Computer Science : Object-Oriented Program Design
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Example Questions
Example Question #1 : Object Oriented Program Design
Which of the following header statements allow you to omit using the std:: when using cout?
#include <cmath>
#include <standard>
using namespace std;
You don't need a header statement.
#include <iostream>
using namespace std;
You must put using namespace std; at the top of your file to avoid having to type std:: every time you use cout and cin.
Example Question #1 : Class Libraries
Which of the access modifiers don't work in Java?
abstract
final
static
delete
delete
One of the benefits to Java is that there is garbage collection. So when data is disposed of its done automatically versus a language like C++ where you need to tell the program to delete dynamically allocated data.
Example Question #11 : Object Oriented Program Design
What line of code is needed to import in order to use Color in the following format Color.Blue, Color.RED, Color.White?
import java.util.Color;
import java.awt.Color;
import java.io.Color;
import java.awt.*;
import java.awt.*;
If you were to use the following format Color.Red, Color.Blue, etc then the correct answer would have to be java.awt.*; While java.awt.Color; does fit the appropriate code, if you import that entire statement, you don't need to put Color.Red just Red and following. The other two import statements are just completely wrong.
Example Question #12 : Class Design
For this question, consider the following code:
private static class Philosopher {
private String name;
private String favoriteSubject;
public Philosopher(String n, String f) {
name = n;
favoriteSubject = f;
}
public String getName() {
return name;
}
public String getFavoriteSubject() {
return favoriteSubject;
}
public void speak() {
System.out.println("Hello, World! My name is "+name + ". My favorite subject is "+favoriteSubject);
}
}
private static class Nominalist extends Philosopher {
boolean franciscan;
public Nominalist(String n,boolean frank) {
super(n,"logic");
franciscan = frank;
}
public void speak() {
super.speak();
if(franciscan) {
System.out.println("I am a Franciscan");
} else {
System.out.println("I am not a Franciscan");
}
}
public String whoMightHaveTaughtMe() {
if(franciscan) {
return "Perhaps William of Ockham?....";
} else {
return "Perhaps it was Durandus of St. Pourçain — scandalous, a Dominican nominalist!";
}
}
}
public static void main(String[] args) {
Philosopher p = new Nominalist("Nicanor",false);
System.out.println(p.whoMightHaveTaughtMe());
}
What is the output for this main method?
Perhaps William of Ockham?....
Perhaps it was Durandus of St. Pourçain — scandalous, a Dominican nominalist!
There is no output.
This will not compile. That method is defined on the subclass, but the variable is defined as the superclass Philosopher, meaning that the method is not visible.
This will not compile. You cannot call a subclass function within the scope of the main method.
This will not compile. That method is defined on the subclass, but the variable is defined as the superclass Philosopher, meaning that the method is not visible.
When you assign a subclass (like Nominalist) to a super class (like Philosopher) you will not be able to call any of the subclass-specific methods on the variable in question. This code does just that, which will prevent the code from compiling.
Example Question #1 : Class Inheritance
Consider the following code:
private static class Philosopher {
private String name;
private String favoriteSubject;
public Philosopher(String n, String f) {
name = n;
favoriteSubject = f;
}
public String getName() {
return name;
}
public String getFavoriteSubject() {
return favoriteSubject;
}
public void speak() {
System.out.println("Hello, World! My name is "+name + ". My favorite subject is "+favoriteSubject);
}
}
private static class Nominalist extends Philosopher {
boolean franciscan;
public Nominalist(String n,boolean frank) {
super(n,"logic");
franciscan = frank;
}
public void speak() {
super.speak();
if(franciscan) {
System.out.println("I am a Franciscan");
} else {
System.out.println("I am not a Franciscan");
}
}
public String whoMightHaveTaughtMe() {
if(franciscan) {
return "Perhaps William of Ockham?....";
} else {
return "Perhaps it was Durandus of St. Pourçain — scandalous, a Dominican nominalist!";
}
}
}
public static void main(String[] args) {
Philosopher[] phils = {
new Philosopher("Petrus","Ethics"),
new Nominalist("Minimus Maximus",false),
new Nominalist("Theodoric",true)};
for(int i = 0; i < phils.length; i++) {
phils[i].speak();
}
}
What is the output for the code above?
Hello, World! My name is Petrus. My favorite subject is Ethics
Hello, World! My name is Minimus Maximus. My favorite subject is logic
Hello, World! My name is Theodoric. My favorite subject is logic
Hello, World! My name is Petrus. My favorite subject is Ethics
Hello, World! My name is Minimus Maximus. My favorite subject is logic
I am not a Franciscan
Hello, World! My name is Theodoric. My favorite subject is logic
I am a Franciscan
Hello, World! My name is Petrus. My favorite subject is Ethics
Hello, World! My name is Minimus Maximus. My favorite subject is logic
Hello, World! My name is Theodoric. My favorite subject is logic
Hello, World! My name is Minimus Maximus. My favorite subject is logic. I am not a Franciscan
Hello, World! My name is Petrus. My favorite subject is Ethics
Hello, World! My name is Theodoric. My favorite subject is logic. I am a Franciscan
Hello, World! My name is Petrus. My favorite subject is Ethics
Hello, World! My name is Minimus Maximus. My favorite subject is logic I am not a Franciscan
Hello, World! My name is Theodoric. My favorite subject is logic I am a Franciscan
Hello, World! My name is Petrus. My favorite subject is Ethics
Hello, World! My name is Minimus Maximus. My favorite subject is logic
I am not a Franciscan
Hello, World! My name is Theodoric. My favorite subject is logic
I am a Franciscan
Three things must be kept in mind for this question. First (and foremost), given the way that inheritance works, you know that for each object, you will get an output that matches the given object's particular type—even though the array is an array of the superclass type (namely Philosopher). Second, you must notice that the lines "I am a Franciscan" and "I am not a Franciscan" come a line after the data before it (which is printed by using the super call). Finally, be careful about punctuation! There are periods missing in some of the output lines.
Example Question #3 : Class Inheritance
Consider the following code:
public class Rectangle {
private double width, height;
public Rectangle(double w,double h) {
width = w;
height = h;
}
public double getArea() {
return width * height;
}
public double getPerimeter() {
return 2 * width + 2 * height;
}
}
public class Square {
private double side;
public Square(double s) {
side = s;
}
public double getArea() {
return side * side;
}
public double getPerimeter() {
return 4 * side;
}
}
Which of the following represents a redefinition of Square that utilizes the benefits of inheritance?
public class Square {
private Rectangle r;
public Square(double s) {
r = new Rectangle(s,s);
}
public double getArea() {
return r.getArea();
}
public double getPerimeter() {
return r.getPerimeter();
}
}
public class Square implements Rectangle {
public Square(double s) {
super(s,s);
}
}
public class Square extends Rectangle {
public Square(double s) {
new Rectangle(s,s);
}
}
public class Square extends Rectangle {
public Square(double s) {
super(s,s);
}
}
public class Square extends Rectangle {
private double side;
public Square(double s) {
super(s,s);
}
}
public class Square extends Rectangle {
public Square(double s) {
super(s,s);
}
}
We know that a square really is just a subclass of a rectangle, for it is merely a rectangle having four sides that are all equal. Using inheritance, you can very easily reuse much of your Rectangle code. First, you need to extend the Rectangle class:
public class Square extends Rectangle { . . .
Next, you can be rid of the field side. This allows you to alter the constructor for Square to call the Rectangle constructor. You do this using super (because Rectangle is the superclass).
After this, you can delete the getArea and getPerimeter methods, for they will be handled by the superclass. This gives you a very simple bit of code!
Example Question #11 : Class Design
Which of the following is TRUE about the Object class?
Object is the only class that never has any descendants.
None of these answers are true.
Object inherits a minimum of four classes.
Object has one superclass, Entity.
Every class has all of Object's methods.
Every class has all of Object's methods.
Object is the most basic class which all others, even user made ones, inherit. Therefore, all classes have Object's methods. A way to think of classes is to think of a tree: the Object class is the lowest node on the tree, where all other nodes can connect back to.
Example Question #2 : Class Inheritance
class Z
{
public:
void Func4();
};
class Y : public Z
{
public:
virtual void Func3();
};
class B : public Y
public:
virtual void Func1();
void Func2();
};
class C : public B
public:
virtual void Func1();
};
What is the base class in the above code.
Class B
Class C
None of them
Class Z
Class Y
Class Z
The base class is a class that doesn't derivate from any other class. Starting from the bottom of the code, we see that class C is inherited from class B, which is inherited from class Y, which is finally inherited by class Z. Class Z is the base class.
Example Question #1 : Class Inheritance
class Pet {
public:
Pet() {}
virtual void bar() {cout << "In pet bar(); }
};
class Cat : public Pet {
public:
virtual void eat() {cout << "Cat eating"; }
virtual void bar() {cout << "In Cat bar()"; }
};
Given the above classes, what would the result of:
int main(){
Cat felix;
Pet peeve;
peeve = felix;
peeve.bar();
}
None of the above
The program runs and prints: In Cat bar()
The program runs and prints: In Pet Bar()
Runtime error
Compilation Error
The program runs and prints: In Pet Bar()
The Cat class is inherited from the Pet class and an instance of each object is created in main.
peeve = felix;
When felix is assigned to peeve, it loses it's atributes as a Cat and now becomes a Pet. When the bar method is called, it will call bar inside the Pet class and not the Cat class.
If the line of code was:
felix = peeve;
Then, the program will crash. This crashes because we are trying to assign a Pet (which is the parent), to a Cat (which is a child class). Assigning a parent to a child will cause a Slicing Problem because the parent is "bigger" than the child. If you try to put something big (a Pet) into a small container (a Cat), it will not work.
Example Question #2 : Class Inheritance
class Member{
public:
Member() { cout<< 1 ; }
};
class Base{
public:
Base(){ cout<< 1; }
Memeber member;
};
class Derived : public Base{
public:
Derived(){ cout << 3; }
};
int main(){
Derived der;
}
Given the code above, what is the output of the program?
213
312
132
321
123
123
When an object is created the order of which everything is created is as follows:
1. Member variables are created first.
2. The constructor of the parent class called (if the object has a parent)
3. The object's own constructor is called.
Following the code, we can see that a Derived object is created in main. Since the Derived class has a parent, the call order jumps to the Base class. Now we are inside the Base class, nothing has been outputted yet. Inside the Base class, the local variables are created first. This brings us to the Member class.
In the Member class, the constructor is called and 1 is outputted.
After this, we jump back to the constructor of the Base class and 2 is outputted.
Finally, we get back to where we started, the Derived class. The constructor of derived is called and 3 is outputted. The final output is 123.
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