We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

Common Core: High School - Algebra : Reasoning with Equations & Inequalities

Study concepts, example questions & explanations for Common Core: High School - Algebra

Create An Account

All Common Core: High School - Algebra Resources

8 Diagnostic Tests 97 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Where do the following equations intersect?

$\displaystyle y = - 45 x + 19$

$\displaystyle y = 43 x - 4$

Possible Answers:

$\left( \frac{23}{88} , \frac{637}{88} \right)$ $\displaystyle \left( \frac{23}{88} , \frac{637}{88} \right)$

$\left( \frac{64}{47} , \frac{1695}{88} \right)$ $\displaystyle \left( \frac{64}{47} , \frac{1695}{88} \right)$

$\left( \frac{64}{47} , \frac{637}{88} \right)$ $\displaystyle \left( \frac{64}{47} , \frac{637}{88} \right)$

$\left( - \frac{45}{43} , \frac{637}{88} \right)$ $\displaystyle \left( - \frac{45}{43} , \frac{637}{88} \right)$

$\left( \frac{64}{47} , 13 \right)$ $\displaystyle \left( \frac{64}{47} , 13 \right)$

Correct answer:

$\left( \frac{23}{88} , \frac{637}{88} \right)$ $\displaystyle \left( \frac{23}{88} , \frac{637}{88} \right)$

Explanation:

To figure out where these equations intersect, we need to set them equal to each other and solve for $\uptext{x}$ $\displaystyle \uptext{x}$.

$\displaystyle - 45 x + 19 = 43 x - 4$

$\displaystyle - 45 x = 43 x - 23$

$\displaystyle - 88 x = -23$

$x = \frac{23}{88}$ $\displaystyle x = \frac{23}{88}$

Now we simply plug this $\uptext{x}$ $\displaystyle \uptext{x}$ value into one of the equations to get the $\uptext{y}$ $\displaystyle \uptext{y}$ value.

$y = -45 \cdot \frac{23}{88} + 19$ $\displaystyle y = -45 \cdot \frac{23}{88} + 19$

$y = - \frac{1035}{88} + 19$ $\displaystyle y = - \frac{1035}{88} + 19$

$y = \frac{637}{88}$ $\displaystyle y = \frac{637}{88}$

Report an Error

Example Question #2 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Where do the following equations intersect?

$\displaystyle y = 22 x - 47$

$\displaystyle y = - 44 x + 4$

Possible Answers:

$\left( \frac{17}{22} , -30 \right)$ $\displaystyle \left( \frac{17}{22} , -30 \right)$

$\left( - \frac{1}{2} , -30 \right)$ $\displaystyle \left( - \frac{1}{2} , -30 \right)$

$\left( \frac{23}{16} , -65 \right)$ $\displaystyle \left( \frac{23}{16} , -65 \right)$

$\left( \frac{23}{16} , - \frac{1017}{22} \right)$ $\displaystyle \left( \frac{23}{16} , - \frac{1017}{22} \right)$

$\left( \frac{23}{16} , -30 \right)$ $\displaystyle \left( \frac{23}{16} , -30 \right)$

Correct answer:

$\left( \frac{17}{22} , -30 \right)$ $\displaystyle \left( \frac{17}{22} , -30 \right)$

Explanation:

To figure out where these equations intersect, we need to set them equal to each other and solve for $\uptext{x}.$ $\displaystyle \uptext{x}.$

$\displaystyle 22 x - 47 = - 44 x + 4$

$\displaystyle 22 x = - 44 x + 51$

$\displaystyle 66 x = 51$

$x = \frac{17}{22}$ $\displaystyle x = \frac{17}{22}$

Now we simply plug this $\uptext{x}$ $\displaystyle \uptext{x}$ value into one of the equations to get the $\uptext{y}$ $\displaystyle \uptext{y}$ value.

$y = 22 \cdot \frac{17}{22} -47$ $\displaystyle y = 22 \cdot \frac{17}{22} -47$

$\displaystyle y = 17 -47$

y = -30 $\displaystyle y = -30$

Report an Error

Example Question #1 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Where do the following equations intersect?

