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Common Core: 8th Grade Math : Grade 8

Study concepts, example questions & explanations for Common Core: 8th Grade Math

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All Common Core: 8th Grade Math Resources

7 Diagnostic Tests 75 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #92 : Solid Geometry

Give the volume of a cone whose height is 10 inches and whose base is a circle with circumference $6 \pi$ inches.

Possible Answers:

$120 \pi \textrm{ in}^{3}$

$45 \pi \textrm{ in}^{3}$

$90 \pi \textrm{ in}^{3}$

$360 \pi \textrm{ in}^{3}$

$30 \pi \textrm{ in}^{3}$

Correct answer:

$30 \pi \textrm{ in}^{3}$

Explanation:

A circle with circumference $6 \pi$ inches has as its radius

$r = \frac{C }{2\pi }=\frac{6\pi }{2\pi } = 3$ inches.

The area of the base is therefore

$B = \pi r^{2} = \pi \cdot 3^{2} = 9 \pi$ square inches.

To find the volume of the cone, substitute $B = 9 \pi , h = 10$ in the formula for the volume of a cone:

$V = \frac{1}{3} Bh = \frac{1}{3} \cdot 9 \pi \cdot 10 = 30 \pi$ cubic inches

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Example Question #1 : Cones

The height of a cone and the radius of its base are equal. The circumference of the base is $10 \pi$ inches. Give its volume.

Possible Answers:

$\frac{1,000}{3} \pi \textrm{ in}^{3}$

$\frac{125}{3} \pi \textrm{ in}^{3}$

$1,000 \textrm{ in}^{3}$

$\frac{5,000}{3} \pi \textrm{ in}^{3}$

$125 \textrm{ in}^{3}$

Correct answer:

$\frac{125}{3} \pi \textrm{ in}^{3}$

Explanation:

A circle with circumference $10 \pi$ inches has as its radius

$r = \frac{C }{2\pi }=\frac{10\pi }{2\pi } = 5$ inches.

The height is also inches, so substitute h = r = 5 in the volume formula for a cone:

$V = \frac{1}{3} \pi r ^{2}h = \frac{1}{3} \pi \cdot 5 ^{2} \cdot 5 = \frac{125}{3} \pi$ cubic inches

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Example Question #1 : Volume Of A Sphere

In terms of $\pi$ , give the volume, in cubic inches, of a spherical water tank with a diameter of 20 feet.

Possible Answers:

$307,200\pi\textrm{ in}^{3}$

$57,600 \pi\textrm{ in}^{3}$

$230,400 \pi\textrm{ in}^{3}$

$2,304,000 \pi \textrm{ in}^{3}$

$18,432,000\pi\textrm{ in}^{3}$

Correct answer:

$2,304,000 \pi \textrm{ in}^{3}$

Explanation:

20 feet = $20 \times 12 = 240$ inches, the diameter of the tank; half of this, or 120 inches, is the radius. Set r = 120 , substitute in the volume formula, and solve for :

$V = \frac{4}{3} \pi r^{3}$

$V = \frac{4}{3} \pi \cdot 120^{3}$

$V = \frac{4}{3} \pi \cdot 1,728,000$

$V = 2,304,000 \pi$ cubic inches

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Example Question #2 : Volume Of A Sphere

A sphere has diameter 3 meters. Give its volume in cubic centimeters (leave in terms of $\pi$ ).

Possible Answers:

$4,500,000\pi \textrm{ cm}^{3}$

$1,125,000\pi \textrm{ cm}^{3}$

$36,000,000\pi \textrm{ cm}^{3}$

$3,375,000\pi \textrm{ cm}^{3}$

$27,000,000\pi \textrm{ cm}^{3}$

Correct answer:

$4,500,000\pi \textrm{ cm}^{3}$

Explanation:

The diameter of 3 meters is equal to $3 \times 100 = 300$ centimeters; the radius is half this, or 150 centimeters. Substitute r = 150 in the volume formula:

$V= \frac{4}{3} \pi r^{3}$

$V= \frac{4}{3} \cdot \pi \cdot 150^{3}$

$V= \frac{4}{3} \cdot 150 \cdot 150 \cdot 150\cdot \pi$

$V= 4,500,000\pi$ cubic centimeters

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Example Question #12 : Volume Of A Three Dimensional Figure

A cone has a radius of inches and a height of inches. Find the volume of the cone.

Possible Answers:

$36\pi\:in^3$

$12\pi\:in^3$

$24\pi\:in^3$

$108\pi\:in^3$

Correct answer:

$36\pi\:in^3$

Explanation:

The volume of a cone is given by the formula:

$\text{Volume}=\frac{1}{3}\pi r^2h$

Now, plug in the values of the radius and height to find the volume of the given cone.

