AP Statistics : Statistical Patterns and Random Phenomena
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Example Questions
Example Question #1 : How To Use The Multiplication Rule
Given a fair coin, what is the probability of obtaining 5 heads and 3 tails from 8 tosses?
0.5000
0.1188
0.6188
0.2188
0.3188
0.2188
First, there are 8 trials and either choose 5 or 3 for heads or tails, respectively. Using this knowledge: 
Example Question #1 : How To Use The Multiplication Rule
How many different combinations of 3 digit numbers can be formed using the numbers 1, 2, 3, 4, and 5, if repetitions are allowed?
125
120
15
60
3
125
The key to answering this question is noting that repetitions are allowed. This means that if a number is picked, it is replaced and may be picked again, thus allowing for duplicates or triplicates. Because there are 5 choices and after each number is picked there remain 5 choices (replacement), and the question is asking for 3 digit combinations, the answer is obtained by multiplying 5 * 5 * 5 = 125. In other words, there are 5 choices for the first digit, 5 choices for the second digit, and 5 choices for the third digit.
Example Question #1 : How To Use The Multiplication Rule
How many different combinations of 3 digit numbers can be formed using the numbers 1, 2, 3, 4, and 5, if repetitions are NOT allowed?
25
125
9
3
60
60
The important thing to note for this question is that there are no repetitions allowed. In other words, once a number had been chosen, it cannot be chosen for the second digit or the third digit. Thus, there are 5 choices for the first digit, 4 for the second, and 3 for the third. So, 5 * 4 * 3 = 60.
Example Question #4 : How To Use The Multiplication Rule
There are 52 total cards in a full deck of playing cards. If a card dealer chooses 4 cards from the deck at random and without replacement, what is the chance that the dealer draws four kings as the first four cards?
0.0037
0.0000052
0.0000025
0.0000037
0.025
0.0000037
In a normal deck of playing cards, there are 4 kings. Thus, when the dealer draws the first card, the chance of the dealer obtaining a king is 4 out of 52. Because this card has been picked and is not replaced, the chance that the next card chosen is a king is 3 out of 52. The chance the third card is a king is 2 out of 52 and the fourth card is 1 out of 52. Each of these events is multiplied together, thus obtaining the correct answer, 0.0000037.
Example Question #22 : Rules Of Probability
If the probability of landing a heads in a coin flip is 0.5 and the probability of observing a meteor hit the earth is 0.03, and these events are independent, what is the probability of landing a heads AND observing a meteor hit the earth?
.35
.015
.5
.15
.035
.015
Since the two events are independent, multiply their probabilities to get their joint probability. Multiplying the probability of the coin flip, 0.5, by the probability of a meteor, 0.03, gives a probability of 0.015.
Example Question #2 : How To Use The Multiplication Rule
Research has found that the probability of having brown eyes is 
Example Question #2 : How To Use The Multiplication Rule
In a standard deck of cards, without replacement, what is the probability of drawing three kings?
Start with 52 cards, probability of drawing first king:
Now you have 51 cards. Probability of drawing second king:
Now you have 50 cards. Probability of drawing third king:
Multiply all probabilities:
Example Question #403 : Algebra Ii
With a standard deck of cards, what is the probability of picking a spade then a red card if there is no replacement?
In a standard deck of cards:
Example Question #22 : Probability
In a bag there are 
Example Question #30 : Probability
A child has a bag of marbles--
To find the probability of possible outcomes for two separate events, multiply the probabilities of the two outcomes.
Then reduce the answer to the least common denominator.
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