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Common Core: 6th Grade Math : Grade 6

Study concepts, example questions & explanations for Common Core: 6th Grade Math

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All Common Core: 6th Grade Math Resources

6 Diagnostic Tests 186 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #11 : The Number System

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 54\\ 2{\overline{\smash{)}108}}\\ -\ 10 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{8\ \ }\\ -\ \ \ 8\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$2\times 64$

$2\times 54$

$2\times 46$

$4\times 44$

$2\times 56$

Correct answer:

$2\times 54$

Explanation:

The computation shows that $108\div2=54$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 54}\\ {\color{Green} 2}{\overline{\smash{)}108}}\\ -\ 10 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 8\ \ }\\ -\ \ \ 8\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$2\times54=108+0$

Simplify.

$2\times54=108$

The correct answer is $2\times 54$

Report an Error

Example Question #6 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 61\\ 2{\overline{\smash{)}122}}\\ -\ 12 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{2\ \ }\\ -\ \ \ 2\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$2\times 76$

$2\times 68$

$2\times 63$

$2\times 61$

$3\times 36$

Correct answer:

$2\times 61$

Explanation:

The computation shows that $122\div2=61$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 61}\\ {\color{Green} 2}{\overline{\smash{)}122}}\\ -\ 12 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 2\ \ }\\ -\ \ \ 2\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$2\times61=122+0$

Simplify.

$2\times61=122$

The correct answer is $2\times 61$

Report an Error

Example Question #7 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 51\\ 3{\overline{\smash{)}153}}\\ -\ 15 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{3\ \ }\\ -\ \ \ 3\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$3\times 36$

$3\times 35$

$3\times 61$

$3\times 53$

$3\times 51$

Correct answer:

$3\times 51$

Explanation:

The computation shows that $153\div3=61$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 51}\\ {\color{Green} 3}{\overline{\smash{)}153}}\\ -\ 15 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 3\ \ }\\ -\ \ \ 3\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$3\times51=153+0$

Simplify.

$3\times51=153$

The correct answer is $3\times 51$

Report an Error

Example Question #3 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 61\\ 3{\overline{\smash{)}183}}\\ -\ 18 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{3\ \ }\\ -\ \ \ 3\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$3\times 42$

$3\times 68$

$3\times 61$

$3\times 63$

$3\times 36$

Correct answer:

$3\times 61$

Explanation:

The computation shows that $183\div3=61$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 61}\\ {\color{Green} 3}{\overline{\smash{)}183}}\\ -\ 18 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 3\ \ }\\ -\ \ \ 3\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$3\times61=183+0$

Simplify.

$3\times61=183$

The correct answer is $3\times 61$

Report an Error

Example Question #9 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 63\\ 3{\overline{\smash{)}189}}\\ -\ 18 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{9\ \ }\\ -\ \ \ 9\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$3\times 63$

$3\times 72$

$3\times 68$

$3\times 69$

$3\times 83$

Correct answer:

$3\times 63$

Explanation:

The computation shows that $189\div3=63$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 63}\\ {\color{Green} 3}{\overline{\smash{)}189}}\\ -\ 18 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 9\ \ }\\ -\ \ \ 9\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$3\times63=189+0$

Simplify.

$3\times63=189$

The correct answer is $3\times 63$

Report an Error

Example Question #10 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 91\\ 3{\overline{\smash{)}273}}\\ -\ 27 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{3\ \ }\\ -\ \ \ 3\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$3\times 93$

$3\times 91$

$3\times 97$

$3\times 79$

$3\times 89$

Correct answer:

$3\times 91$

Explanation:

The computation shows that $273\div3=91$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 91}\\ {\color{Green} 3}{\overline{\smash{)}273}}\\ -\ 27 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 3\ \ }\\ -\ \ \ 3\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$3\times91=273+0$

Simplify.

$3\times91=273$

The correct answer is $3\times 91$

Report an Error

Example Question #3451 : Operations

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 21\\ 9{\overline{\smash{)}189}}\\ -\ 18 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{9\ \ }\\ -\ \ \ 9\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$9\times 21$

$9\times 18$

$9\times 32$

$9\times 27$

$9\times 23$

Correct answer:

$9\times 21$

Explanation:

The computation shows that $189\div9=21$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 21}\\ {\color{Green} 9}{\overline{\smash{)}189}}\\ -\ 18 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 9\ \ }\\ -\ \ \ 9\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$9\times21=189+0$

Simplify.

$9\times21=189$

The correct answer is $9\times 21$

Report an Error

Example Question #3452 : Operations

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 31\\ 9{\overline{\smash{)}279}}\\ -\ 27 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{9\ \ }\\ -\ \ \ 9\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$9\times 36$

$9\times 93$

$9\times 31$

$9\times 33$

$3\times 93$

Correct answer:

$9\times 31$

Explanation:

The computation shows that $279\div9=31$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 31}\\ {\color{Green} 9}{\overline{\smash{)}279}}\\ -\ 27 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 9\ \ }\\ -\ \ \ 9\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$9\times31=279+0$

Simplify.

$9\times31=279$

The correct answer is $9\times 31$

Report an Error

Example Question #3451 : Operations

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 21\\ 7{\overline{\smash{)}147}}\\ -\ 14 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{7\ \ }\\ -\ \ \ 7\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$7\times 41$

$7\times 31$

$7\times 21$

$7\times 28$

$7\times 17$

Correct answer:

$7\times 21$

Explanation:

The computation shows that $147\div7=21$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 21}\\ {\color{Green} 7}{\overline{\smash{)}147}}\\ -\ 14 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 7\ \ }\\ -\ \ \ 7\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$7\times21=147+0$

Simplify.

$7\times21=147$

The correct answer is $7\times 21$

Report an Error

Example Question #21 : The Number System

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 31\\ 7{\overline{\smash{)}217}}\\ -\ 21 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{7\ \ }\\ -\ \ \ 7\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$7\times 28$

$7\times 23$

$7\times 21$

$7\times 31$

$7\times 34$

Correct answer:

$7\times 31$

Explanation:

The computation shows that $217\div7=31$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 31}\\ {\color{Green} 7}{\overline{\smash{)}217}}\\ -\ 21 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 7\ \ }\\ -\ \ \ 7\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$7\times31=217+0$

Simplify.

$7\times31=217$

The correct answer is $7\times 31$

Report an Error

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All Common Core: 6th Grade Math Resources

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Common Core: 6th Grade Math : Grade 6

Study concepts, example questions & explanations for Common Core: 6th Grade Math

All Common Core: 6th Grade Math Resources

Example Questions

Example Question #11 : The Number System

Example Question #6 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Example Question #7 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Example Question #3 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Example Question #9 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Example Question #10 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Example Question #3451 : Operations

Example Question #3452 : Operations

Example Question #3451 : Operations

Example Question #21 : The Number System

All Common Core: 6th Grade Math Resources

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