Calculus 3 : Calculus 3

Study concepts, example questions & explanations for Calculus 3

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Example Questions

Example Question #1921 : Calculus 3

\(\displaystyle \begin{align*}&\text{A point in space is located, in cylindrical coordinates, at } (113,2^{\circ},-74).\\&\text{What is the position of this point in Cartesian coordinates?}\end{align*}\)

Possible Answers:

\(\displaystyle (112.93,3.94,-74)\)

\(\displaystyle (102.75,-47.02,-74)\)

\(\displaystyle (-47.02,102.75,-74)\)

\(\displaystyle (3.94,112.93,-74)\)

Correct answer:

\(\displaystyle (112.93,3.94,-74)\)

Explanation:

\(\displaystyle \begin{align*}&\text{If asked to convert cylindrical coordinates of the form} (r,\theta,z)\\&\text{to Cartesian coordinates of the form }(x,y,z)\text{, it is necessary to relate } x\text{ and }y\\& \text{to the radius, }r\text{, and the angle, }\theta.\text{ The relationships are as follows:}\\&x=rcos(\theta)\\&y=rsin(\theta)\\&\text{Finding }z\text{ is much simpler; it does not change between}\\& \text{Cartesian and cylindrical coordinates:}\\&z=z\\&\text{However, care should be taken when finding }x\text{ and }y\text{; if using a calculator, it is}\\& \text{imperative that the correct units (degrees or radians) are specified}\\& \text{for the input!}\\&\text{For our coordinates}\\&x=113cos(2^{\circ})=112.93\\&y=113sin(2^{\circ})=3.94\\&z=-74\end{align*}\)

Example Question #1922 : Calculus 3

\(\displaystyle \begin{align*}&\text{A point in space is located, in cylindrical coordinates, at } (105,166^{\circ},118).\\&\text{What is the position of this point in Cartesian coordinates?}\end{align*}\)

Possible Answers:

\(\displaystyle (25.4,-101.88,118)\)

\(\displaystyle (50.75,-91.92,118)\)

\(\displaystyle (-91.92,50.75,118)\)

\(\displaystyle (-101.88,25.4,118)\)

Correct answer:

\(\displaystyle (-101.88,25.4,118)\)

Explanation:

\(\displaystyle \begin{align*}&\text{If asked to convert cylindrical coordinates of the form} (r,\theta,z)\\&\text{to Cartesian coordinates of the form }(x,y,z)\text{, it is necessary to relate } x\text{ and }y\\& \text{to the radius, }r\text{, and the angle, }\theta.\text{ The relationships are as follows:}\\&x=rcos(\theta)\\&y=rsin(\theta)\\&\text{Finding }z\text{ is much simpler; it does not change between}\\& \text{Cartesian and cylindrical coordinates:}\\&z=z\\&\text{However, care should be taken when finding }x\text{ and }y\text{; if using a calculator, it is}\\& \text{imperative that the correct units (degrees or radians) are specified}\\& \text{for the input!}\\&\text{For our coordinates}\\&x=105cos(166^{\circ})=-101.88\\&y=105sin(166^{\circ})=25.4\\&z=118\end{align*}\)

Example Question #1923 : Calculus 3

\(\displaystyle \begin{align*}&\text{A point in space is located, in cylindrical coordinates, at } (83,-127^{\circ},-109).\\&\text{What is the position of this point in Cartesian coordinates?}\end{align*}\)

Possible Answers:

\(\displaystyle (-49.95,-66.29,-109)\)

\(\displaystyle (19.29,-80.73,-109)\)

\(\displaystyle (-80.73,19.29,-109)\)

\(\displaystyle (-66.29,-49.95,-109)\)

Correct answer:

\(\displaystyle (-49.95,-66.29,-109)\)

Explanation:

\(\displaystyle \begin{align*}&\text{If asked to convert cylindrical coordinates of the form} (r,\theta,z)\\&\text{to Cartesian coordinates of the form }(x,y,z)\text{, it is necessary to relate } x\text{ and }y\\& \text{to the radius, }r\text{, and the angle, }\theta.\text{ The relationships are as follows:}\\&x=rcos(\theta)\\&y=rsin(\theta)\\&\text{Finding }z\text{ is much simpler; it does not change between}\\& \text{Cartesian and cylindrical coordinates:}\\&z=z\\&\text{However, care should be taken when finding }x\text{ and }y\text{; if using a calculator, it is}\\& \text{imperative that the correct units (degrees or radians) are specified}\\& \text{for the input!}\\&\text{For our coordinates}\\&x=83cos(-127^{\circ})=-49.95\\&y=83sin(-127^{\circ})=-66.29\\&z=-109\end{align*}\)