$\displaystyle y = 49 x + 17$

$\displaystyle y = - 40 x - 23$

Possible Answers:

$\left( \frac{32}{17} , \frac{1473}{89} \right)$ $\displaystyle \left( \frac{32}{17} , \frac{1473}{89} \right)$

$\left( \frac{32}{17} , - \frac{447}{89} \right)$ $\displaystyle \left( \frac{32}{17} , - \frac{447}{89} \right)$

$\left( \frac{32}{17} , 3 \right)$ $\displaystyle \left( \frac{32}{17} , 3 \right)$

$\left( - \frac{40}{89} , - \frac{447}{89} \right)$ $\displaystyle \left( - \frac{40}{89} , - \frac{447}{89} \right)$

$\left( - \frac{49}{40} , - \frac{447}{89} \right)$ $\displaystyle \left( - \frac{49}{40} , - \frac{447}{89} \right)$

Correct answer:

$\left( - \frac{40}{89} , - \frac{447}{89} \right)$ $\displaystyle \left( - \frac{40}{89} , - \frac{447}{89} \right)$

Explanation:

To figure out where these equations intersect, we need to set them equal to each other and solve for $\uptext{x}.$ $\displaystyle \uptext{x}.$

Subtract $\displaystyle 17$ from both sides:

$\displaystyle 49 x + 17 = - 40 x - 23$

Add 40x $\displaystyle 40x$ to both sides:

$\displaystyle 49 x = - 40 x - 40$

Divide both sides by $89\textup:$ $\displaystyle 89\textup:$

$\displaystyle 89 x = -40$

$x = - \frac{40}{89}$ $\displaystyle x = - \frac{40}{89}$

Now plug this $\uptext{x}$ $\displaystyle \uptext{x}$ value into one of the equations to solve for the $\uptext{y}$ $\displaystyle \uptext{y}$ value.

$\displaystyle y = 49 x + 17$

$y = 49 \cdot - \frac{40}{89} + 17$ $\displaystyle y = 49 \cdot - \frac{40}{89} + 17$

Multiply $\frac{49}{1}$ $\displaystyle \frac{49}{1}$ by $-\frac{40}{89}\textup:$ $\displaystyle -\frac{40}{89}\textup:$

$y = - \frac{1960}{89} + 17$ $\displaystyle y = - \frac{1960}{89} + 17$

Make fractions with common denominators:

$\frac{17}{1}=\frac{1513}{89}$ $\displaystyle \frac{17}{1}=\frac{1513}{89}$

Add fractions:

$y = - \frac{1960}{89} + \frac{1513}{89}$ $\displaystyle y = - \frac{1960}{89} + \frac{1513}{89}$

$y = - \frac{447}{89}$ $\displaystyle y = - \frac{447}{89}$

Report an Error

Example Question #1 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Where do the following equations intersect?

$\displaystyle y = 16 x + 22$

$\displaystyle y = - 10 x + 30$

Possible Answers:

$\left( \frac{4}{13} , \frac{350}{13} \right)$ $\displaystyle \left( \frac{4}{13} , \frac{350}{13} \right)$

$\left( - \frac{3}{20} , \frac{350}{13} \right)$ $\displaystyle \left( - \frac{3}{20} , \frac{350}{13} \right)$

$\left( - \frac{3}{20} , 58 \right)$ $\displaystyle \left( - \frac{3}{20} , 58 \right)$

$\left( - \frac{8}{5} , \frac{350}{13} \right)$ $\displaystyle \left( - \frac{8}{5} , \frac{350}{13} \right)$

$\left( - \frac{3}{20} , \frac{290}{13} \right)$ $\displaystyle \left( - \frac{3}{20} , \frac{290}{13} \right)$

Correct answer:

$\left( \frac{4}{13} , \frac{350}{13} \right)$ $\displaystyle \left( \frac{4}{13} , \frac{350}{13} \right)$

Explanation:

To figure out where these equations intersect, we need to set them equal to each other and solve for $\uptext{x}$ $\displaystyle \uptext{x}$.

