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GED Math : Triangles

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Example Questions

Example Question #2 : Similar Triangles And Proportions

Which of the following statements follows from the statement $\Delta KLM \sim \Delta XYZ$ ?

Possible Answers:

$\angle L \cong \angle M$

$\frac{KL}{LM } = \frac{XY}{YZ}$

$\overline{KM} \cong \overline{XZ}$

$\angle K \cong \angle Y$

Correct answer:

$\frac{KL}{LM } = \frac{XY}{YZ}$

Explanation:

The similarity of two triangles implies nothing about the relationship of two angles of the same triangle. Therefore, $\angle L \cong \angle M$ can be eliminated.

The similarity of two triangles implies that corresponding angles between the triangles are congruent. However, because of the positions of the letters, $\angle K$ in $\Delta KLM$ corresponds to $\angle X$ , not $\angle Y$ , in $\Delta XYZ$ , so $\angle K \cong \angle X$ . The statement $\angle K \cong \angle Y$ can be eliminated.

Similarity of two triangles does not imply any congruence between sides of the triangles, so $\overline{KM} \cong \overline{XZ}$ can be eliminated.

Similarity of triangles implies that corresponding sides are in proportion. $\overline{KL}$ and $\overline{LM}$ in $\Delta KLM$ correspond, respectively, to $\overline{XY}$ and $\overline{YZ}$ in $\Delta XYZ$ . Therefore, it follows that $\frac{KL}{LM } = \frac{XY}{YZ}$ , and this statement is the correct choice.

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Example Question #81 : Triangles

Triangles

Note: Figure NOT drawn to scale.

Refer to the above diagram. If $\Delta ABC \sim \Delta DE F$ , which of the following is false?

Possible Answers:

$\angle E$ is a right angle

EF = 20

DF = 30

$\angle A \cong \angle D$

Correct answer:

EF = 20

Explanation:

Suppose $\Delta ABC \sim \Delta DE F$ .

Corresponding angles of similar triangles are congruent, so $\angle A \cong \angle D$ . Also, $\angle B \cong \angle E$ , so, since $\angle B$ is a right angle, so is $\angle E$ .

Corresponding sides of similar triangles are in proportion. Since

$\frac{DE}{AB} = \frac{24}{8} = 3$ ,

the similarity ratio of $\Delta DE F$ to $\Delta ABC$ is 3.

By the Pythagorean Theorem, since is the hypotenuse of a right triangle with legs 6 and 8, its measure is

$AC = \sqrt{6^{2} + 8 ^{2}} = \sqrt{36 + 64 } = \sqrt{100} = 10$ .

$DF = 3 (AC) = 3 \cdot 10 = 30$ , so DF = 30 is a true statement.

But $EF = 3 (BC) = 3 \cdot 8 = 24 \neq 20$ , so EF = 20 is false if the triangles are similar. This is the correct choice.

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Example Question #2 : Similar Triangles And Proportions

Triangles

Note: Figures NOT drawn to scale.

Refer to the above figures. Given that $\Delta ABC \sim \Delta DE F$ , evaluate .

Possible Answers:

$93\frac{1}{3}$

$52 \frac{1}{2}$

Correct answer:

Explanation:

By the Pythagorean Theorem, since is the hypotenuse of a right triangle with legs 6 and 8, its measure is

$AC = \sqrt{6^{2} + 8 ^{2}} = \sqrt{36 + 64 } = \sqrt{100} = 10$ .

The similarity ratio of $\Delta DE F$ to $\Delta ABC$ is

$\frac{DF}{AC} = \frac{70}{10} = 7$ .

Likewise,

$\frac{EF}{BC} = 7$

$\frac{EF}{6} = 7$

EF = 42

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Example Question #3 : Similar Triangles And Proportions

Triangles

Note: Figures NOT drawn to scale.

Refer to the above figures. Given that $\Delta ABC \sim \Delta DE F$ , give the area of $\Delta DE F$ .

Possible Answers:

486

607.5

810

405

Correct answer:

486

Explanation:

Corresponding angles of similar triangles are congruent, so, since $\angle B$ is right, so is $\angle E$ . This makes $\overline{DE}$ and $\overline{EF}$ the legs of a right triangle, so its area is half their product.

By the Pythagorean Theorem, since is the hypotenuse of a right triangle with legs 6 and 8, its measure is

$AC = \sqrt{6^{2} + 8 ^{2}} = \sqrt{36 + 64 } = \sqrt{100} = 10$ .

The similarity ratio of $\Delta DE F$ to $\Delta ABC$ is

$\frac{DF}{AC} = \frac{45}{10} = 4.5$ .

This can be used to find and :

$\frac{DE}{AB} = 4.5$

$\frac{DE}{8} = 4.5$

$DE = 8 \cdot 4.5 = 36$

$\frac{EF}{BC} = 4.5$

$\frac{EF}{6} = 4.5$

$EF = 6 \cdot 4.5 = 27$

The area of $\Delta DE F$ is therefore

$\frac{1}{2} \cdot DE \cdot EF = \frac{1}{2} \cdot 36 \cdot 27 =486$ .

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Example Question #2 : Similar Triangles And Proportions

In the figure below, the two triangles are similar. Find the value of .

Possible Answers:

Correct answer:

Explanation:

Since the two triangles are similar, we know that their corresponding sides must be in the same ratio to each other. Thus, we can write the following equation:

$\frac{12}{8}=\frac{9}{x}$

Now, solve for .

12x=72

x=6

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Example Question #82 : Triangles

The two legs of a right triangle measure 30 and 40. What is its perimeter?

Possible Answers:

125

130

140

120

135

Correct answer:

120

Explanation:

By the Pythagorean Theorem, if a ,b are the legs of a right triangle and is its hypotenuse,

$c^{2} = a^{2} + b^{2}$

Substitute a = 30, b= 40 and solve for :

$c^{2} = 30 ^{2} + 40^{2} = 900 + 1,600 = 2,500$

$c = \sqrt{2,500} = 50$

The perimeter of the triangle is

P = 30 + 40 + 50 = 120

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Example Question #2 : Pythagorean Theorem

A right triangle has legs 30 and 40. Give its perimeter.

Possible Answers:

600

120

1,200

Correct answer:

120

Explanation:

The hypotenuse of the right triangle can be calculated using the Pythagorean theorem:

$c = \sqrt{30^{2}+40^{2}} = \sqrt{900+1600} = \sqrt{2,500} = 50$

Add the three sides:

P = 30 + 40 + 50 = 120

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Example Question #3 : Pythagorean Theorem

A right triangle has one leg measuring 14 inches; its hypotenuse is 50 inches. Give its perimeter.

Possible Answers:

$112 \textrm{ in}$

$114\textrm{ in}$

$78 \textrm{ in}$

$64\textrm{ in}$

Correct answer:

$112 \textrm{ in}$

Explanation:

The Pythagorean Theorem can be used to derive the length of the second leg:

$b = \sqrt{50^{2}-14^{2}} = \sqrt{2,500 - 196} = \sqrt{2,304} = 48$ inches

Add the three sides to get the perimeter.

P = 14 + 48 + 50 = 112 inches.

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Example Question #4 : Pythagorean Theorem

Whicih of the following could be the lengths of the sides of a right triangle?

Possible Answers:

10 inches, 1 foot, 14 inches

7 inches, 2 feet, 30 inches

15 inches, 3 feet, 40 inches

2 feet, 32 inches, 40 inches

Correct answer:

2 feet, 32 inches, 40 inches

Explanation:

A triangle is right if and only if it satisfies the Pythagorean relationship

$a ^{2}+ b^{2}= c^{2}$

where is the measure of the longest side and a,b are the other two sidelengths. We test each of the four sets of lengths, remembering to convert feet to inches by multiplying by 12.

7 inches, 2 feet, 30 inches:

2 feet is equal to 24 inches. The relationship to be tested is

$7^{2}+ 24 ^{2} = 30^{2}$

49 + 576 = 900

625 = 900 - False

10 inches, 1 foot, 14 inches:

1 foot is equal to 12 inches. The relationship to be tested is

$10^{2}+ 12^{2}= 14^{2}$

100 + 144 = 196

244 = 196 - False

15 inches, 3 feet, 40 inches:

3 feet is equal to 36 inches. The relationship to be tested is

$15^{2}+ 36^{2} = 40^{2}$

225 + 1,296 = 1,600

1,521 = 1,600 - False

2 feet, 32 inches, 40 inches:

2 feet is equal to 24 inches. The relationship to be tested is

$24 ^{2}+ 32^{2} = 40^{2}$

576+ 1,024= 1,600

1,600 =1,600 - True

The correct choice is 2 feet, 32 inches, 40 inches.

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Example Question #4 : Pythagorean Theorem

An isosceles right triangle has hypotenuse 80 inches. Give its perimeter. (If not exact, round to the nearest tenth of an inch.)

Possible Answers:

$96.6\textrm{ in}$

$136.6\textrm{ in}$

$153.1 \textrm{ in}$

$193.1 \textrm{ in}$

Correct answer:

$193.1 \textrm{ in}$

Explanation:

Each leg of an isosceles right triangle has length that is the length of the hypotenuse divided by $\sqrt{2}$ . The hypotenuse has length 80, so each leg has length

$\frac{80}{\sqrt{2}} = \frac{80\cdot \sqrt{2}}{\sqrt{2} \cdot \sqrt{2}}= \frac{80 \sqrt{2}}{2} = 40 \sqrt{2}$ .

The perimeter is the sum of the three sides:

$80 + 40 \sqrt{2}+ 40\sqrt{2}= 80 + 80\sqrt{2}$ inches.To the nearest tenth:

$80 + 80\sqrt{2} \approx 80 + 80 \times 1.414 \approx 80 + 113.1 = 193.1$ inches.

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GED Math : Triangles

Study concepts, example questions & explanations for GED Math

All GED Math Resources

Example Questions

Example Question #2 : Similar Triangles And Proportions

Example Question #81 : Triangles

Example Question #2 : Similar Triangles And Proportions

Example Question #3 : Similar Triangles And Proportions

Example Question #2 : Similar Triangles And Proportions

Example Question #82 : Triangles

Example Question #2 : Pythagorean Theorem

Example Question #3 : Pythagorean Theorem

Example Question #4 : Pythagorean Theorem

Example Question #4 : Pythagorean Theorem

All GED Math Resources

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