Common Core: 5th Grade Math : Operations & Algebraic Thinking

Study concepts, example questions & explanations for Common Core: 5th Grade Math

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Example Questions

Example Question #595 : Ssat Middle Level Quantitative (Math)

Complete the table below using the equation \(\displaystyle y=13x+3\)

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Possible Answers:

\(\displaystyle 41\)

\(\displaystyle 44\)

\(\displaystyle 42\)

\(\displaystyle 45\)

\(\displaystyle 43\)

Correct answer:

\(\displaystyle 42\)

Explanation:

In order to solve this question, we need to use both the equation and the table. We are looking for the corresponding \(\displaystyle y\) value for \(\displaystyle x=3\). We can plug \(\displaystyle 3\) into the \(\displaystyle x\) in our equation to solve for \(\displaystyle y\).

\(\displaystyle y=13(3)+3\)

\(\displaystyle y=39+3\)

\(\displaystyle y=42\)

Example Question #596 : Ssat Middle Level Quantitative (Math)

Complete the table below using the equation \(\displaystyle y=14x+6\)

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Possible Answers:

\(\displaystyle 89\)

\(\displaystyle 88\)

\(\displaystyle 91\)

\(\displaystyle 90\)

\(\displaystyle 92\)

Correct answer:

\(\displaystyle 90\)

Explanation:

In order to solve this question, we need to use both the equation and the table. We are looking for the corresponding \(\displaystyle y\) value for \(\displaystyle x=6\). We can plug \(\displaystyle 6\) into the \(\displaystyle x\) in our equation to solve for \(\displaystyle y\).

\(\displaystyle y=14(6)+6\)

\(\displaystyle y=84+6\)

\(\displaystyle y=90\)

Example Question #11 : Generate Two Numerical Patterns Using Two Given Rules: Ccss.Math.Content.5.Oa.B.3

Complete the table below using the equation \(\displaystyle y=7x+3\)

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Possible Answers:

\(\displaystyle 46\)

\(\displaystyle 45\)

\(\displaystyle 49\)

\(\displaystyle 48\)

\(\displaystyle 47\)

Correct answer:

\(\displaystyle 45\)

Explanation:

In order to solve this question, we need to use both the equation and the table. We are looking for the corresponding \(\displaystyle y\) value for \(\displaystyle x=6\). We can plug \(\displaystyle 6\) into the \(\displaystyle x\)  in our equation to solve for \(\displaystyle y\).

\(\displaystyle y=7(6)+3\)

\(\displaystyle y=42+3\)

\(\displaystyle y=45\)

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