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Example Questions
Example Question #551 : Integrals
Solve the following definite integral.
Example Question #2302 : Calculus Ii
If
Not enough information.
If we think of the anti-derivative as computing the area under the curve, then between and , the area under our function equals . We also know that between and , the area under our function equals . Then, to find the area under the function between and , we must simply subtract the other two areas. Therefore:
Example Question #189 : Definite Integrals
If , what is ?
Remember that the anti-derivative computes the area under the curve of the function between the values specified by the upper and lower integral limits. In this question, the upper and lower integral limits match! This, by definition, means that the integral equals There is no area if you start and end at the same point!
Example Question #552 : Integrals
If , and what is
To find the total integral on our interval from to , we need to find the area under each subinterval and add them all up. The first and last part are given in the problem statement, but the middle interval has backwards limits.
Remember:
Therefore, we need to switch the sign on the middle area. Therefore,
Example Question #204 : Finding Integrals
In exponentially decaying systems, often times the solutions to differential equations take on the form of an integral called Duhamel's Integral. This is given by:
Where is a constant and is a function that represents an external force. represents the overall solution to the differential equation.
Determine if the external force is given by
We can rewrite the integral as
Using substitution, we let
We can therefore write the integral as:
Since .
Example Question #193 : Definite Integrals
In exponentially decaying systems, often times the solutions to differential equations take on the form of an integral called Duhamel's Integral. This is given by:
Where is a constant and is a function that represents an external force.
Determine the value at if .
Plugging into the equation:
Integrating by parts, we can assign values for , , , and :
Plugging into our equation:
The first term becomes:
The integral term becomes
Plugging everything else in we get:
Example Question #553 : Integrals
Evaluate the following definite integral:
This integral requires use of the power rule for antiderivatives, which simplifies as follows:
Example Question #192 : Definite Integrals
Evaluate the following definite integral:
Make the substitution:
Where
The limits of the integral, 0 and 1, are also changed in the substitution:
Using this in the original expression:
Example Question #193 : Definite Integrals
Evaluate the following definite integral:
To solve this with integration by parts, we rewrite the expression in the form
where
and
To integrate, apply the formula for integration by parts:
Example Question #194 : Definite Integrals
Evaluate the following definite integral:
This integral can be solved by using partial fractions. First, we have to factor the denominator write the fraction as a sum of two fractions:
Next, we can solve for A and B:
When we let x=3:
When x=2:
Replacing A and B in the integral, we can now solve it:
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