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Basic Geometry : How to find the perimeter of a square

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Example Questions

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Example Question #861 : Basic Geometry

If the diagonal of a square is $12\sqrt2$ , what is the perimeter of the square?

Possible Answers:

144

Correct answer:

Explanation:

The diagonal of a square is also a hypotenuse of a right triangle with the side lengths as legs of the triangle.

Use the Pythagorean Theorem to find the length of one side of the square.

$\text{Diagonal}=\sqrt{\text{side length}^2+\text{side length}^2}$

$\text{Diagonal}=\sqrt{2(\text{side length})^2}$

$\text{Diagonal}=(\text{side length})\sqrt2$

$\text{Side length}=\frac{\text{Diagonal}}{\sqrt2}$

For the square given in the question,

$\text{Side length}=\frac{12\sqrt2}{\sqrt{2}}$

Simplify.

$\text{Side length}=12$

Now, recall how to find the perimeter of a square.

$\text{Perimeter}=4\times\text{side length}$

For the square in question,

$\text{Perimeter}=4\times 12$

Solve.

$\text{Perimeter}=48$

Report an Error

Example Question #867 : Basic Geometry

If the diagonal of a square is $2\sqrt2$ , what is the perimeter of the square?

Possible Answers:

$8\sqrt2$

Correct answer:

Explanation:

The diagonal of a square is also a hypotenuse of a right triangle with the side lengths as legs of the triangle.

Use the Pythagorean Theorem to find the length of one side of the square.

$\text{Diagonal}=\sqrt{\text{side length}^2+\text{side length}^2}$

$\text{Diagonal}=\sqrt{2(\text{side length})^2}$

$\text{Diagonal}=(\text{side length})\sqrt2$

$\text{Side length}=\frac{\text{Diagonal}}{\sqrt2}$

For the square given in the question,

$\text{Side length}=\frac{2\sqrt2}{\sqrt{2}}$

Simplify.

$\text{Side length}=2$

Now, recall how to find the perimeter of a square.

$\text{Perimeter}=4\times\text{side length}$

For the square in question,

$\text{Perimeter}=4\times 2$

Solve.

$\text{Perimeter}=8$

Report an Error

Example Question #862 : Basic Geometry

If the diagonal of a square is $7\sqrt2$ , what is the perimeter of the square?

Possible Answers:

$28\sqrt2$

Correct answer:

Explanation:

The diagonal of a square is also a hypotenuse of a right triangle with the side lengths as legs of the triangle.

Use the Pythagorean Theorem to find the length of one side of the square.

$\text{Diagonal}=\sqrt{\text{side length}^2+\text{side length}^2}$

$\text{Diagonal}=\sqrt{2(\text{side length})^2}$

$\text{Diagonal}=(\text{side length})\sqrt2$

$\text{Side length}=\frac{\text{Diagonal}}{\sqrt2}$

For the square given in the question,

$\text{Side length}=\frac{7\sqrt2}{\sqrt{2}}$

Simplify.

$\text{Side length}=7$

Now, recall how to find the perimeter of a square.

$\text{Perimeter}=4\times\text{side length}$

For the square in question,

$\text{Perimeter}=4\times 7$

Solve.

$\text{Perimeter}=28$

Report an Error

Example Question #863 : Basic Geometry

If the diagonal of a square is $14\sqrt2$ , what is the perimeter of the square?

Possible Answers:

196

Correct answer:

Explanation:

The diagonal of a square is also a hypotenuse of a right triangle with the side lengths as legs of the triangle.

Use the Pythagorean Theorem to find the length of one side of the square.

$\text{Diagonal}=\sqrt{\text{side length}^2+\text{side length}^2}$

$\text{Diagonal}=\sqrt{2(\text{side length})^2}$

$\text{Diagonal}=(\text{side length})\sqrt2$

$\text{Side length}=\frac{\text{Diagonal}}{\sqrt2}$

For the square given in the question,

$\text{Side length}=\frac{14\sqrt2}{\sqrt{2}}$

Simplify.

$\text{Side length}=14$

Now, recall how to find the perimeter of a square.

$\text{Perimeter}=4\times\text{side length}$

For the square in question,

$\text{Perimeter}=4\times 14$

Solve.

$\text{Perimeter}=56$

Report an Error

Example Question #864 : Basic Geometry

If the diagonal of a square is $10\sqrt2$ , what is the perimeter of the square?

Possible Answers:

Correct answer:

Explanation:

The diagonal of a square is also a hypotenuse of a right triangle with the side lengths as legs of the triangle.

Use the Pythagorean Theorem to find the length of one side of the square.

$\text{Diagonal}=\sqrt{\text{side length}^2+\text{side length}^2}$

$\text{Diagonal}=\sqrt{2(\text{side length})^2}$

$\text{Diagonal}=(\text{side length})\sqrt2$

$\text{Side length}=\frac{\text{Diagonal}}{\sqrt2}$

For the square given in the question,

$\text{Side length}=\frac{10\sqrt2}{\sqrt{2}}$

Simplify.

$\text{Side length}=10$

Now, recall how to find the perimeter of a square.

$\text{Perimeter}=4\times\text{side length}$

For the square in question,

$\text{Perimeter}=4\times 10$

Solve.

$\text{Perimeter}=40$

Report an Error

Example Question #871 : Basic Geometry

If the diagonal of a square is $9\sqrt2$ , what is the perimeter of the square?

Possible Answers:

Correct answer:

Explanation:

The diagonal of a square is also a hypotenuse of a right triangle with the side lengths as legs of the triangle.