$\displaystyle 16 x + 22 = - 10 x + 30$

Now we subtract $\displaystyle 22$ from each side.

$\displaystyle 16 x = - 10 x + 8$

Now we add 10 x $\displaystyle 10 x$ to each side.

$\displaystyle 26 x = 8$

Now we divide by $\displaystyle 26$ on each side.

$x = \frac{4}{13}$ $\displaystyle x = \frac{4}{13}$

Now we simply plug this $\uptext{x}$ $\displaystyle \uptext{x}$ value into one of the equations to get the $\uptext{y}$ $\displaystyle \uptext{y}$ value.

$y = 16 \cdot \frac{4}{13} + 22$ $\displaystyle y = 16 \cdot \frac{4}{13} + 22$

$y = \frac{64}{13} + 22$ $\displaystyle y = \frac{64}{13} + 22$

$y = \frac{350}{13}$ $\displaystyle y = \frac{350}{13}$

Report an Error

Example Question #2 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Where do the following equations intersect?

$\displaystyle y = - 23 x - 30$

$\displaystyle y = 4 x - 13$

Possible Answers:

$\left( - \frac{23}{4} , - \frac{419}{27} \right)$ $\displaystyle \left( - \frac{23}{4} , - \frac{419}{27} \right)$

$\left( - \frac{7}{17} , -62 \right)$ $\displaystyle \left( - \frac{7}{17} , -62 \right)$

$\left( - \frac{7}{17} , - \frac{827}{27} \right)$ $\displaystyle \left( - \frac{7}{17} , - \frac{827}{27} \right)$

$\left( - \frac{7}{17} , - \frac{419}{27} \right)$ $\displaystyle \left( - \frac{7}{17} , - \frac{419}{27} \right)$

$\left( - \frac{17}{27} , - \frac{419}{27} \right)$ $\displaystyle \left( - \frac{17}{27} , - \frac{419}{27} \right)$

Correct answer:

$\left( - \frac{17}{27} , - \frac{419}{27} \right)$ $\displaystyle \left( - \frac{17}{27} , - \frac{419}{27} \right)$

Explanation:

To figure out where these equations intersect, we need to set them equal to each other and solve for $\uptext{x}$ $\displaystyle \uptext{x}$.

$\displaystyle - 23 x - 30 = 4 x - 13$

Now we add $\displaystyle 30$ to each side.

$\displaystyle - 23 x = 4 x + 17$

Now we subtract 4 x $\displaystyle 4 x$ from each side.

$\displaystyle - 27 x = 17$

Now we divide by $\displaystyle -27$ on each side.

$x = - \frac{17}{27}$ $\displaystyle x = - \frac{17}{27}$

Now we simply plug this $\uptext{x}$ $\displaystyle \uptext{x}$ value into one of the equations to get the $\uptext{y}$ $\displaystyle \uptext{y}$ value.

$y = -23 \cdot - \frac{17}{27} -30$ $\displaystyle y = -23 \cdot - \frac{17}{27} -30$

$y = \frac{391}{27} -30$ $\displaystyle y = \frac{391}{27} -30$

$y = - \frac{419}{27}$ $\displaystyle y = - \frac{419}{27}$

Report an Error

Example Question #3 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Where do the following equations intersect?

$\displaystyle y = - 4 x + 20$

$\displaystyle y = 12 x - 35$

Possible Answers:

$\left( \frac{55}{16} , \frac{25}{4} \right)$ $\displaystyle \left( \frac{55}{16} , \frac{25}{4} \right)$

$\left( \frac{24}{47} , -7 \right)$ $\displaystyle \left( \frac{24}{47} , -7 \right)$

$\left( - \frac{1}{3} , \frac{25}{4} \right)$ $\displaystyle \left( - \frac{1}{3} , \frac{25}{4} \right)$

$\left( \frac{24}{47} , \frac{375}{16} \right)$ $\displaystyle \left( \frac{24}{47} , \frac{375}{16} \right)$

$\left( \frac{24}{47} , \frac{25}{4} \right)$ $\displaystyle \left( \frac{24}{47} , \frac{25}{4} \right)$

Correct answer:

$\left( \frac{55}{16} , \frac{25}{4} \right)$ $\displaystyle \left( \frac{55}{16} , \frac{25}{4} \right)$

Explanation:

To figure out where these equations intersect, we need to set them equal to each other and solve for $\uptext{x}$ $\displaystyle \uptext{x}$.