Example Question #1924 : Calculus 3

\(\displaystyle \begin{align*}&\text{A point in space is located, in cylindrical coordinates, at } (39,-89^{\circ},103).\\&\text{What is the position of this point in Cartesian coordinates?}\end{align*}\)

Possible Answers:

\(\displaystyle (0.68,-38.99,103)\)

\(\displaystyle (-33.54,19.9,103)\)

\(\displaystyle (-38.99,0.68,103)\)

\(\displaystyle (19.9,-33.54,103)\)

Correct answer:

\(\displaystyle (0.68,-38.99,103)\)

Explanation:

\(\displaystyle \begin{align*}&\text{If asked to convert cylindrical coordinates of the form} (r,\theta,z)\\&\text{to Cartesian coordinates of the form }(x,y,z)\text{, it is necessary to relate } x\text{ and }y\\& \text{to the radius, }r\text{, and the angle, }\theta.\text{ The relationships are as follows:}\\&x=rcos(\theta)\\&y=rsin(\theta)\\&\text{Finding }z\text{ is much simpler; it does not change between}\\& \text{Cartesian and cylindrical coordinates:}\\&z=z\\&\text{However, care should be taken when finding }x\text{ and }y\text{; if using a calculator, it is}\\& \text{imperative that the correct units (degrees or radians) are specified}\\& \text{for the input!}\\&\text{For our coordinates}\\&x=39cos(-89^{\circ})=0.68\\&y=39sin(-89^{\circ})=-38.99\\&z=103\end{align*}\)

Example Question #1925 : Calculus 3

\(\displaystyle \begin{align*}&\text{A point in space is located, in cylindrical coordinates, at } (123,155^{\circ},-77).\\&\text{What is the position of this point in Cartesian coordinates?}\end{align*}\)

Possible Answers:

\(\displaystyle (-107.42,-59.92,-77)\)

\(\displaystyle (-59.92,-107.42,-77)\)

\(\displaystyle (-111.48,51.98,-77)\)

\(\displaystyle (51.98,-111.48,-77)\)

Correct answer:

\(\displaystyle (-111.48,51.98,-77)\)

Explanation:

\(\displaystyle \begin{align*}&\text{If asked to convert cylindrical coordinates of the form} (r,\theta,z)\\&\text{to Cartesian coordinates of the form }(x,y,z)\text{, it is necessary to relate } x\text{ and }y\\& \text{to the radius, }r\text{, and the angle, }\theta.\text{ The relationships are as follows:}\\&x=rcos(\theta)\\&y=rsin(\theta)\\&\text{Finding }z\text{ is much simpler; it does not change between}\\& \text{Cartesian and cylindrical coordinates:}\\&z=z\\&\text{However, care should be taken when finding }x\text{ and }y\text{; if using a calculator, it is}\\& \text{imperative that the correct units (degrees or radians) are specified}\\& \text{for the input!}\\&\text{For our coordinates}\\&x=123cos(155^{\circ})=-111.48\\&y=123sin(155^{\circ})=51.98\\&z=-77\end{align*}\)

Example Question #1926 : Calculus 3

\(\displaystyle \begin{align*}&\text{A point in space is located, in cylindrical coordinates, at } (53,-90^{\circ},-91).\\&\text{What is the position of this point in Cartesian coordinates?}\end{align*}\)

Possible Answers:

\(\displaystyle (-47.38,-23.75,-91)\)

\(\displaystyle (-53,0,-91)\)

\(\displaystyle (0,-53,-91)\)

\(\displaystyle (-23.75,-47.38,-91)\)

Correct answer:

\(\displaystyle (0,-53,-91)\)

Explanation:

\(\displaystyle \begin{align*}&\text{If asked to convert cylindrical coordinates of the form} (r,\theta,z)\\&\text{to Cartesian coordinates of the form }(x,y,z)\text{, it is necessary to relate } x\text{ and }y\\& \text{to the radius, }r\text{, and the angle, }\theta.\text{ The relationships are as follows:}\\&x=rcos(\theta)\\&y=rsin(\theta)\\&\text{Finding }z\text{ is much simpler; it does not change between}\\& \text{Cartesian and cylindrical coordinates:}\\&z=z\\&\text{However, care should be taken when finding }x\text{ and }y\text{; if using a calculator, it is}\\& \text{imperative that the correct units (degrees or radians) are specified}\\& \text{for the input!}\\&\text{For our coordinates}\\&x=53cos(-90^{\circ})=0\\&y=53sin(-90^{\circ})=-53\\&z=-91\end{align*}\)