$\text{Volume}=\frac{1}{3}\pi\times3^2\times12=\frac{1}{3}\pi\times9\times12=\frac{108}{3}\pi=36\pi\:in^3$

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Example Question #22 : Know And Use The Formulas For The Volumes Of Cones, Cylinders, And Spheres: Ccss.Math.Content.8.G.C.9

Calculate the volume of the cylinder provided. Round the answer to the nearest hundredth.

Possible Answers:

$907.45\textup{ in}^3$

$933.24\textup{ in}^3$

$913.33\textup{ in}^3$

$904.78\textup{ in}^3$

$924.84\textup{ in}^3$

Correct answer:

$904.78\textup{ in}^3$

Explanation:

In order to solve this problem, we need to recall the formula used to calculate the volume of a cylinder:

$V=\pi r^2h$

Now that we have this formula, we can substitute in the given values and solve:

$V=\pi6^2(8)$

$V=\pi36(8)$

$V=\pi288$

$V=904.78\textup{ in}^3$

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Example Question #501 : Grade 8

Calculate the volume of the cone provided. Round the answer to the nearest hundredth.

Possible Answers:

$364.16\textup{ in}^3$

$300\textup{ in}^3$

$314.16\textup{ in}^3$

$320.14\textup{ in}^3$

$315\textup{ in}^3$

Correct answer:

$314.16\textup{ in}^3$

Explanation:

In order to solve this problem, we need to recall the formula used to calculate the volume of a cone:

$V=\pi r^2\left ( \frac{h}{3} \right )$

Now that we have this formula, we can substitute in the given values and solve:

$V=\pi5^2\left ( \frac{12}{3} \right )$

$V=\pi25(4)$

$V=\pi100$

$V=314.16\textup{ in}^3$

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Example Question #191 : Geometry

Calculate the volume of the cone provided. Round the answer to the nearest hundredth.

Possible Answers:

$155.32\textup{ in}^3$

$162.38\textup{ in}^3$

$142.80\textup{ in}^3$

$150.80\textup{ in}^3$

$160.21\textup{ in}^3$

Correct answer:

$150.80\textup{ in}^3$

Explanation:

In order to solve this problem, we need to recall the formula used to calculate the volume of a cone:

$V=\pi r^2\left ( \frac{h}{3} \right )$

Now that we have this formula, we can substitute in the given values and solve:

$V=\pi4^2\left ( \frac{9}{3} \right )$

$V=\pi16(3)$

$V=\pi48$

$V=150.80\textup{ in}^3$

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Example Question #501 : Grade 8

Calculate the volume of the cone provided. Round the answer to the nearest hundredth.

Possible Answers:

$58.45\textup{ in}^3$

$56.55\textup{ in}^3$

$60.23\textup{ in}^3$

$64.62\textup{ in}^3$

$62.22\textup{ in}^3$

Correct answer:

$56.55\textup{ in}^3$

Explanation:

In order to solve this problem, we need to recall the formula used to calculate the volume of a cone:

$V=\pi r^2\left ( \frac{h}{3} \right )$

Now that we have this formula, we can substitute in the given values and solve:

$V=\pi3^2\left ( \frac{6}{3} \right )$

$V=\pi9(2)$

$V=\pi18$

$V=56.55\textup{ in}^3$

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Example Question #502 : Grade 8

Calculate the volume of the cone provided. Round the answer to the nearest hundredth.

Possible Answers:

$1\textup,887.55\textup{ in}^3$

$1\textup,885.96\textup{ in}^3$

$1\textup,884.96\textup{ in}^3$

$1\textup,884.65\textup{ in}^3$

$1\textup,885\textup{ in}^3$

Correct answer:

$1\textup,885.96\textup{ in}^3$

Explanation:

In order to solve this problem, we need to recall the formula used to calculate the volume of a cone:

$V=\pi r^2\left ( \frac{h}{3} \right )$

Now that we have this formula, we can substitute in the given values and solve:

$V=\pi10^2\left ( \frac{18}{3} \right )$

$V=\pi100(6)$

$V=\pi600$

$V=1\textup,884.96\textup{ in}^3$

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Common Core: 8th Grade Math : Grade 8

Study concepts, example questions & explanations for Common Core: 8th Grade Math

All Common Core: 8th Grade Math Resources

Example Questions

Example Question #92 : Solid Geometry

Example Question #1 : Cones

Example Question #1 : Volume Of A Sphere

Example Question #2 : Volume Of A Sphere

Example Question #12 : Volume Of A Three Dimensional Figure

Example Question #22 : Know And Use The Formulas For The Volumes Of Cones, Cylinders, And Spheres: Ccss.Math.Content.8.G.C.9

Example Question #501 : Grade 8

Example Question #191 : Geometry

Example Question #501 : Grade 8

Example Question #502 : Grade 8

All Common Core: 8th Grade Math Resources

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