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GED Math : Triangles

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Example Questions

Example Question #3 : Area Of A Triangle

Find the area of a triangle with a base of 7in and a height that is two times the base.

Possible Answers:

$36\text{in}^2$

$49\text{in}^2$

$98\text{in}^2$

$28\text{in}^2$

$21\text{in}^2$

Correct answer:

$49\text{in}^2$

Explanation:

To find the area of a triangle, we will use the following formula:

$A = \frac{1}{2} \cdot b \cdot h$

where b is the base and h is the height of the triangle.

Now, we know the base of the triangle is 7in. We also know the height of the triangle is two times the base. Therefore, the height is 14in. So, we can substitute. We get

$A = \frac{1}{2} \cdot 7\text{in} \cdot 14\text{in}$

$A = \frac{1}{2} \cdot 14\text{in} \cdot 7\text{in}$

$A = 7\text{in} \cdot 7\text{in}$

$A = 49\text{in}^2$

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Example Question #4 : Area Of A Triangle

Find the area of a triangle with a base of 8in and a height that is half the base.

Possible Answers:

$16\text{in}^2$

$12\text{in}^2$

$24\text{in}^2$

$36\text{in}^2$

$32\text{in}^2$

Correct answer:

$16\text{in}^2$

Explanation:

To find the area of a triangle, we will use the following formula:

$A = \frac{1}{2} \cdot b \cdot h$

where b is the base and h is the height of the triangle.

Now, we know the base of the triangle is 8in. We also know the height of the triangle is half the base. Therefore, the height is 4in. So, we can substitute. We get

$A = \frac{1}{2} \cdot 8\text{in} \cdot 4\text{in}$

$A = 4\text{in} \cdot4\text{in}$

$A = 16\text{in}^2$

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Example Question #3 : Area Of A Triangle

What is the area of a triangle with a base of $\frac{1}{2}$ and a height of $\frac{2}{3}$ ?

Possible Answers:

$\frac{1}{6}$

$\frac{1}{2}$

$\frac{1}{12}$

$\frac{1}{9}$

$\frac{1}{3}$

Correct answer:

$\frac{1}{6}$

Explanation:

Write the formula for the area of a triangle.

$A = \frac{1}{2}bh$

Substitute the base and height.

$A = \frac{1}{2}(\frac{1}{2})(\frac{2}{3})$

Simplify the fractions.

The answer is: $\frac{1}{6}$

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Example Question #3 : Area Of A Triangle

Find the area of a triangle with a base of 6cm and a height that is three times the base.

Possible Answers:

$18\text{cm}^2$

$108\text{cm}^2$

$36\text{cm}^2$

$54\text{cm}^2$

$48\text{cm}^2$

Correct answer:

$54\text{cm}^2$

Explanation:

To find the area of a triangle, we will use the following formula:

$A = \frac{1}{2} \cdot b \cdot h$

where b is the base and h is the height of the triangle.

Now, we know the base of the triangle is 6cm. We also know the height is three times the base. Therefore, the height is 18cm. So, we substitute. We get

$A = \frac{1}{2} \cdot 6\text{cm} \cdot 18\text{cm}$

$A = 3\text{cm} \cdot 18\text{cm}$

$A = 54\text{cm}^2$

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Example Question #3 : Area Of A Triangle

Find the area of a triangle with a base of 10in and a height of 9in.

Possible Answers:

$35\text{in}^2$

$45\text{in}^2$

$40\text{in}^2$

$28\text{in}^2$

$90\text{in}^2$

Correct answer:

$45\text{in}^2$

Explanation:

To find the area of a triangle, we will use the following formula:

$A = \frac{1}{2} \cdot b \cdot h$

where b is the base and h is the height of the triangle.

Now, we know the base of the triangle is 10in. We know the height of the triangle is 9in. So, we can substitute. We get

$A = \frac{1}{2} \cdot 10\text{in} \cdot 9\text{in}$

$A = 5\text{in} \cdot 9\text{in}$

$A = 45\text{in}^2$

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Example Question #211 : 2 Dimensional Geometry

Find the area of a triangle with a base of 8cm and a height of 12cm.

Possible Answers:

$20\text{cm}^2$

$48\text{cm}^2$

$24\text{cm}^2$

$96\text{cm}^2$

$32\text{cm}^2$

Correct answer:

$48\text{cm}^2$

Explanation:

To find the area of a triangle, we will use the following formula:

$A = \frac{1}{2} \cdot b \cdot h$

where b is the base and h is the height of the triangle.

We know the base of the triangle is 8cm.

We know the height of the triangle is 12cm.

Now, we can substitute. We get

$A = \frac{1}{2} \cdot 8\text{cm} \cdot 12\text{cm}$

$A = 4\text{cm} \cdot 12\text{cm}$

$A = 48\text{cm}^2$

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Example Question #211 : Geometry And Graphs

Find the area of a triangle with a base of 16x^2 and a height of .

Possible Answers:

64x^5

8x^2+2x

32x^3

64x^3

16x^2+4x

Correct answer:

32x^3

Explanation:

Write the area for a triangle.

$A= \frac{BH}{2}$

Substitute the base and height.

$A= \frac{(16x^2)(4x)}{2} = \frac{64x^3}{2} = 32x^3$

The answer is: 32x^3

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Example Question #12 : Area Of A Triangle

Find the area of a triangle with a base of 14in and a height of 9in.

Possible Answers:

$72\text{in}^2$

$126\text{in}^2$

$54\text{in}^2$

$63\text{in}^2$

$88\text{in}^2$

Correct answer:

$63\text{in}^2$

Explanation:

To find the area of a triangle, we will use the following formula:

$A = \frac{1}{2} \cdot b \cdot h$

where b is the base and h is the height of the triangle.

Now, we know the base of the triangle is 14in and the height is 9in. So, we can substitute. We get

$A = \frac{1}{2} \cdot 14\text{in} \cdot 9\text{in}$

$A = 7\text{in} \cdot 9\text{in}$

$A = 63\text{in}^2$

Report an Error

Example Question #32 : Triangles

Find the area of a triangle with a base of and a height of .

Possible Answers:

108

Correct answer:

Explanation:

Write the formula for a triangle.

$A = \frac{BH}{2}$

Substitute the dimensions and find the area.

$A = \frac{(12)(3)}{2} = 6(3) = 18$

The answer is:

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Example Question #33 : Triangles

Find the area of a triangle with a base length of 6 and a height of $\frac{1}{4}$ .

Possible Answers:

$\frac{1}{2}$

$\frac{3}{2}$

$\frac{3}{4}$

$\frac{2}{3}$

Correct answer:

$\frac{3}{4}$

Explanation:

Write the area for a triangle.

$A = \frac{BH}{2}$

Substitute the base and height into the equation.

$A = \frac{6(\frac{1}{4})}{2} = 3(\frac{1}{4}) = \frac{3}{4}$

The answer is: $\frac{3}{4}$

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GED Math : Triangles

Study concepts, example questions & explanations for GED Math

All GED Math Resources

Example Questions

Example Question #3 : Area Of A Triangle

Example Question #4 : Area Of A Triangle

Example Question #3 : Area Of A Triangle

Example Question #3 : Area Of A Triangle

Example Question #3 : Area Of A Triangle

Example Question #211 : 2 Dimensional Geometry

Example Question #211 : Geometry And Graphs

Example Question #12 : Area Of A Triangle

Example Question #32 : Triangles

Example Question #33 : Triangles

All GED Math Resources

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