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Basic Geometry : Quadrilaterals

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Example Question #101 : Rectangles

A rectangle has an area of 60in^2 , and a length of 10in . Find the width in inches.

Possible Answers:

5in

12in

6in

10in

8in

Correct answer:

6in

Explanation:

By using the formula for area, which is..:

Area = length (width)

..we plug in the numbers given. This gives us

60 = 10 (width)

$\frac{60}{10} = width$

6in = width

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Example Question #101 : Quadrilaterals

Find the length of a recangle given area is 10 and width is 2.

Possible Answers:

Correct answer:

Explanation:

To solve, simply use the formula for the area of a rectangle and solve for length.

$A=w*l\Rightarrow l=\frac{A}{w}$

$l=\frac{10}{2}=5$

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Example Question #103 : Rectangles

A checkerboard has an area of $315\;cm^2$ and one of the sides has a length of $15\;cm$ . What is the length of the other side of the board?

Possible Answers:

$20\;cm$

$21\;cm$

$19\;cm$

$22\;cm$

$18\;cm$

Correct answer:

$21\;cm$

Explanation:

We can use the formula for the area of a rectangle to find the length of the side with the information provided:

$\\Area=length\cdot width\\315\;cm^2=length\cdot15\;cm\\length=\frac{315\;cm^2}{15\;cm}=21\;cm\\length=21\;cm$

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Example Question #104 : Rectangles

If a graham cracker has a width of $5\;cm$ and an area of $62.5\;cm^2$ , what would be the length of the cracker?

Possible Answers:

$12.5\;cm$

$13\;cm$

$12\;cm$

$13.5\;cm$

$14\;cm$

Correct answer:

$12.5\;cm$

Explanation:

We can solve for the missing length using the formula for area of a rectangle:

$\\area=length\cdot width\\62.5\;cm^2=length\cdot5\;cm$

$length=\frac{62.5\;cm^2}{5\;cm}=12.5\;cm$

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Example Question #105 : Rectangles

A rectangle has a width of 5 meters. Its length is 2.5 times the width. What is the length of the long side and the total area of this rectangle?

Possible Answers:

A=62.5m

L=12.5m

None of these.

A=75m

L=15m

A=50m

L=10m

A=80

L=15

Correct answer:

A=62.5m

L=12.5m

Explanation:

"2.5 times the width" is equivalent to 2.5w. The length of the long side is L=2.5w=2.5(5)=12.5m .

The area is A=L*W=12.5*5=62.5m^2

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Example Question #106 : Rectangles

A rectangle has a perimeter of 30in . Its width is 5 in. What is the length of one long side?

Possible Answers:

L=5in

L=10in

None of these.

L=20in

L=25in

Correct answer:

L=10in

Explanation:

The perimeter of a rectangle can be found with P=2w+2l .

Fill in the information given, and solve for l:

30=2(5)+2l

30=10+2l

20=2l

$\mathbf{l=10}$

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Example Question #107 : Rectangles

Brady wants create a garage with an area of 2000 square feet. He needs the garage to be 50 feet long to fit all of his equipment. How wide will the garage be?

Possible Answers:

$40\ ft$

$30\ ft$

$45\ ft$

None of the answers given are correct

$50\ ft$

Correct answer:

$40\ ft$

Explanation:

Since we have the area, and we have the length, we use the area of a rectangle formula to find the missing side length.

$length\cdot width = area$

$50\cdot width = 2000$

divide both sides by 50 to get the variable by itself

width=40 inches

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Example Question #1 : How To Find The Length Of The Diagonal Of A Rectangle

A rectangle has a length of 12 in and a width of 5 in. What is the diagonal of the rectangle?

Possible Answers:

$17\; in$

$14\; in$

$16\; in$

$15\; in$

$13\; in$

Correct answer:

$13\; in$

Explanation:

To find the diagonal we use the Pythagorean Theorem:

$5^{2}+12^{2}= x^{2}$ where = hypotenuse

$25+144=x^{2}$ or $x=13\; in$

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Example Question #1 : How To Find The Length Of The Diagonal Of A Rectangle

One side of a rectangle is 7 inches and another is 9 inches. How many inches long is the rectangle's diagonal?

Possible Answers:

11.4

130

10.2

Correct answer:

11.4

Explanation:

You can find the diagonal of a rectangle if you have the width and the height. The diagonal equals the square root of the width squared plus the height squared.

$\sqrt{9^{2}+7^{2}}=11.4$

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Example Question #1 : How To Find The Length Of The Diagonal Of A Rectangle

Find the length of the diagonal.

Possible Answers:

$4\sqrt{13}$

$16\sqrt{13}$

Correct answer:

$4\sqrt{13}$

Explanation:

The rectangle can be cut into two equal right triangles, where the hypotenuse of both is the rectangle's diagonal.

Use the Pythagorean Theorem to find the hypotenuse:

a^2+b^2=c^2 , where a and b are the legs and c is the hypotenuse

(12)^2 + (8)^2 = c^2

144 + 64 = c^2

208 = c^2

$\sqrt{208} = \sqrt{c^2}$

$c = 4\sqrt{13}$

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Basic Geometry : Quadrilaterals

Study concepts, example questions & explanations for Basic Geometry

All Basic Geometry Resources

Example Questions

Example Question #101 : Rectangles

Example Question #101 : Quadrilaterals

Example Question #103 : Rectangles

Example Question #104 : Rectangles

Example Question #105 : Rectangles

Example Question #106 : Rectangles

Example Question #107 : Rectangles

Example Question #1 : How To Find The Length Of The Diagonal Of A Rectangle

Example Question #1 : How To Find The Length Of The Diagonal Of A Rectangle

Example Question #1 : How To Find The Length Of The Diagonal Of A Rectangle

All Basic Geometry Resources

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