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Calculus 2 : Parametric, Polar, and Vector

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9 Diagnostic Tests 308 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #195 : Vector

Calculate the dot product of $a=\left<3,2,-1\right>$ and $b=\left<-1,2,-3\right>$ .

Possible Answers:

$-\frac{1}{4}$

$\frac{1}{4}$

None of the above

Correct answer:

Explanation:

We can calculate the dot product of $a=\left<3,2,-1\right>$ and $b=\left<-1,2,-3\right>$ by finding the sum of the products of both vectors' corresponding elements. Thus:

$\left<3,2,-1\right> \times \left<-1,2,-3\right>$

$=(3\times -1)+(2\times 2)+(-1\times -3)$

=(-3)+(4)+(3)

=(-3)+(3)+(4)

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Example Question #196 : Vector

Calculate the dot product of $a=\left<1,-1,0\right>$ and $b=\left<-1,2,-1\right>$ .

Possible Answers:

$-\frac{1}{3}$

None of the above

$\frac{1}{3}$

Correct answer:

Explanation:

We can calculate the dot product of $a=\left<1,-1,0\right>$ and $b=\left<-1,2,-1\right>$ by finding the sum of the products of both vectors' corresponding elements. Thus:

$\left<1,-1,0\right> \times \left<-1,2,-1\right>$

$=(1\times -1)+(-1\times 2)+(0\times -1)$

=-1+(-2)+0

=-3+0

=-3

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Example Question #197 : Vector

What is the dot product of $a=\left \langle 2,3-7\right \rangle$ and $b=\left \langle -4,1,-2\right \rangle$ ?

Possible Answers:

None of the above

$\frac{1}{9}$

$-\frac{1}{9}$

Correct answer:

Explanation:

The dot product of two vectors is the sum of the products of the vectors' corresponding elements. Given $a=\left \langle 2,3-7\right \rangle$ and $b=\left \langle -4,1,-2\right \rangle$ , then:

$\left \langle 2,3-7\right \rangle \times \left \langle -4,1,-2\right \rangle$

$=(2\times -4)+(3\times 1)+(-7\times -2)$

=(-8)+3+14

=(-8)+17

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Example Question #198 : Vector

What is the dot product of $a=\left \langle 3,-3,2\right \rangle$ and $b=\left \langle 2,3,-3\right \rangle$ ?

Possible Answers:

Correct answer:

Explanation:

The dot product of two vectors is the sum of the products of the vectors' corresponding elements. Given $a=\left \langle 3,-3,2\right \rangle$ and $b=\left \langle 2,3,-3\right \rangle$ , then:

$\left \langle 3,-3,2\right \rangle\times \left \langle 2,3,-3\right \rangle$

$=(3\times 2)+(-3\times 3)+(2\times -3)$

=6+(-9)+(-6)

=0 +(-9)

=-9

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Example Question #199 : Vector

What is the dot product of $a=\left \langle 1,2,0\right \rangle$ and $b=\left \langle 3,0,-1\right \rangle$ ?

Possible Answers:

Correct answer:

Explanation:

The dot product of two vectors is the sum of the products of the vectors' corresponding elements. Given $a=\left \langle 1,2,0\right \rangle$ and $b=\left \langle 3,0,-1\right \rangle$ , then:

$\left \langle 1,2,0\right \rangle\times \left \langle 3,0,-1\right \rangle$

$=(1\times 3)+(2\times 0)+(0\times -1)$

=3+0+0

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Example Question #200 : Vector

What is the norm of the vector $a=\left \langle 7,-4,1\right \rangle$ ?

Possible Answers:

$\sqrt{67}$

$\sqrt{66}$

$\sqrt{65}$

$\sqrt{63}$

Correct answer:

$\sqrt{66}$

Explanation:

In order to find the norm of a vector, we must first find the sum of the squares of the vector's elements and take the square root of that sum. Given $a=\left \langle 7,-4,1\right \rangle$ , then:

$\left \| a\right \|=\sqrt{(7)^{2}+(-4)^{2}+(1)^{2}}$

$\left \| a\right \|=\sqrt{49+16+1}$

$\left \| a\right \|=\sqrt{65+1}$

$\left \| a\right \|=\sqrt{66}$

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Example Question #201 : Vector

What is the norm of the vector $a=\left \langle 2,3,-1\right \rangle$ ?

Possible Answers:

$\sqrt{14}$

$\sqrt{17}$

$\sqrt{15}$

Correct answer:

$\sqrt{14}$

Explanation:

In order to find the norm of a vector, we must first find the sum of the squares of the vector's elements and take the square root of that sum. Given $a=\left \langle 2,3,-1\right \rangle$ , then:

$\left \| a\right \|=\sqrt{(2)^{2}+(3)^{2}+(-1)^{2}}$

$\left \| a\right \|=\sqrt{4+9+1}$

$\left \| a\right \|=\sqrt{13+1}$

$\left \| a\right \|=\sqrt{14}$

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Example Question #202 : Vector

What is the norm of the vector $a=\left \langle 0,1,2\right \rangle$ ?

Possible Answers:

$\sqrt{3}$

$\sqrt{5}$

Correct answer:

$\sqrt{5}$

Explanation:

In order to find the norm of a vector, we must first find the sum of the squares of the vector's elements and take the square root of that sum. Given $a=\left \langle 0,1,2\right \rangle$ , then:

$\left \| a\right \|=\sqrt{(0)^{2}+(1)^{2}+(2)^{2}}$

$\left \| a\right \|=\sqrt{0+1+4}$

$\left \| a\right \|=\sqrt{5}$

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Example Question #203 : Vector

What is the norm of $a=\left \langle 3,-1,7\right \rangle$ ?

Possible Answers:

$2\sqrt{15}$

$\sqrt{61}$

$\sqrt{59}$

$\sqrt{65}$

Correct answer:

$\sqrt{59}$

Explanation:

In order to find the norm of a vector, we must first find the sum of the squares of the vector's individual elements and then take the square root of that sum. Given $a=\left \langle 3,-1,7\right \rangle$ ,

$\left \| a\right \|=\sqrt{(3)^{2}+(-1)^{2}+(7)^{2}}$

$\left \| a\right \|=\sqrt{9+1+49}$

$\left \| a\right \|=\sqrt{10+49}$

$\left \| a\right \|=\sqrt{59}$

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Example Question #204 : Vector

What is the norm of $a=\left \langle 2,0,3\right \rangle$ ?

Possible Answers:

$\sqrt{11}$

$\sqrt{13}$

$\sqrt{14}$

$2\sqrt{3}$

Correct answer:

$\sqrt{13}$

Explanation:

In order to find the norm of a vector, we must first find the sum of the squares of the vector's individual elements and then take the square root of that sum. Given $a=\left \langle 2,0,3\right \rangle$ ,

$\left \| a\right \|=\sqrt{(2)^{2}+(0)^{2}+(3)^{2}}$

$\left \| a\right \|=\sqrt{4+0+9}$

$\left \| a\right \|=\sqrt{13}$

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Calculus 2 : Parametric, Polar, and Vector

Study concepts, example questions & explanations for Calculus 2

All Calculus 2 Resources

Example Questions

Example Question #195 : Vector

Example Question #196 : Vector

Example Question #197 : Vector

Example Question #198 : Vector

Example Question #199 : Vector

Example Question #200 : Vector

Example Question #201 : Vector

Example Question #202 : Vector

Example Question #203 : Vector

Example Question #204 : Vector

All Calculus 2 Resources

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