Call Now to Set Up Tutoring:

(888) 888-0446

Basic Geometry : Basic Geometry

Study concepts, example questions & explanations for Basic Geometry

Create An Account

All Basic Geometry Resources

9 Diagnostic Tests 164 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #321 : Basic Geometry

Find the diameter of a circle whose area is $\frac{1}{4}\pi$ .

Possible Answers:

$\frac{1}{2}$

$\frac{1}{4}$

Correct answer:

Explanation:

Recall how to find the area of a circle:

$\text{Area}=\pi\times\text{radius}^2$

Next, plug in the information given by the question.

$\frac{1}{4}\pi=\pi\times\text{radius}^2$

From this, we can see that we can solve for the radius.

$\text{radius}^2=\frac{1}{4}$

$\text{radius}=\sqrt{\frac{1}{4}}=\frac{1}{2}$

Now recall the relationship between the radius and the diameter.

$\text{diameter}=2\times\text{radius}$

Plug in the value of the radius to find the diameter.

$\text{diameter}=2\times \frac{1}{2} = 1$

Report an Error

Example Question #13 : Diameter

Find the diameter of a circle whose area is $\frac{1}{16}\pi$ .

Possible Answers:

$\frac{1}{2}$

$\frac{1}{4}$

$\frac{1}{8}$

Correct answer:

$\frac{1}{2}$

Explanation:

Recall how to find the area of a circle:

$\text{Area}=\pi\times\text{radius}^2$

Next, plug in the information given by the question.

$\frac{1}{16}\pi=\pi\times\text{radius}^2$

From this, we can see that we can solve for the radius.

$\text{radius}^2=\frac{1}{16}$

$\text{radius}=\sqrt{\frac{1}{16}}=\frac{1}{4}$

Now recall the relationship between the radius and the diameter.

$\text{diameter}=2\times\text{radius}$

Plug in the value of the radius to find the diameter.

$\text{diameter}=2\times \frac{1}{4} = \frac{1}{2}$

Report an Error

Example Question #322 : Plane Geometry

Find the diameter of a circle whose area is $484\pi$ .

Possible Answers:

Correct answer:

Explanation:

Recall how to find the area of a circle:

$\text{Area}=\pi\times\text{radius}^2$

Next, plug in the information given by the question.

$484\pi=\pi\times\text{radius}^2$

From this, we can see that we can solve for the radius.

$\text{radius}^2=484$

$\text{radius}=\sqrt{484}=22$

Now recall the relationship between the radius and the diameter.

$\text{diameter}=2\times\text{radius}$

Plug in the value of the radius to find the diameter.

$\text{diameter}=2\times 22 = 44$

Report an Error

Example Question #12 : How To Find The Length Of The Diameter

Find the diameter of a circle whose area is $3025\pi$ .

Possible Answers:

110

220

Correct answer:

110

Explanation:

Recall how to find the area of a circle:

$\text{Area}=\pi\times\text{radius}^2$

Next, plug in the information given by the question.

$3025\pi=\pi\times\text{radius}^2$

From this, we can see that we can solve for the radius.

$\text{radius}^2=3025$

$\text{radius}=\sqrt{3025}=55$

Now recall the relationship between the radius and the diameter.

$\text{diameter}=2\times\text{radius}$

Plug in the value of the radius to find the diameter.

$\text{diameter}=2\times 55 = 110$

Report an Error

Example Question #19 : How To Find The Length Of The Diameter

Find the diameter of a circle whose area is $529\pi$ .

Possible Answers:

Correct answer:

Explanation:

Recall how to find the area of a circle:

$\text{Area}=\pi\times\text{radius}^2$

Next, plug in the information given by the question.

$529\pi=\pi\times\text{radius}^2$

From this, we can see that we can solve for the radius.

$\text{radius}^2=529$

$\text{radius}=\sqrt{529}=23$

Now recall the relationship between the radius and the diameter.

$\text{diameter}=2\times\text{radius}$

Plug in the value of the radius to find the diameter.

$\text{diameter}=2\times 23 = 46$

Report an Error

Example Question #322 : Plane Geometry

Find the diameter of a circle whose area is $1156\pi$ .

Possible Answers:

136

Correct answer:

Explanation:

Recall how to find the area of a circle:

$\text{Area}=\pi\times\text{radius}^2$

Next, plug in the information given by the question.

$1156\pi=\pi\times\text{radius}^2$

From this, we can see that we can solve for the radius.

$\text{radius}^2=1156$

$\text{radius}=\sqrt{1156}=34$

Now recall the relationship between the radius and the diameter.

$\text{diameter}=2\times\text{radius}$

Plug in the value of the radius to find the diameter.

$\text{diameter}=2\times 34 = 68$

Report an Error

Example Question #324 : Circles

Find the diameter of a circle that has a circumference of .

