Common Core: High School - Geometry : High School: Geometry

Study concepts, example questions & explanations for Common Core: High School - Geometry

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All Common Core: High School - Geometry Resources

6 Diagnostic Tests 114 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #5 : Understand That By Similarity, Side Ratios In Right Triangles Are Properties Of The Angles In The Triangle, Leading To Definitions Of Trigonometric Ratios For Acute Angles

Using the information from the triangle below, use the side ratios to find .

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Possible Answers:

Correct answer:

Explanation:

The definition of the sine of an angle is .  So here we must determine which side is opposite of angle  and which side is the hypotenuse of this triangle.  We know that side  is the hypotenuse since it is opposite of the right angle.  Side  is directly opposite of angle .  So:

 

Example Question #6 : Understand That By Similarity, Side Ratios In Right Triangles Are Properties Of The Angles In The Triangle, Leading To Definitions Of Trigonometric Ratios For Acute Angles

Consider the following right triangle.  Use trigonometric ratios to solve for sides  and .

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Possible Answers:

Correct answer:

Explanation:

 We are given angle  and we need to find sides  and .  So first we need to think about what relation these sides are to angle .  Side  is the hypotenuse of the triangle since it is opposite of the right angle.  So side must be the side adjacent to angle .  Recall that the trigonometric ratio that corresponds to cosine is .  We can solve for the missing sides by solving for the following equation.

 

It follows that:

 

Example Question #7 : Understand That By Similarity, Side Ratios In Right Triangles Are Properties Of The Angles In The Triangle, Leading To Definitions Of Trigonometric Ratios For Acute Angles

Using the information of the side lengths in the triangle below, use the side ratios to find the .

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Possible Answers:

Correct answer:

Explanation:

The definition of cosine of an acute angle is .  So here we must determine what sides are adjacent and which is the hypotenuse.  The hypotenuse is the easiest to pick out.  This is the side that is directly across from the right angle in a right triangle.  Our hypotenuse is .  Now we must choose the adjacent side.  Adjacent means next to, and since  is our hypotenuse then  must be our adjacent side.  So:

 

Example Question #2 : Understand That By Similarity, Side Ratios In Right Triangles Are Properties Of The Angles In The Triangle, Leading To Definitions Of Trigonometric Ratios For Acute Angles

Find angle  using trigonometric ratios.

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Possible Answers:

60 degrees

50 degrees

75 degrees

45 degrees

Correct answer:

45 degrees

Explanation:

We are given the adjacent side to angle  and the hypotenuse of the triangle.  We can use this to set up the trigonometric ratio  which we know to be the definition of cosine.  We can solve for angle  using the following equation.

Example Question #9 : Understand That By Similarity, Side Ratios In Right Triangles Are Properties Of The Angles In The Triangle, Leading To Definitions Of Trigonometric Ratios For Acute Angles

Assume the two triangles below are similar.  Using the fact that their side ratios are , what trigonomic function could this represent for angles  and .

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Possible Answers:

Correct answer:

Explanation:

We must begin by manipulating our equation of the side ratios to get fractions that include both of the sides of the same triangles:

 

 multiply both sides by 

 divide both sides by 

 

If we look at angle  we see that  is the .  Looking at angle  we see that  is also the .  This is the definition of the tangent of an angle.  So:

 

Example Question #10 : Understand That By Similarity, Side Ratios In Right Triangles Are Properties Of The Angles In The Triangle, Leading To Definitions Of Trigonometric Ratios For Acute Angles

Assume the following two triangles are similar.  Using the fact that their side ratios are , what trigonomic function could this represent for angles  and ?

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Possible Answers:

Correct answer:

Explanation:

We must begin by manipulating our equation of the side ratios to get fractions that include both of the sides of the same triangles:

 

 

 

If we look at angle , we see that  is the .  Looking at angle  we see that  is also the .  This is the definition of the sine function.  So:

 

Example Question #1 : Derive The Formula A = 1/2 Ab Sin(C) For The Area Of A Triangle By Drawing An Auxiliary Line From A Vertex Perpendicular To The Opposite Side

Is the following statement True or False?

We want to use the formula .  Consider an obtuse triangle .  We know the lengths of  and , but only know the angle for .  We are still able to use this formula.

Possible Answers:

False

True

Correct answer:

True

Explanation:

There are two approaches to this problem.  We are able to calculate the angle by using the Sine Law.  The Sine Law states:

 

So we can set  and solve accordingly for angle .

Our other option is to use the area formula we have been but altering it to correspond to angle .  We would draw our vertical line down from the vertex as shown below and our formula would be in the form .

 

 

Example Question #1 : Derive The Formula A = 1/2 Ab Sin(C) For The Area Of A Triangle By Drawing An Auxiliary Line From A Vertex Perpendicular To The Opposite Side

Solve for x using the formula  given that the area of the following triangle is  (round to the second decimal  place if needed).

Possible Answers:

Correct answer:

Explanation:

Even though the formula  is using sides and angle , this is a general formula and can be used with any angle in the triangle.  Since we are now working with an obtuse angle rather than an acute angle, we need to do some more work to get the logic right.

Using the figure above, to be able to label the sides we are using correctly, we extend the original triangle horizontally past the obtuse angle and draw a vertical line down from the top vertex to form a right angle.  This vertical line is .  Angle  for the supplementary (orange) triangle is .  Using the fact that , we can set up our formula to be the following:

 (either angle can be used and I will show this to be true)

  (Using from the original triangle)

 

This shows that when using this formula for an obtuse angle, you can use either the supplementary angle you made, or the original.  It is always helpful to draw this supplementary triangle in order to be able to visualize and understand logically how the formula is working for obtuse angles as well.

 

 

 

Example Question #2 : Derive The Formula A = 1/2 Ab Sin(C) For The Area Of A Triangle By Drawing An Auxiliary Line From A Vertex Perpendicular To The Opposite Side

Is the following statement True or False?

In order to use this formula, you only need to know two of the triangles sides' lengths.

 

Possible Answers:

True

False

Correct answer:

False

Explanation:

In order to use this formula you need to either the height (which can be used to find the angle) or the angle (which can be used to find the height).

Example Question #3 : Derive The Formula A = 1/2 Ab Sin(C) For The Area Of A Triangle By Drawing An Auxiliary Line From A Vertex Perpendicular To The Opposite Side

Given the triangle below, what is the formula for finding the area?

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Possible Answers:

The area of triangle  is .  Considering the entire triangle, .  Solving for , .  Therefore, .

The area of triangle  is .  Only considering the right triangle , .  Solving for , .  Therefore, .

The area of triangle  is .  Considering the right triangle , . Solving for , . Therefore, .

The area of triangle  is Considering the entire triangle, Solving for Therefore, .

Correct answer:

The area of triangle  is .  Only considering the right triangle , .  Solving for , .  Therefore, .

Explanation:

The formula for the area of a triangle is (base)(height).  Since this is an obtuse triangle we need to break it into two right triangles by drawing the line down from the vertex perpendicular to the opposite side.

 

Now that we have two right triangles we can solve for the area of this triangle.  Notice our base is and our height is .  Plugging into the formula for the area of a triangle gives us .  Most of the time, we will not have an exact length for , but we may have, or will be able to solve for, the lengths of  and the angles .  Using our  relationship for right triangles, we know .  In this case we will use  as our angle.  So

 

    

    


We can plug  in for in our formula for area and we are left with .

All Common Core: High School - Geometry Resources

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