GED Math : Algebra

Study concepts, example questions & explanations for GED Math

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Example Questions

Example Question #651 : Ged Math

Give the solution set:

\(\displaystyle 4x < 8x + 72\)

Possible Answers:

\(\displaystyle \left \{ x | x< 6\right \}\)

\(\displaystyle \left \{ x | x > -18\right \}\)

\(\displaystyle \left \{ x | x< -19\right \}\)

\(\displaystyle \left \{ x | x > 6\right \}\)

Correct answer:

\(\displaystyle \left \{ x | x > -18\right \}\)

Explanation:

Collect the like terms by subtracting \(\displaystyle 8x\) from both sides:

\(\displaystyle 4x - 8x < 8x + 72 - 8x\)

\(\displaystyle -4x < 72\)

Isolate \(\displaystyle x\) on the right by dividing both sides by \(\displaystyle -4\). Reverse the direction of the inequality symbol, since you are dividing by a negative number:

\(\displaystyle \frac{-4x}{-4} > \frac{72}{-4}\)

\(\displaystyle x > -18\)

The solution set is \(\displaystyle \left \{ x | x > -18\right \}\).

Example Question #652 : Ged Math

Solve for \(\displaystyle x\):  \(\displaystyle 7x-3 = -5-2x\)

Possible Answers:

\(\displaystyle -\frac{8}{5}\)

\(\displaystyle \frac{5}{8}\)

\(\displaystyle \frac{8}{9}\)

\(\displaystyle -\frac{2}{9}\)

\(\displaystyle -\frac{8}{9}\)

Correct answer:

\(\displaystyle -\frac{2}{9}\)

Explanation:

Add \(\displaystyle 2x\) on both sides.

\(\displaystyle 7x-3 +2x= -5-2x+2x\)

\(\displaystyle 9x-3 = -5\)

Add three on both sides.

\(\displaystyle 9x-3+3 = -5+3\)

\(\displaystyle 9x =-2\)

Divide by 9 on both sides.

\(\displaystyle \frac{9x}{9} =\frac{-2}{9}\)

The answer is:  \(\displaystyle -\frac{2}{9}\)

Example Question #653 : Ged Math

Solve for \(\displaystyle x\):  \(\displaystyle -8x+7 = 9x+1\)

Possible Answers:

\(\displaystyle -\frac{6 }{17}\)

\(\displaystyle \frac{6 }{17}\)

\(\displaystyle 8\)

\(\displaystyle 6\)

\(\displaystyle -\frac{8}{17}\)

Correct answer:

\(\displaystyle \frac{6 }{17}\)

Explanation:

Add \(\displaystyle 8x\) on both sides.

\(\displaystyle -8x+7+8x = 9x+1+8x\)

\(\displaystyle 7= 17x+1\)

Subtract 1 from both sides.

\(\displaystyle 7-1= 17x+1-1\)

\(\displaystyle 6 = 17x\)

Divide by 17 on both sides.

\(\displaystyle \frac{6 }{17}= \frac{17x}{17}\)

The answer is:  \(\displaystyle \frac{6 }{17}\)

Example Question #654 : Ged Math

Solve the for \(\displaystyle x\):  \(\displaystyle -3x+5 = -8\)

Possible Answers:

\(\displaystyle 1\)

\(\displaystyle \frac{13}{3}\)

\(\displaystyle -\frac{13}{3}\)

\(\displaystyle 16\)

\(\displaystyle -1\)

Correct answer:

\(\displaystyle \frac{13}{3}\)

Explanation:

Subtract 5 from both sides.

\(\displaystyle -3x+5 -5= -8-5\)

\(\displaystyle -3x = -13\)

Divide by negative three on both sides.

