To solve this problem, we first need to know what number  represents:

We are looking for a point on the number line that is on . Based on the number line provided, point G is the best representation of 

To solve this problem, we can think of perfect squares around 

This means that  has to be between  and  on the number line, but closer to  because  is closer to  than . Based on the number line provided, point H is the best representation of 

To solve this problem, we can think of perfect squares around 

This means that  has to be between  and  on the number line, but closer to  because  is closer to  than . Based on the number line provided, point I is the best representation of 

To solve this problem, we can think of perfect squares around 

This means that  has to be between  and  on the number line. Based on the number line provided, point J is the best representation of 

To solve this problem, we first need to know what number  represents:

We are looking for a point on the number line that is on . Based on the number line provided, point K is the best representation of 

To solve this problem, we first need to know what number the symbol  represents:

We are looking for a point on the number line that is between  and , but much closer to . Based on the number line provided, point C is the best representation of 

Begin by distributing the exponent through the parentheses. The power rule dictates that an exponent raised to another exponent means that the two exponents are multiplied:

Any negative exponents can be converted to positive exponents in the denominator of a fraction:

The like terms can be simplified by subtracting the power of the denominator from the power of the numerator:

Use the power rule to distribute the exponent:

To simplify this, we will need to use the power rule and order of operations.

Evaluate the first term.  This will be done in two ways to show that the power rule will work for exponents outside of the parenthesis for a single term.

For the second term, we cannot distribute  and  with the exponent  outside the parentheses because it's not a single term.  Instead, we must evaluate the terms inside the parentheses first.

 Evaluate the second term.

Square the value inside the parentheses.

Subtract the value of the second term with the first term.

Which of the following is equivalent to the expression ?

We can rewrite the given expression by distributing the exponent on the outside.

Now, this may look a little messier, but we need to recall that when we distribute an exponent through parentheses as we are trying to do above, we need to multiple the exponent on the inside by the number on the outside. 

In a general sense it looks like this:

For our specific problem, it looks like this: