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Basic Geometry : Quadrilaterals

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Example Questions

Example Question #451 : Quadrilaterals

Find the perimeter of a square that has side lengths 6.3 .

Possible Answers:

26.2

25.2

16.2

18.2

Correct answer:

25.2

Explanation:

Use the following formula to find the perimeter of a square:

$\text{Perimeter}=4(\text{side length})$

For the given square,

$\text{Perimeter}=4(6.3)=25.2$

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Example Question #452 : Quadrilaterals

Find the perimeter of a square that has side lengths of 12.6 .

Possible Answers:

62.4

50.4

48.4

52.4

Correct answer:

50.4

Explanation:

Use the following formula to find the perimeter of a square:

$\text{Perimeter}=4(\text{side length})$

For the given square,

$\text{Perimeter}=4(12.6)=50.4$

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Example Question #453 : Quadrilaterals

Find the perimeter of a square that has side lengths of 8.9 .

Possible Answers:

38.6

35.6

27.6

32.6

Correct answer:

35.6

Explanation:

Use the following formula to find the perimeter of a square:

$\text{Perimeter}=4(\text{side length})$

For the given square,

$\text{Perimeter}=4(8.9)=35.6$

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Example Question #454 : Quadrilaterals

Find the perimeter of a square that has side lengths of 102 .

Possible Answers:

1020

408

308

608

Correct answer:

408

Explanation:

Use the following formula to find the perimeter of a square:

$\text{Perimeter}=4(\text{side length})$

For the given square,

$\text{Perimeter}=4(102)=408$

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Example Question #455 : Quadrilaterals

Find the perimeter of a square that has side lengths of 196.3 .

Possible Answers:

802.2

762.2

695.2

785.2

Correct answer:

785.2

Explanation:

Use the following formula to find the perimeter of a square:

$\text{Perimeter}=4(\text{side length})$

For the given square,

$\text{Perimeter}=4(196.3)=785.2$

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Example Question #456 : Quadrilaterals

Find the perimeter of a square with the side lengths of $\frac{3}{4}$ .

Possible Answers:

Correct answer:

Explanation:

Use the following formula to find the perimeter of a square:

$\text{Perimeter}=4(\text{side length})$

For the given square,

$\text{Perimeter}=4\left(\frac{3}{4}\right)=3$

In this particular case the fours cancel out and our final answer is three.

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Example Question #457 : Quadrilaterals

Find the perimeter of a square with side lengths of $\frac{5}{6}$ .

Possible Answers:

$\frac{5}{24}$

$\frac{1}{8}$

$\frac{20}{3}$

$\frac{10}{3}$

Correct answer:

$\frac{10}{3}$

Explanation:

Use the following formula to find the perimeter of a square:

$\text{Perimeter}=4(\text{side length})$

For the given square,

$\text{Perimeter}=4\left(\frac{5}{6}\right)=\frac{20}{6}=\frac{2\cdot 10}{2\cdot 3}=\frac{10}{3}$

Since there is a two in the numerator and a two in the denominator they cancel out which results in the simplified fraction.

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Example Question #866 : Plane Geometry

If the diagonal of a square is $12\sqrt2$ , what is the perimeter of the square?

Possible Answers:

144

Correct answer:

Explanation:

The diagonal of a square is also a hypotenuse of a right triangle with the side lengths as legs of the triangle.

Use the Pythagorean Theorem to find the length of one side of the square.

$\text{Diagonal}=\sqrt{\text{side length}^2+\text{side length}^2}$

$\text{Diagonal}=\sqrt{2(\text{side length})^2}$

$\text{Diagonal}=(\text{side length})\sqrt2$

$\text{Side length}=\frac{\text{Diagonal}}{\sqrt2}$

For the square given in the question,

$\text{Side length}=\frac{12\sqrt2}{\sqrt{2}}$

Simplify.

$\text{Side length}=12$

Now, recall how to find the perimeter of a square.

$\text{Perimeter}=4\times\text{side length}$

For the square in question,

$\text{Perimeter}=4\times 12$

Solve.

$\text{Perimeter}=48$

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Example Question #867 : Plane Geometry

If the diagonal of a square is $2\sqrt2$ , what is the perimeter of the square?

Possible Answers:

$8\sqrt2$

Correct answer:

Explanation:

The diagonal of a square is also a hypotenuse of a right triangle with the side lengths as legs of the triangle.

Use the Pythagorean Theorem to find the length of one side of the square.

$\text{Diagonal}=\sqrt{\text{side length}^2+\text{side length}^2}$

$\text{Diagonal}=\sqrt{2(\text{side length})^2}$

$\text{Diagonal}=(\text{side length})\sqrt2$

$\text{Side length}=\frac{\text{Diagonal}}{\sqrt2}$

For the square given in the question,

$\text{Side length}=\frac{2\sqrt2}{\sqrt{2}}$

Simplify.

$\text{Side length}=2$

Now, recall how to find the perimeter of a square.

$\text{Perimeter}=4\times\text{side length}$

For the square in question,

$\text{Perimeter}=4\times 2$

Solve.

$\text{Perimeter}=8$

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Example Question #868 : Plane Geometry

If the diagonal of a square is $7\sqrt2$ , what is the perimeter of the square?

Possible Answers:

$28\sqrt2$

Correct answer:

Explanation:

The diagonal of a square is also a hypotenuse of a right triangle with the side lengths as legs of the triangle.

Use the Pythagorean Theorem to find the length of one side of the square.

$\text{Diagonal}=\sqrt{\text{side length}^2+\text{side length}^2}$

$\text{Diagonal}=\sqrt{2(\text{side length})^2}$

$\text{Diagonal}=(\text{side length})\sqrt2$

$\text{Side length}=\frac{\text{Diagonal}}{\sqrt2}$

For the square given in the question,

$\text{Side length}=\frac{7\sqrt2}{\sqrt{2}}$

Simplify.

$\text{Side length}=7$

Now, recall how to find the perimeter of a square.

$\text{Perimeter}=4\times\text{side length}$

For the square in question,

$\text{Perimeter}=4\times 7$

Solve.

$\text{Perimeter}=28$

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Basic Geometry : Quadrilaterals

Study concepts, example questions & explanations for Basic Geometry

All Basic Geometry Resources

Example Questions

Example Question #451 : Quadrilaterals

Example Question #452 : Quadrilaterals

Example Question #453 : Quadrilaterals

Example Question #454 : Quadrilaterals

Example Question #455 : Quadrilaterals

Example Question #456 : Quadrilaterals

Example Question #457 : Quadrilaterals

Example Question #866 : Plane Geometry

Example Question #867 : Plane Geometry

Example Question #868 : Plane Geometry

All Basic Geometry Resources

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