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Common Core: 6th Grade Math : Ratios & Proportional Relationships

Study concepts, example questions & explanations for Common Core: 6th Grade Math

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All Common Core: 6th Grade Math Resources

6 Diagnostic Tests 186 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

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Example Question #57 : How To Find A Ratio

At a car production company, manufacturers place tires and transmission on every car in the production line. A manager orders tires, how many transmissions should he order?

Possible Answers:

$2\ \text{transmissions}$

$3\ \text{transmissions}$

$4\ \text{transmissions}$

$1\ \text{transmission}$

$5\ \text{transmissions}$

Correct answer:

$2\ \text{transmissions}$

Explanation:

In order to solve this problem we must make a table of ratios. In the question we are given the base ratio:

$4\ \text{tires}:1\ \text{transmission}$

We can use this ratio to make a table.

Tires

According to the table, the manager should order $2\ \text{transmissions}$ .

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Example Question #58 : How To Find A Ratio

At a car production company, manufacturers place tires and transmission on every car in the production line. A manager orders tires, how many transmissions should he order?

Possible Answers:

$4\ \text{transmissions}$

$3\ \text{transmissions}$

$6\ \text{transmissions}$

$5\ \text{transmissions}$

$7\ \text{transmissions}$

Correct answer:

$5\ \text{transmissions}$

Explanation:

In order to solve this problem we must make a table of ratios. In the question we are given the base ratio:

$4\ \text{tires}:1\ \text{transmission}$

We can use this ratio to make a table.

Tires

According to the table, the manager should order $5\ \text{transmissions}$ .

Report an Error

Example Question #41 : Ratios & Proportional Relationships

Traffic from the suburbs and farms into a city typically follows an observable pattern. On any given morning there are cars for every trucks. On one particular busy morning there are trucks. How many cars are sitting in traffic?

Possible Answers:

$21\ \text{cars}$

$16\ \text{cars}$

$14\ \text{cars}$

$13\ \text{cars}$

$12\ \text{cars}$

Correct answer:

$14\ \text{cars}$

Explanation:

In order to solve this problem we must make a table of ratios. In the question we are given the base ratio:

$7\ \text{cars}:3\ \text{trucks}$

We can use this ratio to make a table.

Cars

According to the table, there are $14\ \text{cars}$ .

Report an Error

Example Question #61 : Ratio And Proportion

Possible Answers:

$28\ \text{cars}$

$24\ \text{cars}$

$26\ \text{cars}$

$30\ \text{cars}$

$32\ \text{cars}$

Correct answer:

$28\ \text{cars}$

Explanation:

In order to solve this problem we must make a table of ratios. In the question we are given the base ratio:

$7\ \text{cars}:3\ \text{trucks}$

We can use this ratio to make a table.

Cars

According to the table, there are $28\ \text{cars}$ .

Report an Error

Example Question #21 : Make Tables Of Equivalent Ratios, Find Missing Values, And Plot Values On A Coordinate Plane: Ccss.Math.Content.6.Rp.A.3a

Possible Answers:

$40\ \text{cars}$

$25\ \text{cars}$

$35\ \text{cars}$

$30\ \text{cars}$

$45\ \text{cars}$

Correct answer:

$35\ \text{cars}$

Explanation:

In order to solve this problem we must make a table of ratios. In the question we are given the base ratio:

$7\ \text{cars}:3\ \text{trucks}$

We can use this ratio to make a table.

Cars

According to the table, there are $35\ \text{cars}$ .

Report an Error

Example Question #44 : Ratios & Proportional Relationships

Possible Answers:

$49\ \text{cars}$

$35\ \text{cars}$

$42\ \text{cars}$

$28\ \text{cars}$

$41\ \text{cars}$

Correct answer:

$42\ \text{cars}$

Explanation:

In order to solve this problem we must make a table of ratios. In the question we are given the base ratio:

$7\ \text{cars}:3\ \text{trucks}$

We can use this ratio to make a table.

Cars

According to the table, there are $42\ \text{cars}$ .

Report an Error

Example Question #61 : Ratio And Proportion

Possible Answers:

$29\ \text{cars}$

$28\ \text{cars}$

$21\ \text{cars}$

$24\ \text{cars}$

$22\ \text{cars}$

Correct answer:

$21\ \text{cars}$

Explanation:

In order to solve this problem we must make a table of ratios. In the question we are given the base ratio:

$7\ \text{cars}:3\ \text{trucks}$

We can use this ratio to make a table.

Cars

According to the table, there are $21\ \text{cars}$ .

Report an Error

Example Question #21 : Make Tables Of Equivalent Ratios, Find Missing Values, And Plot Values On A Coordinate Plane: Ccss.Math.Content.6.Rp.A.3a

Traffic from the suburbs into a city typically follows an observable pattern. On any given morning there are cars on the road for every trucks on the road. On Monday morning there are trucks on the road. How many cars are on the road?

Possible Answers:

$59\ \text{cars}$

$51\ \text{cars}$

$28\ \text{cars}$

$49\ \text{cars}$

$56\ \text{cars}$

Correct answer:

$49\ \text{cars}$

Explanation:

In order to solve this problem we must make a table of ratios. In the question we are given the base ratio:

$7\ \text{cars}:3\ \text{trucks}$

We can use this ratio to make a table.

Cars

According to the table, there are $49\ \text{cars}$ .

Report an Error

Example Question #1 : Solve Unit Rate Problems: Ccss.Math.Content.6.Rp.A.3b

At a local market, farmers trade produce to obtain a more diverse crop. A farmer will trade turnips for ears of corn. If a man has ears of corn, then how many turnips can he get?

Possible Answers:

$43\ \text{turnips}$

$39\ \text{turnips}$

$22\ \text{turnips}$

$94\ \text{turnips}$

$93\ \text{turnips}$

Correct answer:

$39\ \text{turnips}$

Explanation:

Ratios can be written in the following format:

$A:B\rightarrow \frac{A}{B}$

Using this format, substitute the given information to create a ratio.

$3\ \text{corn}: 13\ \text{turnips}$

Rewrite the ratio as a fraction.

$3\ \text{corn}: 13\ \text{turnips}\rightarrow \frac{3\ \text{corn}}{13\ \text{turnips}}$

We know that the farmer has ears of corn. Create a ratio with the variable that represents how many turnips he can get.

$\frac{9\ \text{corn}}{T}$

Create a proportion using the two ratios.

$\frac{3\ \text{corn}}{13\ \text{turnips}}=\frac{9\ \text{corn}}{T}$

Cross multiply and solve for .

$9\ \text{corn}\times 13\ \text{turnips}=3\ \text{corn}\times T$

Simplify.

3T=117

Divide both sides of the equation by .

$\frac{3T}{3}=\frac{117}{3}$

Solve.

T=39

The farmer can get $39\ \text{turnips}$ .

Report an Error

Example Question #1 : Solve Unit Rate Problems: Ccss.Math.Content.6.Rp.A.3b

At a local market, farmers trade produce to obtain a more diverse crop. A farmer will trade turnips for ears of corn. If a man has ears of corn, then how many turnips can he get?

Possible Answers:

$87\ \text{turnips}$

$127\ \text{turnips}$

$111\ \text{turnips}$

$117\ \text{turnips}$

$171\ \text{turnips}$

Correct answer:

$117\ \text{turnips}$

Explanation:

Ratios can be written in the following format:

$A:B\rightarrow \frac{A}{B}$

Using this format, substitute the given information to create a ratio.

$3\ \text{corn}: 13\ \text{turnips}$

Rewrite the ratio as a fraction.

$3\ \text{corn}: 13\ \text{turnips}\rightarrow \frac{3\ \text{corn}}{13\ \text{turnips}}$

We know that the farmer has ears of corn. Create a ratio with the variable that represents how many turnips he can get.

$\frac{27\ \text{corn}}{T}$

Create a proportion using the two ratios.

$\frac{3\ \text{corn}}{13\ \text{turnips}}=\frac{27\ \text{corn}}{T}$

Cross multiply and solve for .

$27\ \text{corn}\times 13\ \text{turnips}=3\ \text{corn}\times T$

Simplify.

3T=351

Divide both sides of the equation by .

$\frac{3T}{3}=\frac{351}{3}$

Solve.

T=117

The farmer can get $117\ \text{turnips}$ .

Report an Error

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Common Core: 6th Grade Math : Ratios & Proportional Relationships

Study concepts, example questions & explanations for Common Core: 6th Grade Math

All Common Core: 6th Grade Math Resources

Example Questions

Example Question #57 : How To Find A Ratio

Example Question #58 : How To Find A Ratio

Example Question #41 : Ratios & Proportional Relationships

Example Question #61 : Ratio And Proportion

Example Question #21 : Make Tables Of Equivalent Ratios, Find Missing Values, And Plot Values On A Coordinate Plane: Ccss.Math.Content.6.Rp.A.3a

Example Question #44 : Ratios & Proportional Relationships

Example Question #61 : Ratio And Proportion

Example Question #21 : Make Tables Of Equivalent Ratios, Find Missing Values, And Plot Values On A Coordinate Plane: Ccss.Math.Content.6.Rp.A.3a

Example Question #1 : Solve Unit Rate Problems: Ccss.Math.Content.6.Rp.A.3b

Example Question #1 : Solve Unit Rate Problems: Ccss.Math.Content.6.Rp.A.3b

All Common Core: 6th Grade Math Resources

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