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GED Math : Geometry and Graphs

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4 Diagnostic Tests 263 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #57 : Squares, Rectangles, And Parallelograms

Find the area of a square with a length of 11cm.

Possible Answers:

$111\text{cm}^2$

$144\text{cm}^2$

$131\text{cm}^2$

$121\text{cm}^2$

$100\text{cm}^2$

Correct answer:

$121\text{cm}^2$

Explanation:

To find the area of a square, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the square.

Now, we know the length of the square is 11cm. Because it is a square, all sides are equal. Therefore, the width is also 11cm. So, we can substitute. We get

$A = 11\text{cm} \cdot 11\text{cm}$

$A = 121\text{cm}^2$

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Example Question #12 : Area Of A Quadrilateral

Find the area of a rectangle with a width of 7in and a length that is three times the width.

Possible Answers:

$147\text{in}^2$

$21\text{in}^2$

$28\text{in}^2$

$63\text{in}^2$

$168\text{in}^2$

Correct answer:

$147\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the width of the rectangle is 7in. We also know the length is three times the width. Therefore, the length is 21in. So, we can substitute. We get

$A =21\text{in} \cdot 7\text{in}$

$A = 147\text{in}^2$

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Example Question #13 : Area Of A Quadrilateral

A square has an area of $196\text{cm}^2$ . Find the length of one side.

Possible Answers:

$18\text{cm}$

$15\text{cm}$

$16\text{cm}$

$13\text{cm}$

$14\text{cm}$

Correct answer:

$14\text{cm}$

Explanation:

A square has 4 equal sides. The formula to find the area of a square is

A = b^2

where b is the length of one side of the square. To find the length of one side of the square, we will solve for b.

Now, we know the area of the square is $196\text{cm}^2$ . So, we will substitute and solve for b. So,

$196\text{cm}^2 = b^2$

$\sqrt{196\text{cm}^2} = \sqrt{b^2}$

$14\text{cm} = b$

$b = 14\text{cm}$

Therefore, the length of one side of the square is 14cm.

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Example Question #15 : Area Of A Quadrilateral

What of the following is NOT a property of a quadrilateral?

Possible Answers:

$\textup{The quadrilateral can be irregular.}$

$\textup{All of the following are properties of a quadrilateral.}$

$\textup{The quadrilateral must contain at least a set of parallel edges.}$

$\textup{A quadrilateral must contain 4 edges and 4 vertices.}$

$\textup{The interior angles must add up to 360 degrees.}$

Correct answer:

$\textup{The quadrilateral must contain at least a set of parallel edges.}$

Explanation:

A quadrilateral is a shape with four corners, or vertices, whose interior angles angles must sum up to 360 degrees.

The shape also has 4 edges.

The quadrilateral does not necessarily require two pairs of parallel lines.

Quadrilaterals may also be irregular.

The answer is:

$\textup{The quadrilateral must contain at least a set of parallel edges.}$

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Example Question #351 : Geometry And Graphs

Find the area of a square with a width of 7cm.

Possible Answers:

$\text{There is not enough information to solve the problem.}$

$49\text{cm}^2$

$35\text{cm}^2$

$42\text{cm}^2$

$28\text{cm}^2$

Correct answer:

$49\text{cm}^2$

Explanation:

To find the area of a square, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the square.

Now, we know the width of the square is 7cm. Because it is a square, all sides are equal. Therefore, the length is also 7cm. So, we can substitute. We get

$A = 7\text{cm} \cdot 7\text{cm}$

$A = 49\text{cm}^2$

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Example Question #21 : Area Of A Quadrilateral

Find the area of a rectangle with a length of 6in and a width that is a third of the length.

Possible Answers:

$9\text{in}^2$

$18\text{in}^2$

$12\text{in}^2$

$24\text{in}^2$

$16\text{in}^2$

Correct answer:

$12\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the length of the rectangle is 6in. We also know the width of the triangle is a third of the length. Therefore, the width is 2in. So, we substitute. We get

$A = 6\text{in} \cdot 2\text{in}$

$A = 12\text{in}^2$

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Example Question #1322 : Ged Math

A square has an area of $144\text{cm}^2$ . Find the length of one side.

Possible Answers:

$16\text{cm}$

$13\text{cm}$

$15\text{cm}$

$18\text{cm}$

$12\text{cm}$

Correct answer:

$12\text{cm}$

Explanation:

A square has 4 equal sides. The formula to find the area of a square is

A = b^2

where b is the length of one side of the square. To find the length of one side of the square, we will solve for b.

Now, we know the area of the square is $144\text{cm}^2$ . So, we will substitute and solve for b. So,

$144\text{cm}^2 = b^2$

$\sqrt{144\text{cm}^2} = \sqrt{b^2}$

$12\text{cm} = b$

$b = 12\text{cm}$

Therefore, the length of one side of the square is 12cm.

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Example Question #22 : Area Of A Quadrilateral

Use the following rectangle to answer the question:

Rectangle1

Find the area.

Possible Answers:

$18\text{in}^2$

$24\text{in}^2$

$9\text{in}^2$

$15\text{in}^2$

$12\text{in}^2$

Correct answer:

$18\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

So, given the rectangle

Rectangle1

we can see the length is 6in and the width is 3in. So, we can substitute. We get

$A = 6\text{in} \cdot 3\text{in}$

$A = 18\text{in}^2$

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Example Question #23 : Area Of A Quadrilateral

Use the following square to answer the question:

Square2

Find the area.

Possible Answers:

$94\text{cm}^2$

$196\text{cm}^2$

$121\text{cm}^2$

$48\text{cm}^2$

$169\text{cm}^2$

Correct answer:

$196\text{cm}^2$

Explanation:

To find the area of a square, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the square.

Now, given the square

Square2

we can see the length is 14cm. Because it is a square, all sides are equal. Therefore, the width is also 14cm. So, we can substitute. We get

$A = 14\text{cm} \cdot 14\text{cm}$

$A = 196\text{cm}^2$

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Example Question #24 : Area Of A Quadrilateral

Find the area of a square with a perimeter of .

Possible Answers:

128

4096

2048

256

Correct answer:

256

Explanation:

A square has four equal sides.

This means that each side is one fourth of the perimeter.

$s=\frac{1}{4} (64) = 16$

Write the area of a square.

A=s^2 = 16^2 = 256

The answer is: 256

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All GED Math Resources

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GED Math : Geometry and Graphs

Study concepts, example questions & explanations for GED Math

All GED Math Resources

Example Questions

Example Question #57 : Squares, Rectangles, And Parallelograms

Example Question #12 : Area Of A Quadrilateral

Example Question #13 : Area Of A Quadrilateral

Example Question #15 : Area Of A Quadrilateral

Example Question #351 : Geometry And Graphs

Example Question #21 : Area Of A Quadrilateral

Example Question #1322 : Ged Math

Example Question #22 : Area Of A Quadrilateral

Example Question #23 : Area Of A Quadrilateral

Example Question #24 : Area Of A Quadrilateral

All GED Math Resources

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