$\displaystyle - 4 x + 20 = 12 x - 35$

Now we subtract $\displaystyle 20$ from each side.

$\displaystyle - 4 x = 12 x - 55$

Now we subtract 12 x $\displaystyle 12 x$ from each side.

$\displaystyle - 16 x = -55$

Now we divide by $\displaystyle -16$ on each side.

$x = \frac{55}{16}$ $\displaystyle x = \frac{55}{16}$

Now we simply plug this $\uptext{x}$ $\displaystyle \uptext{x}$ value into one of the equations to get the $\uptext{y}$ $\displaystyle \uptext{y}$ value.

$y = -4 \cdot \frac{55}{16} + 20$ $\displaystyle y = -4 \cdot \frac{55}{16} + 20$

$y = - \frac{55}{4} + 20$ $\displaystyle y = - \frac{55}{4} + 20$

$y = \frac{25}{4}$ $\displaystyle y = \frac{25}{4}$

Report an Error

Example Question #4 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Where do the following equations intersect?

$\displaystyle y = - 29 x - 22$

$\displaystyle y = - x - 9$

Possible Answers:

$\left( \frac{7}{8} , -61 \right)$ $\displaystyle \left( \frac{7}{8} , -61 \right)$

$\left( \frac{7}{8} , - \frac{239}{28} \right)$ $\displaystyle \left( \frac{7}{8} , - \frac{239}{28} \right)$

$\left( 29 , - \frac{239}{28} \right)$ $\displaystyle \left( 29 , - \frac{239}{28} \right)$

$\left( \frac{7}{8} , - \frac{629}{28} \right)$ $\displaystyle \left( \frac{7}{8} , - \frac{629}{28} \right)$

$\left( - \frac{13}{28} , - \frac{239}{28} \right)$ $\displaystyle \left( - \frac{13}{28} , - \frac{239}{28} \right)$

Correct answer:

$\left( - \frac{13}{28} , - \frac{239}{28} \right)$ $\displaystyle \left( - \frac{13}{28} , - \frac{239}{28} \right)$

Explanation:

To figure out where these equations intersect, we need to set them equal to each other and solve for $\uptext{x}$ $\displaystyle \uptext{x}$.

$\displaystyle - 29 x - 22 = - x - 9$

Now we add $\displaystyle 22$ to each side.

$\displaystyle - 29 x = - x + 13$

Now we add $\displaystyle x$ to each side.

$\displaystyle - 28 x = 13$

Now we divide by $\displaystyle -28$ on each side.

$x = - \frac{13}{28}$ $\displaystyle x = - \frac{13}{28}$

Now we simply plug this $\uptext{x}$ $\displaystyle \uptext{x}$ value into one of the equations to get the $\uptext{y}$ $\displaystyle \uptext{y}$ value.

$y = -29 \cdot - \frac{13}{28} -22$ $\displaystyle y = -29 \cdot - \frac{13}{28} -22$

$y = \frac{377}{28} -22$ $\displaystyle y = \frac{377}{28} -22$

$y = - \frac{239}{28}$ $\displaystyle y = - \frac{239}{28}$

Report an Error

Example Question #5 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Where do the following equations intersect?