Use the Pythagorean Theorem to find the length of one side of the square.

$\text{Diagonal}=\sqrt{\text{side length}^2+\text{side length}^2}$

$\text{Diagonal}=\sqrt{2(\text{side length})^2}$

$\text{Diagonal}=(\text{side length})\sqrt2$

$\text{Side length}=\frac{\text{Diagonal}}{\sqrt2}$

For the square given in the question,

$\text{Side length}=\frac{9\sqrt2}{\sqrt{2}}$

Simplify.

$\text{Side length}=9$

Now, recall how to find the perimeter of a square.

$\text{Perimeter}=4\times\text{side length}$

For the square in question,

$\text{Perimeter}=4\times 9$

Solve.

$\text{Perimeter}=36$

Report an Error

Example Question #872 : Basic Geometry

If the diagonal of a square is $22\sqrt2$ , what is the perimeter of the square?

Possible Answers:

176

484

Correct answer:

Explanation:

The diagonal of a square is also a hypotenuse of a right triangle with the side lengths as legs of the triangle.

Use the Pythagorean Theorem to find the length of one side of the square.

$\text{Diagonal}=\sqrt{\text{side length}^2+\text{side length}^2}$

$\text{Diagonal}=\sqrt{2(\text{side length})^2}$

$\text{Diagonal}=(\text{side length})\sqrt2$

$\text{Side length}=\frac{\text{Diagonal}}{\sqrt2}$

For the square given in the question,

$\text{Side length}=\frac{22\sqrt2}{\sqrt{2}}$

Simplify.

$\text{Side length}=22$

Now, recall how to find the perimeter of a square.

$\text{Perimeter}=4\times\text{side length}$

For the square in question,

$\text{Perimeter}=4\times 22$

Solve.

$\text{Perimeter}=88$

Report an Error

Example Question #23 : How To Find The Perimeter Of A Square

If the diagonal of a square is $23\sqrt2$ , what is the perimeter of the square?

Possible Answers:

102

Correct answer:

Explanation:

The diagonal of a square is also a hypotenuse of a right triangle with the side lengths as legs of the triangle.

Use the Pythagorean Theorem to find the length of one side of the square.

$\text{Diagonal}=\sqrt{\text{side length}^2+\text{side length}^2}$

$\text{Diagonal}=\sqrt{2(\text{side length})^2}$

$\text{Diagonal}=(\text{side length})\sqrt2$

$\text{Side length}=\frac{\text{Diagonal}}{\sqrt2}$

For the square given in the question,

$\text{Side length}=\frac{23\sqrt2}{\sqrt{2}}$

Simplify.

$\text{Side length}=23$

Now, recall how to find the perimeter of a square.

$\text{Perimeter}=4\times\text{side length}$

For the square in question,

$\text{Perimeter}=4\times 23$

Solve.

$\text{Perimeter}= 92$

Report an Error

Example Question #873 : Basic Geometry

If the diagonal of a square is $56\sqrt2$ , what is the perimeter of the square?

Possible Answers:

236

224

112

324

Correct answer:

224

Explanation:

The diagonal of a square is also a hypotenuse of a right triangle with the side lengths as legs of the triangle.

Use the Pythagorean Theorem to find the length of one side of the square.

$\text{Diagonal}=\sqrt{\text{side length}^2+\text{side length}^2}$

$\text{Diagonal}=\sqrt{2(\text{side length})^2}$

$\text{Diagonal}=(\text{side length})\sqrt2$

$\text{Side length}=\frac{\text{Diagonal}}{\sqrt2}$

For the square given in the question,

$\text{Side length}=\frac{56\sqrt2}{\sqrt{2}}$

Simplify.

$\text{Side length}=56$

Now, recall how to find the perimeter of a square.

$\text{Perimeter}=4\times\text{side length}$

For the square in question,

$\text{Perimeter}=4\times 56$

Solve.

$\text{Perimeter}=224$

Report an Error

Example Question #21 : How To Find The Perimeter Of A Square

If the diagonal of a square is $236\sqrt2$ , what is the perimeter of the square?

Possible Answers:

1024

487

784

944

Correct answer:

944

Explanation:

The diagonal of a square is also a hypotenuse of a right triangle with the side lengths as legs of the triangle.

Use the Pythagorean Theorem to find the length of one side of the square.

$\text{Diagonal}=\sqrt{\text{side length}^2+\text{side length}^2}$

$\text{Diagonal}=\sqrt{2(\text{side length})^2}$

$\text{Diagonal}=(\text{side length})\sqrt2$

$\text{Side length}=\frac{\text{Diagonal}}{\sqrt2}$

For the square given in the question,

$\text{Side length}=\frac{236\sqrt2}{\sqrt{2}}$

Simplify.

$\text{Side length}=236$

Now, recall how to find the perimeter of a square.

$\text{Perimeter}=4\times\text{side length}$

For the square in question,

$\text{Perimeter}=4\times 236$

Solve.

$\text{Perimeter}=944$

Report an Error

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Basic Geometry : How to find the perimeter of a square

Study concepts, example questions & explanations for Basic Geometry

All Basic Geometry Resources

Example Questions

Example Question #861 : Basic Geometry

Example Question #867 : Basic Geometry

Example Question #862 : Basic Geometry

Example Question #863 : Basic Geometry

Example Question #864 : Basic Geometry

Example Question #871 : Basic Geometry

Example Question #872 : Basic Geometry

Example Question #23 : How To Find The Perimeter Of A Square

Example Question #873 : Basic Geometry

Example Question #21 : How To Find The Perimeter Of A Square

All Basic Geometry Resources

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