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Complex Analysis : Complex Numbers

Study concepts, example questions & explanations for Complex Analysis

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Example Questions

Example Question #11 : Complex Numbers

Evaluate:

$\left| ( 8 + 5 i ) ( -10 + 3 i ) \right|$

Possible Answers:

$\sqrt{9701}$

$- \sqrt{9701}$

9701

$\frac{\sqrt{9701}}{2}$

Correct answer:

$\sqrt{9701}$

Explanation:

The general formula to figure out the modulus is

$\left|a+bi\right|=\sqrt{a^2+b^2}$

We apply this to get

$\left| ( 8 + 5 i ) ( -10 + 3 i ) \right| = \sqrt{ 64 + 25 }\cdot \sqrt{ 100 + 9 }$

$= \sqrt{89} \cdot \sqrt{109}$

$= \sqrt{9701}$

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Example Question #12 : Complex Numbers

Evaluate: $\left| 9 - 7 i \right|$

Possible Answers:

130

$\sqrt{130}$

$-\sqrt{130}$

Correct answer:

$\sqrt{130}$

Explanation:

The general formula to figure out the modulus is

$\left|a+bi\right|=\sqrt{a^2+b^2}$ .

We apply this notion to get.

$\left| 9 - 7 i \right| = \sqrt{ 81 + 49 }$

$= \sqrt{130}$

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Example Question #13 : Complex Numbers

Evaluate $(\sqrt{3} - i)^6$

Possible Answers:

None of the other answers

-64

-64i

64i

Correct answer:

-64

Explanation:

Converting from rectangular to polar coordinates gives us

$r = \sqrt{x^2+y^2} = \sqrt{3+1} = 2$

$\theta = tan^{-1}(y/x) = tan^{-1}\left(-\frac{1}{\sqrt{3}}\right) = -\frac{\pi}{6}$

$(\sqrt{3}-i)^6 = (2e^{-\frac{\pi}{6}i})^6 = 64e^{-\pi i} = -64$

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Example Question #14 : Complex Numbers

Compute $(-16)^\frac{1}{4}$

Possible Answers:

$\pm\sqrt{2}(1-i)$

$\pm(\sqrt{3} - i) \text{ and } \pm(1+\sqrt{3}i)$

$\pm 2 \text{ and } \pm 2i$

$\pm\sqrt{2}(1+i)$

$\pm\sqrt{2}(1+i) \text{ and } \pm\sqrt{2}(1-i)$

Correct answer:

$\pm\sqrt{2}(1+i) \text{ and } \pm\sqrt{2}(1-i)$

Explanation:

Converting from Rectangular to Polar Coordinates

$(-16)^\frac{1}{4} = (16e^{i\pi + 2\pi k})^\frac{1}{4} = 2e^{i\frac{\pi}{4} + \frac{\pi}{2}k}$

Evaluating for k = 0,1,2,3

we get that

$\pm\sqrt{2}(1+i) \text{ and } \pm\sqrt{2}(1-i)$

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Example Question #15 : Complex Numbers

The 5th roots of unity are the five unique solutions to which equation?

Possible Answers:

z^5-1=0

None of these

(z-1)^5=0

z^5+z^4+z^3+z^2+z+1=0

z^5+1=0

Correct answer:

z^5-1=0

Explanation:

A 5th root of unity is a complex number such that z^5=1 . Manipulating this equation yields z^5-1=0 .

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Example Question #16 : Complex Numbers

What is the magnitude of the following complex number?

5+2i

Possible Answers:

$\sqrt{14}$

$\sqrt{29}$

None of these

Correct answer:

$\sqrt{29}$

Explanation:

The magnitude of a complex number a+bi is defined as

$\vert a+bi\vert=\sqrt{a^2+b^2}.$

So the modulus of 5+2i is

$\vert5+2i\vert=\sqrt{5^2+2^2}=\sqrt{25+4}=\sqrt{29}$ .

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Example Question #14 : Complex Numbers

What is the magnitude of the following complex number?

3-i

Possible Answers:

$\sqrt{10}$

None of these

$\sqrt{8}$

Correct answer:

$\sqrt{10}$

Explanation:

The magnitude of a complex number a+bi is defined as

$\vert a+bi\vert=\sqrt{a^2+b^2}.$

So the modulus of 3-i is

$\vert3-i\vert=\sqrt{3^2+(-1)^2}=\sqrt{9+1}=\sqrt{10}$ .

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Example Question #17 : Complex Numbers

What is the magnitude of the following complex number?

Possible Answers:

$2\sqrt2$

None of these

Correct answer:

Explanation:

The magnitude of a complex number a+bi is defined as

$\vert a+bi\vert=\sqrt{a^2+b^2}.$

Because the complex number has no imaginary part, we can write it in the form 8+0i . Then the modulus of 8+0i is

$\vert8+0i\vert=\sqrt{8^2+0^2}=\sqrt{64+0}=\sqrt{64}=8$ .

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Example Question #18 : Complex Numbers

What is the argument of the following complex number?

1+i

Possible Answers:

$\frac{-3\pi}{4}$

$\frac{\pi}{4}$

None of these

$\frac{\pi}{2}$

Correct answer:

$\frac{\pi}{4}$

Explanation:

Note that the complex number 1+i lies in the first quadrant of the complex plane.

For a complex number z=a+bi , the argument of is defined as the real number $\theta$ such that

$\tan(\theta)=\frac{b}{a}$ ,

where $-\pi<\theta\leq\pi$ is in radians.

Then the argument of 1+i is

$\tan(\theta)=\frac{1}{1}=1$

$\theta=\frac{-3\pi}{4},\frac{\pi}{4}$ .

The angle $\frac{-3\pi}{4}$ lies in the third quadrant of the complex plane, but the angle $\frac{\pi}{4}$ lies in the first quadrant, as does 1+i . So $\theta=\frac{\pi}{4}$ .

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Example Question #19 : Complex Numbers

What is the argument of the following complex number in radians, rounded to the nearest hundredth?

2-3i

Possible Answers:

3.61

None of these

-0.98

-0.59

2.16

Correct answer:

-0.98

Explanation:

Note that the complex number 2-3i lies in the fourth quadrant of the complex plane.

For a complex number z=a+bi , the argument of is defined as the real number $\theta$ such that

$\tan(\theta)=\frac{b}{a}$ ,

where $-\pi<\theta\leq\pi$ is in radians.

Then the argument of 2-3i is

$\tan(\theta)=\frac{-3}{2}$

$\theta=-0.98,2.16$ .

The angle 2.16 lies in the second quadrant of the complex plane, but the angle -0.98 lies in the fourth quadrant, as does 2-3i . So $\theta=-0.98$ .

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Complex Analysis : Complex Numbers

Study concepts, example questions & explanations for Complex Analysis

All Complex Analysis Resources

Example Questions

Example Question #11 : Complex Numbers

Example Question #12 : Complex Numbers

Example Question #13 : Complex Numbers

Example Question #14 : Complex Numbers

Example Question #15 : Complex Numbers

Example Question #16 : Complex Numbers

Example Question #14 : Complex Numbers

Example Question #17 : Complex Numbers

Example Question #18 : Complex Numbers

Example Question #19 : Complex Numbers

All Complex Analysis Resources

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