\(\displaystyle \frac{-3x}{-3} = \frac{-13}{-3}\)

The answer is:  \(\displaystyle \frac{13}{3}\)

Example Question #655 : Ged Math

Which of the following makes this equation true:

\(\displaystyle 8x - 13 = 99\)

Possible Answers:

\(\displaystyle x=13\)

\(\displaystyle x=14\)

\(\displaystyle x=8\)

\(\displaystyle x=9\)

\(\displaystyle x=12\)

Correct answer:

\(\displaystyle x=14\)

Explanation:

To answer the question, we will solve for x. We get

\(\displaystyle 8x - 13 = 99\)

\(\displaystyle 8x-13+13=99+13\)

\(\displaystyle 8x-0=112\)

\(\displaystyle 8x=112\)

\(\displaystyle \frac{8x}{8} = \frac{112}{8}\)

\(\displaystyle x = 14\)

Example Question #661 : Ged Math

Solve for x:  

\(\displaystyle 2(x-3 )= -13\)

Possible Answers:

\(\displaystyle \frac{7}{12}\)

\(\displaystyle \frac{7}{4}\)

\(\displaystyle \frac{21}{2}\)

\(\displaystyle -\frac{7}{2}\)

\(\displaystyle -\frac{21}{2}\)

Correct answer:

\(\displaystyle -\frac{7}{2}\)

Explanation:

Distribute the two with both of the terms inside the binomial.

\(\displaystyle 2x-6 = -13\)

Add 6 on both sides.

\(\displaystyle 2x-6 +6= -13+6\)

\(\displaystyle 2x =-7\)

Divide by 2 on both sides.

\(\displaystyle \frac{2x }{2}=\frac{-7}{2}\)

The answer is:  \(\displaystyle -\frac{7}{2}\)

Example Question #662 : Ged Math

Solve for \(\displaystyle x\).

\(\displaystyle \sqrt{3x-3}+2=14\)

Possible Answers:

\(\displaystyle 51\)

\(\displaystyle 49\)

\(\displaystyle 55\)

\(\displaystyle 53\)

Correct answer:

\(\displaystyle 49\)

Explanation:

\(\displaystyle \sqrt{3x-3}+2=14\)

Start by subtracting \(\displaystyle 2\) from both sides.

\(\displaystyle \sqrt{3x-3}=12\)

Square both sides of the equation to get rid of the square root.

\(\displaystyle 3x-3=144\)

Add \(\displaystyle 3\) to both sides of the equation.

\(\displaystyle 3x=147\)

Divide both sides by \(\displaystyle 3\).

\(\displaystyle x=49\)

 

Example Question #663 : Ged Math

Which of the following makes this equation true:

\(\displaystyle 7h+19=103\)

Possible Answers:

\(\displaystyle h=12\)

\(\displaystyle h=19\)

\(\displaystyle h=9\)

\(\displaystyle h=13\)

\(\displaystyle h=8\)

Correct answer:

\(\displaystyle h=12\)

Explanation:

To answer the question, we will solve for h. We get

\(\displaystyle 7h+19=103\)

\(\displaystyle 7h+19-19=103-19\)

\(\displaystyle 7h+0=84\)

\(\displaystyle 7h=84\)

\(\displaystyle \frac{7h}{7} = \frac{84}{7}\)

\(\displaystyle h=12\)

Example Question #101 : Single Variable Algebra

Solve:  \(\displaystyle 3x = -\frac{1}{11}\)

Possible Answers:

\(\displaystyle -\frac{11}{3}\)

\(\displaystyle -\frac{1}{33}\)

\(\displaystyle -\frac{1}{14}\)

\(\displaystyle -\frac{1}{3}\)

\(\displaystyle -\frac{3}{11}\)

Correct answer:

\(\displaystyle -\frac{1}{33}\)

Explanation:

To isolate the x-variable, we will need to multiply by one-third on both sides.

\(\displaystyle 3x \cdot \frac{1}{3}= -\frac{1}{11} \cdot \frac{1}{3}\)

The answer is:  \(\displaystyle -\frac{1}{33}\)

Example Question #665 : Ged Math

Which of the following makes this equation true:

\(\displaystyle 9x-5=94\)

Possible Answers:

\(\displaystyle x=11\)

\(\displaystyle x=9\)

\(\displaystyle x=5\)

\(\displaystyle x=13\)

\(\displaystyle x=12\)

Correct answer:

\(\displaystyle x=11\)

Explanation:

To answer the question, we will solve for x. So, we get

\(\displaystyle 9x-5=94\)

 

\(\displaystyle 9x-5+5=94+5\)

 

\(\displaystyle 9x-0=99\)

 

\(\displaystyle 9x=99\)

 

\(\displaystyle \frac{9x}{9} = \frac{99}{9}\)

 

\(\displaystyle x=11\)

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