Example Question #1927 : Calculus 3

\(\displaystyle \begin{align*}&\text{A point in space is located, in cylindrical coordinates, at } (93,-54^{\circ},-8).\\&\text{What is the position of this point in Cartesian coordinates?}\end{align*}\)

Possible Answers:

\(\displaystyle (-77.13,51.97,-8)\)

\(\displaystyle (-75.24,54.66,-8)\)

\(\displaystyle (54.66,-75.24,-8)\)

\(\displaystyle (51.97,-77.13,-8)\)

Correct answer:

\(\displaystyle (54.66,-75.24,-8)\)

Explanation:

\(\displaystyle \begin{align*}&\text{If asked to convert cylindrical coordinates of the form} (r,\theta,z)\\&\text{to Cartesian coordinates of the form }(x,y,z)\text{, it is necessary to relate } x\text{ and }y\\& \text{to the radius, }r\text{, and the angle, }\theta.\text{ The relationships are as follows:}\\&x=rcos(\theta)\\&y=rsin(\theta)\\&\text{Finding }z\text{ is much simpler; it does not change between}\\& \text{Cartesian and cylindrical coordinates:}\\&z=z\\&\text{However, care should be taken when finding }x\text{ and }y\text{; if using a calculator, it is}\\& \text{imperative that the correct units (degrees or radians) are specified}\\& \text{for the input!}\\&\text{For our coordinates}\\&x=93cos(-54^{\circ})=54.66\\&y=93sin(-54^{\circ})=-75.24\\&z=-8\end{align*}\)

Example Question #1928 : Calculus 3

\(\displaystyle \begin{align*}&\text{A point in space is located, in cylindrical coordinates, at } (125,18^{\circ},26).\\&\text{What is the position of this point in Cartesian coordinates?}\end{align*}\)

Possible Answers:

\(\displaystyle (38.63,118.88,26)\)

\(\displaystyle (-93.87,82.54,26)\)

\(\displaystyle (82.54,-93.87,26)\)

\(\displaystyle (118.88,38.63,26)\)

Correct answer:

\(\displaystyle (118.88,38.63,26)\)

Explanation:

\(\displaystyle \begin{align*}&\text{If asked to convert cylindrical coordinates of the form} (r,\theta,z)\\&\text{to Cartesian coordinates of the form }(x,y,z)\text{, it is necessary to relate } x\text{ and }y\\& \text{to the radius, }r\text{, and the angle, }\theta.\text{ The relationships are as follows:}\\&x=rcos(\theta)\\&y=rsin(\theta)\\&\text{Finding }z\text{ is much simpler; it does not change between}\\& \text{Cartesian and cylindrical coordinates:}\\&z=z\\&\text{However, care should be taken when finding }x\text{ and }y\text{; if using a calculator, it is}\\& \text{imperative that the correct units (degrees or radians) are specified}\\& \text{for the input!}\\&\text{For our coordinates}\\&x=125cos(18^{\circ})=118.88\\&y=125sin(18^{\circ})=38.63\\&z=26\end{align*}\)

Example Question #1929 : Calculus 3

\(\displaystyle \begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (76,-36,20).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}\)

Possible Answers:

\(\displaystyle (84.1,154.65^{\circ},20)\)

\(\displaystyle (84.1,-25.35^{\circ},20)\)

\(\displaystyle (40,-25.35^{\circ},20)\)

\(\displaystyle (40,154.65^{\circ},20)\)

Correct answer:

\(\displaystyle (84.1,-25.35^{\circ},20)\)

Explanation:

\(\displaystyle \begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(76,-36,20)\\&r=\sqrt{(76)^2+(-36)^2}=84.1\\&\theta=arctan(\frac{-36}{76})=-25.35^{\circ}\\&z=20\end{align*}\)

Example Question #1930 : Calculus 3

\(\displaystyle \begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (-128,-134,9).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}\)

Possible Answers:

\(\displaystyle (262,46.31^{\circ},9)\)

\(\displaystyle (185.31,46.31^{\circ},9)\)\(\displaystyle (262,-133.69^{\circ},9)\)

\(\displaystyle (185.31,-133.69^{\circ},9)\)

\(\displaystyle (262,-133.69^{\circ},9)\)

Correct answer:

\(\displaystyle (185.31,-133.69^{\circ},9)\)

Explanation:

\(\displaystyle \begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(-128,-134,9)\\&r=\sqrt{(-128)^2+(-134)^2}=185.31\\&\theta=arctan(\frac{-134}{-128})=-133.69^{\circ}\\&z=9\end{align*}\)

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