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Common Core: 7th Grade Math : Divide Integers: CCSS.Math.Content.7.NS.A.2b

Study concepts, example questions & explanations for Common Core: 7th Grade Math

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All Common Core: 7th Grade Math Resources

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Example Questions

Example Question #441 : Grade 7

Solve:

$-33\div-11$ $\displaystyle -33\div-11$

Possible Answers:

$\displaystyle -22$

$\displaystyle -3$

$\displaystyle 44$

$\displaystyle 22$

$\displaystyle 3$

Correct answer:

$\displaystyle 3$

Explanation:

We know the following information:

$33\div11=3$ $\displaystyle 33\div11=3$

In this particular case, do the negative numbers change our answer? . There are a couple of rules that we need to remember when multiplying with negative numbers:

A negative number divided by a positive number will always equal a negative number, and a positive number divided by a negative number will always equal a negative number.
A negative number divided by a negative number will always equal a positive number

Thus,

$-33\div-11=3$ $\displaystyle -33\div-11=3$

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Example Question #442 : Grade 7

Solve:

$14\div-7$ $\displaystyle 14\div-7$

Possible Answers:

$\displaystyle -7$

$\displaystyle -2$

$\displaystyle 7$

$\displaystyle 21$

$\displaystyle 2$

Correct answer:

$\displaystyle -2$

Explanation:

We know the following information:

$14\div7=2$ $\displaystyle 14\div7=2$

However, the $\displaystyle -7$ changes our answer, in this particular case. There are a couple of rules that we need to remember when multiplying with negative numbers:

A negative number divided by a positive number will always equal a negative number, and a positive number divided by a negative number will always equal a negative number.
A negative number divided by a negative number will always equal a positive number

Thus,

$14\div-7=-2$ $\displaystyle 14\div-7=-2$

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Example Question #23 : Divide Integers: Ccss.Math.Content.7.Ns.A.2b

Solve:

$21\div-7$ $\displaystyle 21\div-7$

Possible Answers:

$\displaystyle 28$

$\displaystyle 3$

$\displaystyle 14$

$\displaystyle -3$

$\displaystyle -28$

Correct answer:

$\displaystyle -3$

Explanation:

We know the following information:

$21\div7=3$ $\displaystyle 21\div7=3$

However, the $\displaystyle -7$ changes our answer, in this particular case. There are a couple of rules that we need to remember when multiplying with negative numbers:

A negative number divided by a positive number will always equal a negative number, and a positive number divided by a negative number will always equal a negative number.
A negative number divided by a negative number will always equal a positive number

Thus,

$21\div-7=-3$ $\displaystyle 21\div-7=-3$

Report an Error

Example Question #24 : Divide Integers: Ccss.Math.Content.7.Ns.A.2b

Solve:

$28\div-7$ $\displaystyle 28\div-7$

Possible Answers:

$\displaystyle -21$

$\displaystyle 21$

$\displaystyle 35$

$\displaystyle 4$

$\displaystyle -4$

Correct answer:

$\displaystyle -4$

Explanation:

We know the following information:

$28\div7=4$ $\displaystyle 28\div7=4$

However, the $\displaystyle -7$ changes our answer, in this particular case. There are a couple of rules that we need to remember when multiplying with negative numbers:

A negative number divided by a positive number will always equal a negative number, and a positive number divided by a negative number will always equal a negative number.
A negative number divided by a negative number will always equal a positive number

Thus,

$28\div-7=-4$ $\displaystyle 28\div-7=-4$

Report an Error

Example Question #25 : Divide Integers: Ccss.Math.Content.7.Ns.A.2b

Solve:

$35\div-7$ $\displaystyle 35\div-7$

Possible Answers:

$\displaystyle 42$

$\displaystyle 28$

$\displaystyle -28$

$\displaystyle 5$

$\displaystyle -5$

Correct answer:

$\displaystyle -5$

Explanation:

We know the following information:

$35\div7=5$ $\displaystyle 35\div7=5$

However, the $\displaystyle -7$ changes our answer, in this particular case. There are a couple of rules that we need to remember when multiplying with negative numbers:

A negative number divided by a positive number will always equal a negative number, and a positive number divided by a negative number will always equal a negative number.
A negative number divided by a negative number will always equal a positive number

Thus,

$35\div-7=-5$ $\displaystyle 35\div-7=-5$

Report an Error

Example Question #26 : Divide Integers: Ccss.Math.Content.7.Ns.A.2b

Solve:

$15\div-5$ $\displaystyle 15\div-5$

Possible Answers:

$\displaystyle 20$

$\displaystyle -10$

$\displaystyle -3$

$\displaystyle 10$

$\displaystyle 3$

Correct answer:

$\displaystyle -3$

Explanation:

We know the following information:

$15\div5=3$ $\displaystyle 15\div5=3$

However, the $\displaystyle -5$ changes our answer, in this particular case. There are a couple of rules that we need to remember when multiplying with negative numbers:

A negative number divided by a positive number will always equal a negative number, and a positive number divided by a negative number will always equal a negative number.
A negative number divided by a negative number will always equal a positive number

Thus,

$15\div-5=-3$ $\displaystyle 15\div-5=-3$

Report an Error

Example Question #21 : Divide Integers: Ccss.Math.Content.7.Ns.A.2b

Solve:

$20\div-5$ $\displaystyle 20\div-5$

Possible Answers:

$\displaystyle 25$

$\displaystyle 4$

$\displaystyle -4$

$\displaystyle -25$

$\displaystyle 15$

Correct answer:

$\displaystyle -4$

Explanation:

We know the following information:

$20\div5=4$ $\displaystyle 20\div5=4$

However, the $\displaystyle -5$ changes our answer, in this particular case. There are a couple of rules that we need to remember when multiplying with negative numbers:

A negative number divided by a positive number will always equal a negative number, and a positive number divided by a negative number will always equal a negative number.
A negative number divided by a negative number will always equal a positive number

Thus,

$20\div-5=-4$ $\displaystyle 20\div-5=-4$

Report an Error

Example Question #28 : Divide Integers: Ccss.Math.Content.7.Ns.A.2b

Solve:

$25\div-5$ $\displaystyle 25\div-5$

Possible Answers:

$\displaystyle 30$

$\displaystyle 20$

$\displaystyle -20$

$\displaystyle -5$

$\displaystyle 5$

Correct answer:

$\displaystyle -5$

Explanation:

We know the following information:

$25\div5=5$ $\displaystyle 25\div5=5$

However, the $\displaystyle -5$ changes our answer, in this particular case. There are a couple of rules that we need to remember when multiplying with negative numbers:

A negative number divided by a positive number will always equal a negative number, and a positive number divided by a negative number will always equal a negative number.
A negative number divided by a negative number will always equal a positive number

Thus,

$25\div-5=-5$ $\displaystyle 25\div-5=-5$

Report an Error

Example Question #29 : Divide Integers: Ccss.Math.Content.7.Ns.A.2b

Solve:

$30\div-5$ $\displaystyle 30\div-5$

Possible Answers:

$\displaystyle -35$

$\displaystyle -6$

$\displaystyle -25$

$\displaystyle 35$

$\displaystyle 25$

Correct answer:

$\displaystyle -6$

Explanation:

We know the following information:

$30\div5=6$ $\displaystyle 30\div5=6$

However, the $\displaystyle -5$ changes our answer, in this particular case. There are a couple of rules that we need to remember when multiplying with negative numbers:

A negative number divided by a positive number will always equal a negative number, and a positive number divided by a negative number will always equal a negative number.
A negative number divided by a negative number will always equal a positive number

Thus,

$30\div-5=-6$ $\displaystyle 30\div-5=-6$

Report an Error

Example Question #30 : Divide Integers: Ccss.Math.Content.7.Ns.A.2b

Solve:

$8\div-2$ $\displaystyle 8\div-2$

Possible Answers:

$\displaystyle -6$

$\displaystyle 10$

$\displaystyle 4$

$\displaystyle -10$

$\displaystyle -4$

Correct answer:

$\displaystyle -4$

Explanation:

We know the following information:

$8\div2=4$ $\displaystyle 8\div2=4$

However, the $\displaystyle -2$ changes our answer, in this particular case. There are a couple of rules that we need to remember when multiplying with negative numbers:

A negative number divided by a positive number will always equal a negative number, and a positive number divided by a negative number will always equal a negative number.
A negative number divided by a negative number will always equal a positive number

Thus,

$8\div-2=-4$ $\displaystyle 8\div-2=-4$

Report an Error

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Common Core: 7th Grade Math : Divide Integers: CCSS.Math.Content.7.NS.A.2b

Study concepts, example questions & explanations for Common Core: 7th Grade Math

All Common Core: 7th Grade Math Resources

Example Questions

Example Question #441 : Grade 7

Example Question #442 : Grade 7

Example Question #23 : Divide Integers: Ccss.Math.Content.7.Ns.A.2b

Example Question #24 : Divide Integers: Ccss.Math.Content.7.Ns.A.2b

Example Question #25 : Divide Integers: Ccss.Math.Content.7.Ns.A.2b

Example Question #26 : Divide Integers: Ccss.Math.Content.7.Ns.A.2b

Example Question #21 : Divide Integers: Ccss.Math.Content.7.Ns.A.2b

Example Question #28 : Divide Integers: Ccss.Math.Content.7.Ns.A.2b

Example Question #29 : Divide Integers: Ccss.Math.Content.7.Ns.A.2b

Example Question #30 : Divide Integers: Ccss.Math.Content.7.Ns.A.2b

All Common Core: 7th Grade Math Resources

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