer utilized in the electron transport chain) into NAD+, which is then returned to the cytosol where it can be used again in glycolysis.
Example Question #2 : Cellular Respiration And Photosynthesis
In what cellular compartment does the process of glycolysis occur?
Endoplasmic reticulum
Nucleus
Cytosol
Mitochondrial outer membrane
Mitochondrial inner membrane
Cytosol
Both phases of glycolysis occur in the cytosol of the cell. The products of glycolysis are moved for further processing into the mitochondria, but the conversion of glucose to pyruvate is a cytosolic reaction.
Example Question #1 : Cellular Respiration And Photosynthesis
Glycolysis converts molecules of glucose into pyruvate. Glycolysis consists of two phases: the preparatory phase (which consumes ATP) and the pay-off phase (which produces ATP). Which of these correctly indicates the number of ATPs consumed in the preparatory phase, and the number of ATPs generated in the pay-off phase of anaerobic glycolysis.
2 ATP consumed, 4 ATP produced
2 ATP consumed, 2 ATP produced
4 ATP consumed, 2 ATP produced
6 ATP consumed, 2 ATP produced
3 ATP consumed, 3 ATP produced
2 ATP consumed, 4 ATP produced
The initial energy investment required for conversion of one glucose to pyruvate is 2 ATP in the preparatory phase. In the pay-off phase, substrate level phosphorylation produces a total of 4 ATP per initial glucose.
Example Question #1 : Cellular Respiration And Photosynthesis
Pyruvate must be oxidized into acetyl-CoA in order to enter the citric acid cycle. Which of the following answers contains the inputs required for this process per one molecule of pyruvate?
,
,
,
, coenzyme A
,
, coenzyme A
and are the resultant molecules from this conversion, not the inputs. and are important molecules in the citric acid cycle, but are not required for this particular oxidation step. must be reduced to , and coenzyme A is a crucial modulator of these reactions. Thus, and coenzyme A are the required inputs for the oxidation of pyruvate to acetyl CoA.