Possible Answers:

$\frac{12}{\pi}$

$\frac{6}{\pi}$

Correct answer:

$\frac{12}{\pi}$

Explanation:

Recall how to find the circumference of a circle:

$\text{Circumference}=\text{diameter}\times\pi$

If we divide both sides of the equation by $\pi$ , then we can write the following equation:

$\text{Diameter}=\frac{\text{Circumference}}{\pi}$

We can substitute in the given information to find the diameter of the circle in the question.

$\text{Diameter}=\frac{12}{\pi}$

Report an Error

Example Question #321 : Plane Geometry

Find the diameter of a circle that has a circumference of 100 .

Possible Answers:

100

$\frac{50}{\pi}$

$\frac{100}{\pi}$

$\frac{200}{\pi}$

Correct answer:

$\frac{100}{\pi}$

Explanation:

Recall how to find the circumference of a circle:

$\text{Circumference}=\text{diameter}\times\pi$

If we divide both sides of the equation by $\pi$ , then we can write the following equation:

$\text{Diameter}=\frac{\text{Circumference}}{\pi}$

We can substitute in the given information to find the diameter of the circle in the question.

$\text{Diameter}=\frac{100}{\pi}$

Report an Error

Example Question #24 : Diameter

Find the diameter of a circle that has a circumference of $14\pi$ .

Possible Answers:

$\pi$

Correct answer:

Explanation:

Recall how to find the circumference of a circle:

$\text{Circumference}=\text{diameter}\times\pi$

If we divide both sides of the equation by $\pi$ , then we can write the following equation:

$\text{Diameter}=\frac{\text{Circumference}}{\pi}$

We can substitute in the given information to find the diameter of the circle in the question.

$\text{Diameter}=\frac{14\pi}{\pi}$

Simplify.

$\text{Diameter}=14$

Report an Error

Example Question #323 : Plane Geometry

Find the diameter of a circle that has a circumference of $10\pi$ .

Possible Answers:

Correct answer:

Explanation:

Recall how to find the circumference of a circle:

$\text{Circumference}=\text{diameter}\times\pi$

If we divide both sides of the equation by $\pi$ , then we can write the following equation:

$\text{Diameter}=\frac{\text{Circumference}}{\pi}$

We can substitute in the given information to find the diameter of the circle in the question.

$\text{Diameter}=\frac{10\pi}{\pi}$

Simplify.

$\text{Diameter}=10$

Report an Error

View Tutors

Bibhash
Certified Tutor

Pune University, Bachelor in Arts, Ecommerce. SDA Bocconi School of Management, Masters in Business Administration, Finance.

View Tutors

Kunj
Certified Tutor

Rutgers University-New Brunswick, Bachelor of Science, Biochemistry and Molecular Biology.

View Tutors

Natalie
Certified Tutor

Barnes-Jewish College Goldfarb School of Nursing, Bachelor in Arts, Nursing (RN). Maryville University of Saint Louis, Master...

All Basic Geometry Resources

9 Diagnostic Tests 164 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

English Tutors in Miami, French Tutors in Boston, Math Tutors in Philadelphia, English Tutors in Philadelphia, GMAT Tutors in Phoenix, SAT Tutors in Los Angeles, English Tutors in Seattle, Reading Tutors in Dallas Fort Worth, Computer Science Tutors in Miami, SAT Tutors in Seattle

Popular Courses & Classes

GMAT Courses & Classes in Atlanta, Spanish Courses & Classes in Seattle, SSAT Courses & Classes in Phoenix, SAT Courses & Classes in Houston, SAT Courses & Classes in San Francisco-Bay Area, MCAT Courses & Classes in New York City, GMAT Courses & Classes in Dallas Fort Worth, SAT Courses & Classes in New York City, SAT Courses & Classes in Denver, ACT Courses & Classes in Atlanta

Popular Test Prep

ACT Test Prep in Atlanta, SAT Test Prep in Miami, SAT Test Prep in Houston, SSAT Test Prep in Philadelphia, SAT Test Prep in New York City, SAT Test Prep in Seattle, GRE Test Prep in Chicago, LSAT Test Prep in San Francisco-Bay Area, LSAT Test Prep in Miami, GMAT Test Prep in Atlanta

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Basic Geometry : Basic Geometry

Study concepts, example questions & explanations for Basic Geometry

All Basic Geometry Resources

Example Questions

Example Question #321 : Basic Geometry

Example Question #13 : Diameter

Example Question #322 : Plane Geometry

Example Question #12 : How To Find The Length Of The Diameter

Example Question #19 : How To Find The Length Of The Diameter

Example Question #322 : Plane Geometry

Example Question #324 : Circles

Example Question #321 : Plane Geometry

Example Question #24 : Diameter

Example Question #323 : Plane Geometry

All Basic Geometry Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: