All Common Core: 5th Grade Math Resources
Example Questions
Example Question #105 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3
Identify the division problem that equals the following:
The fraction line means divided by; therefore, we can read as divided by , or
Example Question #106 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3
Identify the division problem that equals the following:
The fraction line means divided by; therefore, we can read as divided by , or
Example Question #107 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3
Identify the division problem that equals the following:
The fraction line means divided by; therefore, we can read as divided by , or
Example Question #108 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3
Identify the division problem that equals the following:
The fraction line means divided by; therefore, we can read as divided by , or
Example Question #109 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3
A baker has cakes to make this weekend. If he has of sugar, how much sugar does can he put in each cake, assuming each cake's recipe calls for an equal amount of sugar? Select the answer that contains the pair of numbers that the answer falls between.
and
and
and
and
and
and
We can think of this problem as an improper fraction and solve for the mixed number by placing the amount of sugar over the number of cakes to be made. We get the following:
can go into only times. In other words, we are looking for the number that when multiplied by the denominator gets us as close to the numerator as possible, without going over the value of the numerator.
Simple multiplication reveals the following:
In order to find out what is left over, we must subtract this number from the numerator.
The difference will always be less than the denominator from the original improper fraction. If it is not, then check your work in the previous step because this means that the denominator could have been divided into the numerator at least one more time.
Then, we put the difference over the denominator:
Let's solve for the entire improper fraction by putting these values together and forming a mixed number:
Last, we know that is between the numbers and ; therefore, the correct answer is:
and
Example Question #110 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3
A baker has cakes to make this weekend. If he has of sugar, how much sugar does can he put in each cake, assuming each cake's recipe calls for an equal amount of sugar? Select the answer that contains the pair of numbers that the answer falls between.
and
and
and
and
and
and
We can think of this problem as an improper fraction and solve for the mixed number by placing the amount of sugar over the number of cakes to be made. We get the following:
can go into only times. In other words, we are looking for the number that when multiplied by the denominator gets us as close to the numerator as possible, without going over the value of the numerator.
Simple multiplication reveals the following:
In order to find out what is left over, we must subtract this number from the numerator.
The difference will always be less than the denominator from the original improper fraction. If it is not, then check your work in the previous step because this means that the denominator could have been divided into the numerator at least one more time.
Then, we put the difference over the denominator:
Let's solve for the entire improper fraction by putting these values together and forming a mixed number:
Last, we know that is between the numbers and ; therefore, the correct answer is:
and
Example Question #111 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3
A baker has cakes to make this weekend. If he has of sugar, how much sugar does can he put in each cake, assuming each cake's recipe calls for an equal amount of sugar? Select the answer that contains the pair of numbers that the answer falls between.
and
and
and
and
and
and
We can think of this problem as an improper fraction and solve for the mixed number by placing the amount of sugar over the number of cakes to be made. We get the following:
can go into only times. In other words, we are looking for the number that when multiplied by the denominator gets us as close to the numerator as possible, without going over the value of the numerator.
Simple multiplication reveals the following:
In order to find out what is left over, we must subtract this number from the numerator.
The difference will always be less than the denominator from the original improper fraction. If it is not, then check your work in the previous step because this means that the denominator could have been divided into the numerator at least one more time.
Then, we put the difference over the denominator:
Let's solve for the entire improper fraction by putting these values together and forming a mixed number:
Last, we know that is between the numbers and ; therefore, the correct answer is:
and
Example Question #988 : Common Core Math: Grade 5
A baker has cakes to make this weekend. If he has of sugar, how much sugar does can he put in each cake, assuming each cake's recipe calls for an equal amount of sugar? Select the answer that contains the pair of numbers that the answer falls between.
and
and
and
and
and
and
We can think of this problem as an improper fraction and solve for the mixed number by placing the amount of sugar over the number of cakes to be made. We get the following:
can go into only times. In other words, we are looking for the number that when multiplied by the denominator gets us as close to the numerator as possible, without going over the value of the numerator.
Simple multiplication reveals the following:
In order to find out what is left over, we must subtract this number from the numerator.
The difference will always be less than the denominator from the original improper fraction. If it is not, then check your work in the previous step because this means that the denominator could have been divided into the numerator at least one more time.
Then, we put the difference over the denominator:
Let's solve for the entire improper fraction by putting these values together and forming a mixed number:
Last, we know that is between the numbers and ; therefore, the correct answer is:
and
Example Question #138 : Number & Operations With Fractions
A baker has cakes to make this weekend. If he has of sugar, how much sugar does can he put in each cake, assuming each cake's recipe calls for an equal amount of sugar? Select the answer that contains the pair of numbers that the answer falls between.
and
and
and
and
and
and
We can think of this problem as an improper fraction and solve for the mixed number by placing the amount of sugar over the number of cakes to be made. We get the following:
can go into only times. In other words, we are looking for the number that when multiplied by the denominator gets us as close to the numerator as possible, without going over the value of the numerator.
Simple multiplication reveals the following:
In order to find out what is left over, we must subtract this number from the numerator.
The difference will always be less than the denominator from the original improper fraction. If it is not, then check your work in the previous step because this means that the denominator could have been divided into the numerator at least one more time.
Then, we put the difference over the denominator:
Let's solve for the entire improper fraction by putting these values together and forming a mixed number:
Last, we know that is between the numbers and ; therefore, the correct answer is:
and
Example Question #114 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3
A baker has cakes to make this weekend. If he has of sugar, how much sugar does can he put in each cake, assuming each cake's recipe calls for an equal amount of sugar? Select the answer that contains the pair of numbers that the answer falls between.
and
and
and
and
and
and
We can think of this problem as an improper fraction and solve for the mixed number by placing the amount of sugar over the number of cakes to be made. We get the following:
can go into only times. In other words, we are looking for the number that when multiplied by the denominator gets us as close to the numerator as possible, without going over the value of the numerator.
Simple multiplication reveals the following:
In order to find out what is left over, we must subtract this number from the numerator.
The difference will always be less than the denominator from the original improper fraction. If it is not, then check your work in the previous step because this means that the denominator could have been divided into the numerator at least one more time.
Then, we put the difference over the denominator:
Let's solve for the entire improper fraction by putting these values together and forming a mixed number:
Last, we know that is between the numbers and ; therefore, the correct answer is:
and