$\displaystyle y = 29 x + 30$

$\displaystyle y = - 41 x + 33$

Possible Answers:

$\left( - \frac{1}{74} , \frac{2187}{70} \right)$ $\displaystyle \left( - \frac{1}{74} , \frac{2187}{70} \right)$

$\left( - \frac{29}{41} , \frac{2187}{70} \right)$ $\displaystyle \left( - \frac{29}{41} , \frac{2187}{70} \right)$

$\left( - \frac{1}{74} , 51 \right)$ $\displaystyle \left( - \frac{1}{74} , 51 \right)$

$\left( \frac{3}{70} , \frac{2187}{70} \right)$ $\displaystyle \left( \frac{3}{70} , \frac{2187}{70} \right)$

$\left( - \frac{1}{74} , \frac{2103}{70} \right)$ $\displaystyle \left( - \frac{1}{74} , \frac{2103}{70} \right)$

Correct answer:

$\left( \frac{3}{70} , \frac{2187}{70} \right)$ $\displaystyle \left( \frac{3}{70} , \frac{2187}{70} \right)$

Explanation:

To figure out where these equations intersect, we need to set them equal to each other and solve for $\uptext{x}$ $\displaystyle \uptext{x}$.

$\displaystyle 29 x + 30 = - 41 x + 33$

Now we subtract $\displaystyle 30$ from each side.

$\displaystyle 29 x = - 41 x + 3$

Now we add 41 x $\displaystyle 41 x$ to each side.

$\displaystyle 70 x = 3$

Now we divide by $\displaystyle 70$ on each side.

$x = \frac{3}{70}$ $\displaystyle x = \frac{3}{70}$

Now we simply plug this $\uptext{x}$ $\displaystyle \uptext{x}$ value into one of the equations to get the $\uptext{y}$ $\displaystyle \uptext{y}$ value.

$y = 29 \cdot \frac{3}{70} + 30$ $\displaystyle y = 29 \cdot \frac{3}{70} + 30$

$y = \frac{87}{70} + 30$ $\displaystyle y = \frac{87}{70} + 30$

$y = \frac{2187}{70}$ $\displaystyle y = \frac{2187}{70}$

Report an Error

Example Question #6 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Where do the following equations intersect?

$\displaystyle y = - 10 x + 41$

$\displaystyle y = 7 x + 7$

Possible Answers:

$\left( -\infty , 45 \right)$ $\displaystyle \left( -\infty , 45 \right)$

$\left( - \frac{10}{7} , 21 \right)$ $\displaystyle \left( - \frac{10}{7} , 21 \right)$

$\left( -\infty , 43 \right)$ $\displaystyle \left( -\infty , 43 \right)$

$\left( 2 , 21 \right)$ $\displaystyle \left( 2 , 21 \right)$

$\left( -\infty , 21 \right)$ $\displaystyle \left( -\infty , 21 \right)$

Correct answer:

$\left( 2 , 21 \right)$ $\displaystyle \left( 2 , 21 \right)$

Explanation:

To figure out where these equations intersect, we need to set them equal to each other and solve for $\uptext{x}$ $\displaystyle \uptext{x}$.

$\displaystyle - 10 x + 41 = 7 x + 7$

Now we subtract $\displaystyle 41$ from each side.

$\displaystyle - 10 x = 7 x - 34$

Now we subtract 7 x $\displaystyle 7 x$ from each side.

$\displaystyle - 17 x = -34$

Now we divide by $\displaystyle -17$ on each side.

x = 2 $\displaystyle x = 2$

Now we simply plug this $\uptext{x}$ $\displaystyle \uptext{x}$ value into one of the equations to get the $\uptext{y}$ $\displaystyle \uptext{y}$ value.

$y = -10 \cdot 2 + 41$ $\displaystyle y = -10 \cdot 2 + 41$

$\displaystyle y = -20 + 41$

y = 21 $\displaystyle y = 21$

Report an Error

Example Question #7 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Where do the following equations intersect?

$\displaystyle y = - 4 x - 12$

$\displaystyle y = - 42 x + 30$

Possible Answers:

$\left( \frac{2}{21} , - \frac{312}{19} \right)$ $\displaystyle \left( \frac{2}{21} , - \frac{312}{19} \right)$

$\left( \frac{1}{9} , -28 \right)$ $\displaystyle \left( \frac{1}{9} , -28 \right)$

$\left( \frac{21}{19} , - \frac{312}{19} \right)$ $\displaystyle \left( \frac{21}{19} , - \frac{312}{19} \right)$

$\left( \frac{1}{9} , - \frac{207}{19} \right)$ $\displaystyle \left( \frac{1}{9} , - \frac{207}{19} \right)$

$\left( \frac{1}{9} , - \frac{312}{19} \right)$ $\displaystyle \left( \frac{1}{9} , - \frac{312}{19} \right)$

Correct answer:

$\left( \frac{21}{19} , - \frac{312}{19} \right)$ $\displaystyle \left( \frac{21}{19} , - \frac{312}{19} \right)$

Explanation:

To figure out where these equations intersect, we need to set them equal to each other and solve for $\uptext{x}$ $\displaystyle \uptext{x}$.

$\displaystyle - 4 x - 12 = - 42 x + 30$

Now we add $\displaystyle 12$ to each side.

$\displaystyle - 4 x = - 42 x + 42$

Now we add 42 x $\displaystyle 42 x$ to each side.

$\displaystyle 38 x = 42$

Now we divide by $\displaystyle 38$ on each side.

$x = \frac{21}{19}$ $\displaystyle x = \frac{21}{19}$

Now we simply plug this $\uptext{x}$ $\displaystyle \uptext{x}$ value into one of the equations to get the $\uptext{y}$ $\displaystyle \uptext{y}$ value.

$y = -4 \cdot \frac{21}{19} -12$ $\displaystyle y = -4 \cdot \frac{21}{19} -12$

$y = - \frac{84}{19} -12$ $\displaystyle y = - \frac{84}{19} -12$

$y = - \frac{312}{19}$ $\displaystyle y = - \frac{312}{19}$

Report an Error

View Tutors

Rachel
Certified Tutor

University of Arkansas at Little Rock, Bachelor in Arts, Mathematics.

View Tutors

Alan
Certified Tutor

Western Connecticut State University, Bachelor of Science, Mathematics Teacher Education.

View Tutors

Louis
Certified Tutor

University of California-Los Angeles, Bachelor in Arts, Film Production.

All Common Core: High School - Algebra Resources

8 Diagnostic Tests 97 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

English Tutors in Los Angeles, SSAT Tutors in Denver, Math Tutors in New York City, Reading Tutors in Washington DC, Chemistry Tutors in Phoenix, GMAT Tutors in Houston, SSAT Tutors in San Francisco-Bay Area, Algebra Tutors in Phoenix, Biology Tutors in Miami, Spanish Tutors in New York City

Popular Courses & Classes

Spanish Courses & Classes in Dallas Fort Worth, SAT Courses & Classes in Denver, ISEE Courses & Classes in New York City, ACT Courses & Classes in Atlanta, ISEE Courses & Classes in San Diego, ISEE Courses & Classes in Miami, LSAT Courses & Classes in San Francisco-Bay Area, ISEE Courses & Classes in San Francisco-Bay Area, LSAT Courses & Classes in Atlanta, GRE Courses & Classes in Chicago

Popular Test Prep

MCAT Test Prep in Miami, GRE Test Prep in Philadelphia, ISEE Test Prep in Phoenix, MCAT Test Prep in Philadelphia, ACT Test Prep in Atlanta, SSAT Test Prep in Chicago, ACT Test Prep in Dallas Fort Worth, SSAT Test Prep in Denver, LSAT Test Prep in Boston, ACT Test Prep in Los Angeles

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Common Core: High School - Algebra : Reasoning with Equations & Inequalities

Study concepts, example questions & explanations for Common Core: High School - Algebra

All Common Core: High School - Algebra Resources

Example Questions

Example Question #1 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Example Question #2 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Example Question #1 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Example Question #1 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Example Question #2 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Example Question #3 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Example Question #4 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Example Question #5 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Example Question #6 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

Example Question #7 : Use Graph Points To Approximate Solutions: Ccss.Math.Content.Hsa Rei.D.11

All Common Core: High School - Algebra Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: