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Common Core: 6th Grade Math : Grade 6

Study concepts, example questions & explanations for Common Core: 6th Grade Math

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All Common Core: 6th Grade Math Resources

6 Diagnostic Tests 186 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #3521 : Operations

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 41\\ 4{\overline{\smash{)}164}}\\ -\ 16 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$4\times 12$

$4\times 51$

$4\times 41$

$4\times 16$

$4\times 31$

Correct answer:

$4\times 41$

Explanation:

The computation shows that $164\div4=41$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 41}\\ {\color{Green} 4}{\overline{\smash{)}164}}\\ -\ 16 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$4\times41=164+0$

Simplify.

$4\times41=164$

The correct answer is $4\times 41$

Report an Error

Example Question #3522 : Operations

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 51\\ 4{\overline{\smash{)}204}}\\ -\ 20 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$4\times 41$

$4\times 20$

$4\times 61$

$4\times 51$

$4\times 24$

Correct answer:

$4\times 51$

Explanation:

The computation shows that $204\div4=51$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 51}\\ {\color{Green} 4}{\overline{\smash{)}204}}\\ -\ 20 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$4\times51=204+0$

Simplify.

$4\times51=204$

The correct answer is $4\times 51$

Report an Error

Example Question #24 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 61\\ 4{\overline{\smash{)}244}}\\ -\ 24 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$4\times 42$

$4\times 61$

$4\times 24$

$4\times 31$

$4\times 71$

Correct answer:

$4\times 61$

Explanation:

The computation shows that $254\div4=61$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 61}\\ {\color{Green} 4}{\overline{\smash{)}244}}\\ -\ 24 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$4\times61=244+0$

Simplify.

$4\times61=204$

The correct answer is $4\times 61$

Report an Error

Example Question #25 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 71\\ 4{\overline{\smash{)}284}}\\ -\ 28 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$4\times 81$

$4\times 61$

$4\times 91$

$4\times 71$

$4\times 82$

Correct answer:

$4\times 71$

Explanation:

The computation shows that $284\div4=71$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 71}\\ {\color{Green} 4}{\overline{\smash{)}284}}\\ -\ 28 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$4\times71=284+0$

Simplify.

$4\times71=284$

The correct answer is $4\times 71$

Report an Error

Example Question #26 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 81\\ 4{\overline{\smash{)}324}}\\ -\ 32 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$4\times 32$

$4\times 81$

$4\times 91$

$4\times 82$

$4\times 101$

Correct answer:

$4\times 81$

Explanation:

The computation shows that $324\div4=81$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 81}\\ {\color{Green} 4}{\overline{\smash{)}324}}\\ -\ 32 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$4\times81=324+0$

Simplify.

$4\times81=324$

The correct answer is $4\times 81$

Report an Error

Example Question #27 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 91\\ 4{\overline{\smash{)}364}}\\ -\ 36 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$4\times 36$

$4\times 91$

$4\times 101$

$4\times 81$

$4\times 63$

Correct answer:

$4\times 91$

Explanation:

The computation shows that $364\div4=91$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 91}\\ {\color{Green} 4}{\overline{\smash{)}364}}\\ -\ 36 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$4\times91=364+0$

Simplify.

$4\times91=364$

The correct answer is $4\times 91$

Report an Error

Example Question #3541 : Operations

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 31\\ 5{\overline{\smash{)}155}}\\ -\ 15 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$5\times 51$

$5\times 21$

$5\times 31$

$5\times 41$

$5\times 15$

Correct answer:

$5\times 31$

Explanation:

The computation shows that $155\div5=31$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 31}\\ {\color{Green} 5}{\overline{\smash{)}155}}\\ -\ 15 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$5\times31=155+0$

Simplify.

$5\times31=155$

The correct answer is $5\times 31$

Report an Error

Example Question #3542 : Operations

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 41\\ 5{\overline{\smash{)}205}}\\ -\ 20 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$5\times 31$

$5\times 62$

$5\times 41$

$5\times 61$

$5\times 20$

Correct answer:

$5\times 41$

Explanation:

The computation shows that $205\div5=41$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 41}\\ {\color{Green} 5}{\overline{\smash{)}205}}\\ -\ 20 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$5\times41=205+0$

Simplify.

$5\times41=205$

The correct answer is $5\times 41$

Report an Error

Example Question #3543 : Operations

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 51\\ 5{\overline{\smash{)}255}}\\ -\ 25 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$5\times 52$

$5\times 51$

$5\times 31$

$5\times 25$

$5\times 71$

Correct answer:

$5\times 51$

Explanation:

The computation shows that $255\div5=51$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 51}\\ {\color{Green} 5}{\overline{\smash{)}255}}\\ -\ 25 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$5\times51=255+0$

Simplify.

$5\times51=255$

The correct answer is $5\times 51$

Report an Error

Example Question #3544 : Operations

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 61\\ 5{\overline{\smash{)}305}}\\ -\ 30 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$5\times 81$

$5\times 61$

$5\times 30$

$5\times 31$

$5\times 63$

Correct answer:

$5\times 61$

Explanation:

The computation shows that $305\div5=61$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 61}\\ {\color{Green} 5}{\overline{\smash{)}305}}\\ -\ 30 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$5\times61=305+0$

Simplify.

$5\times61=305$

The correct answer is $5\times 61$

Report an Error

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All Common Core: 6th Grade Math Resources

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Common Core: 6th Grade Math : Grade 6

Study concepts, example questions & explanations for Common Core: 6th Grade Math

All Common Core: 6th Grade Math Resources

Example Questions

Example Question #3521 : Operations

Example Question #3522 : Operations

Example Question #24 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Example Question #25 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Example Question #26 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Example Question #27 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Example Question #3541 : Operations

Example Question #3542 : Operations

Example Question #3543 : Operations

Example Question #3544 : Operations

All Common Core: 6th Grade Math Resources

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