All Common Core: 6th Grade Math Resources
Example Questions
Example Question #66 : Equations
What is ?
Divide each side by :
Example Question #69 : Equations
What is ?
Divide each side by :
Example Question #70 : Equations
What is ?
Divide each side by :
Example Question #353 : How To Find The Solution To An Equation
Solve for :
In order to solve this equation we need to isolate the variable to one side. Do not forget to perform the same operation on both sides of the equation.
Divide each side of the equation by :
Solve.
Example Question #524 : Expressions & Equations
Solve for :
In order to solve this equation we need to isolate the variable to one side. Do not forget to perform the same operation on both sides of the equation.
Subtract from both sides of the equation.
Solve.
Example Question #22 : Solve Real World And Mathematical Problems By Writing And Solving Equations: Ccss.Math.Content.6.Ee.B.7
Solve for :
The equation asks us to identify which number, , plus is equal to .
In order to solve this equation, we need to isolate the variable on one side of the equals sign. We will do this by performing the opposite of the operations that were done on the variable, . We need to remember that whatever we do to one side of the equals sign, we have to do to the other.
Since was added to the variable, we can subtract from both sides of the equation.
Simplify by dropping the because it has not numerical value; therefore:
We can check to make sure we have the correct value for by plugging into the original equation; thus:
Example Question #974 : Grade 6
Solve for :
The equation asks us to identify which number, , plus is equal to .
In order to solve this equation, we need to isolate the variable on one side of the equals sign. We will do this by performing the opposite of the operations that were done on the variable,. We need to remember that whatever we do to one side of the equals sign, we have to do to the other.
Since was added to the variable, we can subtract from both sides of the equation.
Simplify by dropping the because it has not numerical value; therefore:
We can check to make sure we have the correct value for by plugging into the original equation; thus:
Example Question #525 : Expressions & Equations
Solve for :
The equation asks us to identify which number, , plus is equal to .
In order to solve this equation, we need to isolate the variable on one side of the equals sign. We will do this by performing the opposite of the operations that were done on the variable,. We need to remember that whatever we do to one side of the equals sign, we have to do to the other.
Since was added to the variable, we can subtract from both sides of the equation.
Simplify by dropping the because it has not numerical value; therefore:
We can check to make sure we have the correct value for by plugging into the original equation; thus:
Example Question #982 : Grade 6
Solve for :
The equation asks us to identify which number, , plus is equal to .
In order to solve this equation, we need to isolate the variable on one side of the equals sign. We will do this by performing the opposite of the operations that were done on the variable,. We need to remember that whatever we do to one side of the equals sign, we have to do to the other.
Since was added to the variable, we can subtract from both sides of the equation.
Simplify by dropping the because it has not numerical value; therefore:
We can check to make sure we have the correct value for by plugging into the original equation; thus:
Example Question #983 : Grade 6
Solve for :
The equation asks us to identify which number, , plus is equal to .
In order to solve this equation, we need to isolate the variable on one side of the equals sign. We will do this by performing the opposite of the operations that were done on the variable,. We need to remember that whatever we do to one side of the equals sign, we have to do to the other.
Since was added to the variable, we can subtract from both sides of the equation.
Simplify by dropping the because it has not numerical value; therefore:
We can check to make sure we have the correct value for by plugging into the original equation; thus: